Physics·Prelims Questions

Measurement of Length — Prelims Questions

NEET UG
Version 1Updated 22 Mar 2026
Q1medium

A student measures the diameter of a small steel ball using a screw gauge. The pitch of the screw gauge is 1,mm1,\text{mm} and there are 100 divisions on the circular scale. The main scale reading is 5,mm5,\text{mm} and the 58th division on the circular scale coincides with the main line. The screw gauge has a positive zero error of 0.03,mm0.03,\text{mm}. What is the corrected diameter of the steel ball?

Q2medium

A Vernier caliper has 10 divisions on its Vernier scale, which coincide with 9 divisions on the main scale. Each main scale division (MSD) is 1,mm1,\text{mm}. When the jaws are closed, the 7th division of the Vernier scale coincides with a main scale division, and the zero of the Vernier scale is to the left of the zero of the main scale. While measuring a length, the main scale reading is 3.5,cm3.5,\text{cm} and the 4th Vernier division coincides. What is the actual length measured?

Q3easy

The diameter of a sphere is measured to be 2.745,cm2.745,\text{cm} using a Vernier caliper. If the least count of the Vernier caliper is 0.01,cm0.01,\text{cm}, what is the maximum possible percentage error in the measurement?

Q4easy

A star is 4.24.2 light-years away from Earth. If 11 light-year is approximately 9.46×1015,m9.46 \times 10^{15},\text{m}, what is the distance of the star in kilometers?

Q5medium

Which of the following statements about the precision and accuracy of length measurements is correct?

Q6hard

The parallax angle of a distant star is measured to be 0.50.5'' (arcseconds). If the baseline used for observation is the diameter of Earth's orbit around the Sun, which is approximately 3×1011,m3 \times 10^{11},\text{m}, what is the distance to the star? (Given: 1=4.85×106,radians1'' = 4.85 \times 10^{-6},\text{radians})

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