Physics·MCQ Practice

Work by Constant Force — MCQ Practice

NEET UG
Version 1Updated 22 Mar 2026

Interactive MCQ Practice

Test your knowledge. Click “Solve” to reveal options, select your answer, then check the result. 6 questions available.

Q1easy

A block of mass 2,kg2,\text{kg} is pulled by a constant force of 10,N10,\text{N} on a horizontal surface. The force makes an angle of 3030^\circ with the horizontal. If the block is displaced by 5,m5,\text{m} horizontally, what is the work done by the applied force? (Given: cos30=320.866\cos 30^\circ = \frac{\sqrt{3}}{2} \approx 0.866)

Q2medium

A porter lifts a luggage of 15,kg15,\text{kg} from the ground and puts it on his head 1.5,m1.5,\text{m} above the ground. Calculate the work done by the porter on the luggage. (Take g=10,m/s2g = 10,\text{m/s}^2)

Q3easy

A body moves a distance of 10,m10,\text{m} along a straight line under the action of a 5,N5,\text{N} force. If the work done is 25,J25,\text{J}, what is the angle between the force and the direction of motion?

Q4medium

A force F=(2i^+3j^),N\vec{F} = (2\hat{i} + 3\hat{j}),\text{N} acts on an object, causing a displacement d=(4i^2j^),m\vec{d} = (4\hat{i} - 2\hat{j}),\text{m}. What is the work done by the force?

Q5easy

A person carries a 10,kg10,\text{kg} suitcase on his head and travels a horizontal distance of 50,m50,\text{m} on a straight road. What is the work done by the person on the suitcase? (Assume constant velocity and g=10,m/s2g = 10,\text{m/s}^2)

Q6hard

A 5,kg5,\text{kg} block slides 2,m2,\text{m} down an inclined plane that makes an angle of 3030^\circ with the horizontal. The coefficient of kinetic friction is 0.20.2. Calculate the work done by the friction force. (Take g=10,m/s2g = 10,\text{m/s}^2)

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