Physics·MCQ Practice

Magnetic Field — MCQ Practice

NEET UG
Updated 22 Mar 2026

Interactive MCQ Practice

Test your knowledge. Click “Solve” to reveal options, select your answer, then check the result. 6 questions available.

Q1medium

An electron moves with a velocity v=(2i^+3j^);m/s\vec{v} = (2\hat{i} + 3\hat{j});\text{m/s} in a uniform magnetic field B=(4i^+2j^);T\vec{B} = (4\hat{i} + 2\hat{j});\text{T}. What is the magnetic force experienced by the electron? (Charge of electron e=1.6×1019;Ce = -1.6 \times 10^{-19};\text{C})

Q2easy

An infinitely long straight conductor carries a current of 5A5\,\text{A}. What is the magnitude of the magnetic field at a perpendicular distance of 10cm10\,\text{cm} from the conductor? (Take μ0=4π×107;Tm/A\mu_0 = 4\pi \times 10^{-7};\text{T}\cdot\text{m/A})

Q3medium

A circular coil of radius RR carrying current II produces a magnetic field B0B_0 at its center. If the current is doubled and the radius is halved, what will be the new magnetic field at the center?

Q4easy

Which of the following statements about magnetic field lines is INCORRECT?

Q5easy

A long solenoid has 1000 turns per meter and carries a current of 2A2\,\text{A}. What is the magnetic field inside the solenoid? (Take μ0=4π×107;Tm/A\mu_0 = 4\pi \times 10^{-7};\text{T}\cdot\text{m/A})

Q6medium

A proton enters a uniform magnetic field of 0.5T0.5\,\text{T} with a velocity of 3×106m/s3 \times 10^6\,\text{m/s} perpendicular to the field. What is the radius of the circular path followed by the proton? (Mass of proton mp=1.67×1027,kgm_p = 1.67 \times 10^{-27},\text{kg}, Charge of proton e=1.6×1019,Ce = 1.6 \times 10^{-19},\text{C})