Physics·Revision Notes

Magnetic Field due to Current — Revision Notes

NEET UG
Updated 22 Mar 2026

⚡ 30-Second Revision

  • Ørsted's Discovery:Current creates magnetic field.
  • Right-Hand Thumb Rule:Thumb = current, fingers = B-field direction.
  • Biot-Savart Law:dvecB=μ04piIdvecl×rr3dvec{B} = \frac{\mu_0}{4pi} \frac{I dvec{l} \times \vec{r}}{r^3} (differential, universal).
  • Ampere's Circuital Law:Bdvecl=μ0Ienclosed\oint \vec{B} \cdot dvec{l} = \mu_0 I_{enclosed} (integral, for symmetry).
  • Straight Wire (infinite):B=μ0I2πrB = \frac{\mu_0 I}{2\pi r}
  • Circular Loop (center):B=μ0I2RB = \frac{\mu_0 I}{2R} (for N turns: B=μ0NI2RB = \frac{\mu_0 N I}{2R})
  • Circular Loop (axis):B=μ0IR22(R2+x2)3/2B = \frac{\mu_0 I R^2}{2(R^2+x^2)^{3/2}}
  • Solenoid (inside):B=μ0nIB = \mu_0 n I (nn = turns/length)
  • Toroid (inside):B=μ0NI2πrB = \frac{\mu_0 N I}{2\pi r} (NN = total turns, rr = mean radius)
  • $\mu_0$ (Permeability of Free Space):4π×107,Tm/A4\pi \times 10^{-7},\text{T}\cdot\text{m/A}

2-Minute Revision

The core idea is that moving charges, or electric currents, generate magnetic fields. This was first observed by Ørsted. The direction of these fields is crucial and is determined by the Right-Hand Thumb Rule: for a straight wire, thumb points in current direction, curled fingers show field direction; for a loop, fingers curl with current, thumb shows field direction inside.

Quantitatively, the Biot-Savart Law (dvecB=μ04piIdvecl×rr3dvec{B} = \frac{\mu_0}{4pi} \frac{I dvec{l} \times \vec{r}}{r^3}) gives the field from a small current element and is universally applicable. For highly symmetric current distributions, Ampere's Circuital Law (Bdvecl=μ0Ienclosed\oint \vec{B} \cdot dvec{l} = \mu_0 I_{enclosed}) provides a simpler integral approach.

Key formulas to remember are for an infinite straight wire (B=μ0I2πrB = \frac{\mu_0 I}{2\pi r}), a circular loop at its center (B=μ0I2RB = \frac{\mu_0 I}{2R}), inside a solenoid (B=μ0nIB = \mu_0 n I), and inside a toroid (B=μ0NI2πrB = \frac{\mu_0 N I}{2\pi r}).

Remember that magnetic fields are vector quantities, so for multiple sources, vector addition is required. Always pay attention to units and the value of μ0\mu_0.

5-Minute Revision

Revisiting 'Magnetic Field due to Current' means solidifying your understanding of how electricity creates magnetism. Start with Ørsted's discovery: current in a wire produces a magnetic field. The Right-Hand Thumb Rule is your best friend for direction: for a straight wire, thumb with current, fingers curl in B-field direction; for a loop, fingers with current, thumb points along axial B-field.

Two fundamental laws govern calculations:

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  1. Biot-Savart Law:dvecB=μ04piIdvecl×rr3dvec{B} = \frac{\mu_0}{4pi} \frac{I dvec{l} \times \vec{r}}{r^3}. This is a differential law, meaning it calculates the field from a tiny current segment. It's universal but often requires complex integration. Remember the cross product for direction.
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  3. Ampere's Circuital Law:Bdvecl=μ0Ienclosed\oint \vec{B} \cdot dvec{l} = \mu_0 I_{enclosed}. This is an integral law, incredibly useful for symmetric current distributions (like infinite wires, solenoids, toroids) because it simplifies the integral. Choose your Amperian loop wisely!

Key Formulas to Master:

  • Infinite Straight Wire:B=μ0I2πrB = \frac{\mu_0 I}{2\pi r}. Example: A 10A10\,\text{A} current in a long wire. At 1cm1\,\text{cm} (0.01m0.01\,\text{m}) away, B=4π×107×102π×0.01=2×104,TB = \frac{4\pi \times 10^{-7} \times 10}{2\pi \times 0.01} = 2 \times 10^{-4},\text{T}.
  • Circular Loop (at center):B=μ0I2RB = \frac{\mu_0 I}{2R}. For NN turns, B=μ0NI2RB = \frac{\mu_0 N I}{2R}. Example: A 5-turn coil of 5cm5\,\text{cm} radius with 2A2\,\text{A} current. B=4π×107×5×22×0.05=4π×105,TB = \frac{4\pi \times 10^{-7} \times 5 \times 2}{2 \times 0.05} = 4\pi \times 10^{-5},\text{T}.
  • Circular Loop (on axis):B=μ0IR22(R2+x2)3/2B = \frac{\mu_0 I R^2}{2(R^2+x^2)^{3/2}}. This shows B decreases with distance xx.
  • Solenoid (inside):B=μ0nIB = \mu_0 n I, where nn is turns per unit length. Example: Solenoid with 2000turns/m2000\,\text{turns/m} and 1A1\,\text{A} current. B=4π×107×2000×1=8π×104,TB = 4\pi \times 10^{-7} \times 2000 \times 1 = 8\pi \times 10^{-4},\text{T}.
  • Toroid (inside):B=μ0NI2πrB = \frac{\mu_0 N I}{2\pi r}, where NN is total turns and rr is mean radius.

Remember that magnetic fields are vector quantities. If you have multiple current sources, you must find the field from each and then add them vectorially, considering both magnitude and direction. Always check units and use μ0=4π×107,Tm/A\mu_0 = 4\pi \times 10^{-7},\text{T}\cdot\text{m/A}. Common mistakes include confusing direction, incorrect formula application, or unit errors. Practice problems involving superposition and varying geometries to solidify your understanding.

Prelims Revision Notes

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  1. Ørsted's Experiment:Electric current produces magnetic field. This is the fundamental link.
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  3. Right-Hand Thumb Rule:

* Straight Wire: Thumb in current direction, curled fingers give magnetic field direction (concentric circles). * Circular Loop: Fingers curl in current direction, thumb gives magnetic field direction along the axis (inside the loop).

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  1. Biot-Savart Law:

* Differential form: dvecB=μ04piIdvecl×rr3dvec{B} = \frac{\mu_0}{4pi} \frac{I dvec{l} \times \vec{r}}{r^3}. * Magnitude: dB=μ04piIdlsinθr2dB = \frac{\mu_0}{4pi} \frac{I dl \sin\theta}{r^2}. * μ0=4π×107,Tm/A\mu_0 = 4\pi \times 10^{-7},\text{T}\cdot\text{m/A} (permeability of free space). * Used for any current distribution, especially for infinitesimal elements.

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  1. Magnetic Field due to a Long Straight Wire:

* Infinite wire: B=μ0I2πrB = \frac{\mu_0 I}{2\pi r}. Direction: concentric circles, by RHTR. * Finite wire: B=μ0I4πr(sinθ1+sinθ2)B = \frac{\mu_0 I}{4\pi r} (\sin\theta_1 + \sin\theta_2).

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  1. Magnetic Field due to a Circular Loop:

* At center: B=μ0I2RB = \frac{\mu_0 I}{2R}. For NN turns: B=μ0NI2RB = \frac{\mu_0 N I}{2R}. * On axis (at distance xx from center): B=μ0IR22(R2+x2)3/2B = \frac{\mu_0 I R^2}{2(R^2+x^2)^{3/2}}.

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  1. Ampere's Circuital Law:

* Integral form: Bdvecl=μ0Ienclosed\oint \vec{B} \cdot dvec{l} = \mu_0 I_{enclosed}. Used for highly symmetric current distributions. IenclosedI_{enclosed} is the net current passing through the Amperian loop, direction by RHTR for the loop.

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  1. Magnetic Field Inside a Solenoid:

* Long solenoid: B=μ0nIB = \mu_0 n I, where n=N/Ln = N/L (turns per unit length). * Field is uniform and axial inside, negligible outside.

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  1. Magnetic Field Inside a Toroid:

* B=μ0NI2πrB = \frac{\mu_0 N I}{2\pi r}, where NN is total turns, rr is mean radius. * Field is confined within the toroid, zero outside.

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  1. Superposition Principle:For multiple current sources, the net magnetic field at a point is the vector sum of the fields produced by individual sources.
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  3. Key Points:Magnetic field is a vector. Field lines are closed loops. Pay attention to units (cm to m, etc.) and powers of 10 in calculations.

Vyyuha Quick Recall

For Biot-Savart, remember: 'B-I-L-S-I-N-R-Squared'. B is proportional to I, L (dl), Sin(theta), and inversely to R-squared. (Ignoring constants and vector nature for quick recall of dependencies). For Ampere's Law, think 'Amps Enclose Current'. The integral of B around a loop equals mu-naught times the enclosed current.