Ionisation Enthalpy, Oxidation States

Updated 22 Mar 2026

Ionisation enthalpy, often referred to as ionisation energy, is the minimum amount of energy required to remove the most loosely bound electron from an isolated gaseous atom or ion in its ground state. For transition elements, this property exhibits complex trends due to the interplay of nuclear charge, shielding effect, and the involvement of both (n-1)d and ns electrons. Oxidation states, on the…

Quick Summary

Ionisation enthalpy is the energy required to remove an electron from a gaseous atom, with successive enthalpies increasing. For transition metals, IE1IE_1 shows irregular trends across a period due to the interplay of increasing nuclear charge, d-electron shielding, and the stability of half-filled (d5d^5) or fully-filled (d10d^{10}) configurations (e.

g., Cr, Cu, Mn, Zn). Down a group, the lanthanoid contraction causes 5d elements to have unexpectedly high IE values, often comparable to 4d elements.

Oxidation states represent the hypothetical charge an atom would have in a compound. Transition metals are characterized by exhibiting variable oxidation states, a property arising from the small energy difference between their (n1)d(n-1)d and nsns orbitals, allowing both sets of electrons to participate in bonding.

The range of oxidation states typically increases up to Manganese (max +7+7) and then decreases. The stability of specific oxidation states is influenced by electronic configuration (e.g., d5d^5, d10d^{10}), the nature of ligands, and the environment (e.

g., aqueous solution). Some intermediate oxidation states can undergo disproportionation, where an element is simultaneously oxidized and reduced.

Full explanation

The properties of ionisation enthalpy and oxidation states are central to understanding the unique chemistry of transition elements. These elements, located in the d-block of the periodic table, exhibit distinct trends and characteristics compared to s-block and p-block elements, largely due to the involvement of their (n-1)d electrons.

Ionisation Enthalpy of Transition Elements

Definition and Successive Ionisation Enthalpies:

Ionisation enthalpy (IE) is the energy required to remove an electron from a gaseous atom or ion. For transition elements, we consider the first, second, and successive ionisation enthalpies. The first ionisation enthalpy (IE1IE_1) removes an electron from a neutral atom.

The second ionisation enthalpy (IE2IE_2) removes an electron from the M+M^+ ion, and so on. A crucial point is that successive ionisation enthalpies always increase (IE1<IE2<IE3IE_1 < IE_2 < IE_3 \dots) because removing an electron from a positively charged species requires overcoming a stronger electrostatic attraction.

As we move across a transition series from left to right (e.g., Sc to Zn), the nuclear charge increases steadily. One might expect a consistent increase in ionisation enthalpy due to this increasing nuclear attraction. However, the trend is not as smooth as in s-block or p-block elements. The IE1IE_1 values generally show a slight and irregular increase across the 3d series. This irregularity is primarily due to:

    1
  1. Increasing Nuclear Charge:As atomic number increases, the number of protons increases, pulling the electrons more strongly towards the nucleus.
  2. 2
  3. Shielding Effect of d-electrons:The added d-electrons effectively shield the outer ns electrons from the increasing nuclear charge. This shielding is not perfectly efficient, but it partially counteracts the effect of increased nuclear charge.
  4. 3
  5. Electron-electron Repulsion:As more electrons are added to the d-subshell, electron-electron repulsions increase, which can slightly reduce the energy required to remove an electron.

Specific Irregularities in 3d Series $IE_1$:

  • Chromium (Cr) and Copper (Cu):These elements show slightly higher IE1IE_1 values than their neighbors. For Cr ([Ar]3d54s1[Ar]3d^54s^1), the 4s14s^1 electron is removed, leaving a stable half-filled 3d53d^5 configuration. For Cu ([Ar]3d104s1[Ar]3d^{10}4s^1), the 4s14s^1 electron is removed, leaving a stable fully-filled 3d103d^{10} configuration. The stability associated with these configurations makes it slightly harder to remove the first electron.
  • Manganese (Mn) and Zinc (Zn):These elements have relatively high IE2IE_2 values. For Mn ([Ar]3d54s2[Ar]3d^54s^2), removing the first 4s4s electron gives Mn+Mn^+ ([Ar]3d54s1[Ar]3d^54s^1). Removing the second electron from 4s14s^1 is relatively easy. However, IE3IE_3 for Mn is very high because it involves removing an electron from the stable half-filled 3d53d^5 configuration of Mn2+Mn^{2+} ([Ar]3d5[Ar]3d^5). For Zn ([Ar]3d104s2[Ar]3d^{10}4s^2), removing the first 4s4s electron gives Zn+Zn^+ ([Ar]3d104s1[Ar]3d^{10}4s^1). Removing the second 4s4s electron is relatively easy. However, IE3IE_3 for Zn is extremely high as it would involve breaking the stable fully-filled 3d103d^{10} configuration of Zn2+Zn^{2+} ([Ar]3d10[Ar]3d^{10}). This explains why Zn2+Zn^{2+} is the most common and stable oxidation state for zinc.

Moving down a group (e.g., from 3d to 4d to 5d series), atomic size generally increases, and the outermost electrons are further from the nucleus. This typically leads to a decrease in ionisation enthalpy.

However, for transition elements, the trend is complicated by the lanthanoid contraction. The poor shielding by 4f electrons in the lanthanoids causes a significant increase in effective nuclear charge for the subsequent 5d elements.

As a result, the 5d elements often have ionisation enthalpies comparable to, or even slightly higher than, their 4d counterparts, despite being larger atoms. For example, IE1IE_1 for Hf is similar to Zr.

Oxidation States of Transition Elements

Variable Oxidation States:

The most distinctive feature of transition elements is their ability to exhibit multiple oxidation states. This contrasts sharply with s-block elements (typically fixed +1+1 or +2+2) and p-block elements (which show fewer variations, often separated by two units). The primary reason for this variability is the very small energy difference between the (n1)d(n-1)d orbitals and the nsns orbitals. This allows electrons from both these subshells to participate in bond formation.

Common Oxidation States in 3d Series:

  • Scandium (Sc):Only exhibits +3+3 oxidation state ([Ar]3d14s2Sc3+[Ar]3d^14s^2 \rightarrow Sc^{3+} with [Ar][Ar] configuration). All three valence electrons are lost.
  • Titanium (Ti):Shows +2,+3,+4+2, +3, +4. +4+4 is most stable ([Ar]3d24s2Ti4+[Ar]3d^24s^2 \rightarrow Ti^{4+} with [Ar][Ar] configuration).
  • Vanadium (V):Shows +2,+3,+4,+5+2, +3, +4, +5. +5+5 is most stable in compounds like V2O5V_2O_5 ([Ar]3d34s2V5+[Ar]3d^34s^2 \rightarrow V^{5+} with [Ar][Ar] configuration).
  • Chromium (Cr):Shows +2,+3,+6+2, +3, +6. +3+3 is common, +6+6 is seen in chromates and dichromates ([Ar]3d54s1[Ar]3d^54s^1).
  • Manganese (Mn):Exhibits the widest range, from +2+2 to +7+7. +2+2 and +7+7 are particularly stable. ([Ar]3d54s2[Ar]3d^54s^2).
  • Iron (Fe):Shows +2,+3+2, +3. +3+3 is generally more stable than +2+2 in many compounds ([Ar]3d64s2[Ar]3d^64s^2).
  • Cobalt (Co):Shows +2,+3+2, +3. +2+2 is more common in simple salts, +3+3 is stable in complexes ([Ar]3d74s2[Ar]3d^74s^2).
  • Nickel (Ni):Primarily +2+2, sometimes +3+3 or +4+4 in complexes ([Ar]3d84s2[Ar]3d^84s^2).
  • Copper (Cu):Shows +1,+2+1, +2. +2+2 is more common and stable in aqueous solutions ([Ar]3d104s1[Ar]3d^{10}4s^1).
  • Zinc (Zn):Only exhibits +2+2 oxidation state ([Ar]3d104s2Zn2+[Ar]3d^{10}4s^2 \rightarrow Zn^{2+} with [Ar]3d10[Ar]3d^{10} configuration).

Stability of Oxidation States:

  • Lower Oxidation States (+2, +3):These are common for most transition metals. The +2+2 state typically arises from the loss of the two nsns electrons. The +3+3 state involves the loss of two nsns electrons and one (n1)d(n-1)d electron.
  • Higher Oxidation States:The highest oxidation state generally increases from group 3 to group 7 (Sc to Mn) and then decreases. The maximum oxidation state often corresponds to the sum of nsns and (n1)d(n-1)d electrons, especially for elements up to Mn. For example, Mn (3d54s23d^54s^2) can show +7+7 (in MnO4MnO_4^-).
  • Factors Affecting Stability:

* Electronic Configuration: Half-filled (d5d^5) and fully-filled (d10d^{10}) d-orbitals confer extra stability. For example, Mn2+Mn^{2+} (3d53d^5) is very stable. Zn2+Zn^{2+} (3d103d^{10}) is very stable.

* Electronegativity of Ligands/Oxidizing Agents: Higher oxidation states are more stable when the metal is bonded to highly electronegative elements like oxygen or fluorine (e.g., MnO4MnO_4^-, CrO42CrO_4^{2-}).

* Acidic/Basic Character of Oxides: Oxides in lower oxidation states are generally basic (e.g., MnOMnO), while those in higher oxidation states are acidic (e.g., Mn2O7Mn_2O_7). Intermediate oxidation states can be amphoteric (e.

g., Cr2O3Cr_2O_3). * Aqueous Stability: The stability of an oxidation state in aqueous solution is influenced by hydration enthalpy and lattice enthalpy (for solid compounds).

Disproportionation:

Some oxidation states can undergo disproportionation, where an element in an intermediate oxidation state simultaneously oxidizes and reduces itself. For example, Cu+Cu^+ in aqueous solution is unstable and disproportionates into Cu2+Cu^{2+} and CuCu:

2Cu+(aq)Cu2+(aq)+Cu(s)2Cu^+(aq) \rightarrow Cu^{2+}(aq) + Cu(s)
This occurs when the stability of the lower and higher oxidation states is significantly greater than the intermediate one.

NEET-Specific Angle:

For NEET, understanding the reasons behind these trends and exceptions is paramount. Questions often test the stability of specific oxidation states, the maximum oxidation state exhibited by an element, or the relative ionisation enthalpies of elements within a series or group.

Pay close attention to the role of d5d^5 and d10d^{10} configurations in conferring stability, and the impact of lanthanoid contraction on 5d series properties. Remember that for transition metals, electrons are first removed from the nsns orbital, then from the (n1)d(n-1)d orbital, when forming ions.

Key Concepts

Factors Affecting Ionisation Enthalpy in Transition Metals

The ionisation enthalpy of transition metals is a complex interplay of several factors. Firstly, the…

Origin and Stability of Variable Oxidation States

The variable oxidation states of transition metals stem from the very small energy difference between their…

Maximum Oxidation States and Trends

The maximum oxidation state exhibited by transition metals generally increases from Group 3 to Group 7 in the…

Often confused with

Side-by-side differences the NEET paper likes to test.

Ionisation Enthalpy, Oxidation States vs s-block elements
AspectIonisation Enthalpy, Oxidation Statess-block elements
Ionisation Enthalpy TrendsTransition Elements (d-block)s-block Elements
Across a periodIrregular increase due to d-electron shielding and stable configurations ($d^5, d^{10}$).Smooth, consistent increase due to increasing effective nuclear charge.
Down a groupGenerally decreases, but 5d elements show higher IE than 4d due to lanthanoid contraction.Consistent decrease due to increasing atomic size and shielding.
Oxidation StatesExhibit variable oxidation states (e.g., Fe: +2, +3) due to small energy difference between (n-1)d and ns orbitals.Typically show fixed oxidation states (+1 for Group 1, +2 for Group 2) as only ns electrons participate.
Highest Oxidation StateCan be very high (e.g., Mn: +7, Os: +8) involving both ns and (n-1)d electrons.Limited to +1 or +2, corresponding to the number of ns electrons.

Transition elements differ significantly from s-block elements in both ionisation enthalpy and oxidation states. While s-block elements show predictable, smooth trends in IE and fixed oxidation states, transition metals exhibit irregular IE trends due to d-electron effects and the unique ability to display multiple oxidation states.

This variability in oxidation states is a direct consequence of the similar energy levels of their (n-1)d and ns orbitals, allowing for diverse chemical behavior not seen in s-block elements.

Why it is tested: NEET relevance: Understanding these differences is crucial for predicting chemical properties, reactivity, and the stability of compounds formed by transition metals, which are frequently tested in NEET. Questions often compare the properties of d-block elements with those of s-block or p-block elements.

Questions students ask

5 answered on this topic.

Why do transition metals exhibit variable oxidation states?

Transition metals exhibit variable oxidation states primarily because the energy difference between their outermost nsns orbitals and the inner (n1)d(n-1)d orbitals is very small. This allows electrons from both these subshells to participate in chemical bonding.

Unlike s-block elements where only nsns electrons are involved, or p-block elements where the energy gap between nsns and npnp can be larger, transition metals can readily lose a varying number of electrons, leading to a wide range of stable oxidation states.

How does lanthanoid contraction affect the ionisation enthalpy of 5d transition elements?

Lanthanoid contraction refers to the greater-than-expected decrease in atomic and ionic radii across the lanthanoid series. This is due to the poor shielding effect of the 4f electrons. This contraction carries over to the 5d transition series, causing elements like Hf to have atomic radii and ionisation enthalpies very similar to their 4d counterparts (e.

g., Zr). Consequently, the 5d elements often have higher ionisation enthalpies than expected, sometimes even higher than 4d elements, due to the increased effective nuclear charge.

Why is the third ionisation enthalpy of Manganese ($Mn$) exceptionally high?

Manganese has an electronic configuration of [Ar]3d54s2[Ar]3d^54s^2. When it loses its two 4s4s electrons, it forms Mn2+Mn^{2+} with a configuration of [Ar]3d5[Ar]3d^5. This 3d53d^5 configuration is half-filled and thus exceptionally stable. Removing a third electron from this highly stable half-filled 3d53d^5 subshell requires a very large amount of energy, making its third ionisation enthalpy (IE3IE_3) significantly high. This stability explains why Mn2+Mn^{2+} is a very common and stable ion.

What is disproportionation, and can you give an example involving transition metals?

Disproportionation is a redox reaction where a single element in an intermediate oxidation state simultaneously undergoes both oxidation (increase in oxidation state) and reduction (decrease in oxidation state).

A classic example in transition metal chemistry is the disproportionation of Cu+Cu^+ ions in aqueous solution. Cu+Cu^+ is unstable in water and reacts as follows: 2Cu+(aq)Cu2+(aq)+Cu(s)2Cu^+(aq) \rightarrow Cu^{2+}(aq) + Cu(s).

Here, one Cu+Cu^+ ion is oxidized to Cu2+Cu^{2+} (oxidation state changes from +1+1 to +2+2), and another Cu+Cu^+ ion is reduced to CuCu metal (oxidation state changes from +1+1 to 00). This occurs because Cu2+Cu^{2+} and CuCu metal are more stable than Cu+Cu^+ in aqueous environments.

Why does Zinc (Zn) only show a +2 oxidation state, unlike other transition metals?

Zinc has an electronic configuration of [Ar]3d104s2[Ar]3d^{10}4s^2. When it loses its two 4s4s electrons, it forms Zn2+Zn^{2+} with a configuration of [Ar]3d10[Ar]3d^{10}. This 3d103d^{10} configuration is fully-filled and extremely stable.

Removing any further electrons would require breaking this highly stable, fully-filled d-subshell, which demands an exceptionally high amount of energy (very high IE3IE_3). Therefore, the +2+2 oxidation state, where the 3d103d^{10} configuration is preserved, is overwhelmingly stable and the only common oxidation state for zinc.

Revise in 30 seconds

  • Ionisation Enthalpy (IE):Energy to remove an electron.
  • $IE_1 < IE_2 < IE_3 \dots$(Successive IEs always increase).
  • 3d Series $IE_1$ Trend:Generally increases, but irregular.

- **Cr (3d54s13d^54s^1), Cu (3d104s13d^{10}4s^1):** Higher IE1IE_1 due to stable d-configs after 4s14s^1 removal. - **Mn (3d54s23d^54s^2):** Exceptionally high IE3IE_3 (Mn2+Mn^{2+} is 3d53d^5). - **Zn (3d104s23d^{10}4s^2):** Exceptionally high IE3IE_3 (Zn2+Zn^{2+} is 3d103d^{10}).

  • Down a Group IE:5d > 4d due to Lanthanoid Contraction.
  • Oxidation States (OS):Hypothetical charge.
  • Transition Metals:Variable OS due to small energy difference between (n1)d(n-1)d and nsns orbitals.
  • Max OS Trend:Increases up to Mn (+7), then decreases.
  • Stable OS:d0,d5,d10d^0, d^5, d^{10} configurations are highly stable (e.g., Sc3+Sc^{3+} (d0d^0), Mn2+Mn^{2+} (d5d^5), Zn2+Zn^{2+} (d10d^{10})).
  • Higher OS Stability:Favored by highly electronegative ligands (O, F).
  • Disproportionation:Element in intermediate OS simultaneously oxidizes and reduces (e.g., 2Cu+Cu2++Cu2Cu^+ \rightarrow Cu^{2+} + Cu).

In Oxidation, Variable Charges Make Fun Compounds, Never Consistently Zero.

  • Ionisation Enthalpy: Remember the general increase but focus on Cr, Cu (higher IE1IE_1) and Mn, Zn (higher IE3IE_3).
  • Oxidation States: Variable for transition metals.
  • Charges: Max OS increases up to Mn (+7).
  • Make: Mn has the widest range.
  • Fun: Fe commonly +2, +3.
  • Compounds: Cu shows +1, +2; +1 disproportionates.
  • Never: Ni mostly +2.
  • Consistently: Co mostly +2, +3.
  • Zero: Zn only +2 (stable d10d^{10}). Sc only +3 (stable d0d^0).

This mnemonic helps recall the key elements and their characteristic oxidation state patterns and IE exceptions.