Chemistry·Explained

Measurement of ΔU and ΔH — Explained

NEET UG
Updated 22 Mar 2026

Detailed Explanation

The measurement of changes in internal energy (ΔU\Delta U) and enthalpy (ΔH\Delta H) are cornerstones of chemical thermodynamics, providing quantitative insights into the energy transformations accompanying chemical reactions and physical processes.

These quantities are state functions, meaning their values depend only on the initial and final states of the system, not on the path taken. \n\n**1. Internal Energy Change (ΔU\Delta U) and Bomb Calorimetry:**\nInternal energy, UU, represents the total energy contained within a thermodynamic system, encompassing the kinetic and potential energies of its constituent particles.

The change in internal energy, ΔU\Delta U, for a process is given by the First Law of Thermodynamics: ΔU=q+w\Delta U = q + w, where qq is the heat exchanged and ww is the work done. \n\nTo measure ΔU\Delta U, we need to ensure that the process occurs under conditions where no work is done, specifically no pressure-volume work.

This is achieved in a bomb calorimeter, which is designed to operate at constant volume. \n\n* Principle: In a bomb calorimeter, the reaction takes place in a sealed, rigid steel vessel (the 'bomb') immersed in a known quantity of water.

Since the volume of the bomb is constant, dV=0dV = 0. Consequently, the pressure-volume work, w=PextΔVw = -P_{ext} \Delta V, becomes zero. Therefore, according to the First Law, ΔU=qV\Delta U = q_V, meaning the heat exchanged at constant volume (qVq_V) is equal to the change in internal energy.

\n* Construction: A typical bomb calorimeter consists of: \n A strong, sealed steel bomb where the reactants are placed, often with an ignition wire. \n A stirring mechanism to ensure uniform temperature distribution in the water.

\n A thermometer (often a very precise platinum resistance thermometer) to measure temperature changes. \n An insulating jacket to minimize heat exchange with the surroundings. \n* Procedure: \n 1.

A known mass of the substance to be combusted (e.g., a fuel) is placed in the bomb. \n 2. The bomb is sealed and filled with oxygen gas at high pressure to ensure complete combustion. \n 3. The bomb is then placed in a known mass of water within the calorimeter.

\n 4. The initial temperature of the water is recorded. \n 5. The reaction is initiated electrically (e.g., by passing current through the ignition wire). \n 6. The heat released by the combustion reaction raises the temperature of the water and the calorimeter components.

\n 7. The final temperature of the water is recorded after the reaction is complete and the temperature stabilizes. \n* Calculations: \n The heat absorbed by the calorimeter system (qcalorimeterq_{calorimeter}) is given by: \n

qcalorimeter=Ccalorimeter×ΔTq_{calorimeter} = C_{calorimeter} \times \Delta T
\n where CcalorimeterC_{calorimeter} is the heat capacity of the calorimeter (including the water and the bomb itself), and ΔT=TfinalTinitial\Delta T = T_{final} - T_{initial} is the observed temperature change.

\n Since the reaction occurs within the calorimeter, the heat released by the reaction (qreactionq_{reaction}) is equal in magnitude but opposite in sign to the heat absorbed by the calorimeter: \n

qreaction=qcalorimeter=Ccalorimeter×ΔTq_{reaction} = -q_{calorimeter} = -C_{calorimeter} \times \Delta T
\n As established, for a constant volume process, qreaction=ΔUq_{reaction} = \Delta U.

Therefore, ΔU=Ccalorimeter×ΔT\Delta U = -C_{calorimeter} \times \Delta T. \n The heat capacity of the calorimeter, CcalorimeterC_{calorimeter}, is usually determined by a separate calibration experiment using a substance with a known heat of combustion (e.

g., benzoic acid). \n\n**2. Enthalpy Change (ΔH\Delta H) and Coffee-Cup Calorimetry:**\nEnthalpy, HH, is a thermodynamic potential defined as H=U+PVH = U + PV. It is particularly useful for processes occurring at constant pressure, which are common in chemical laboratories and biological systems.

The change in enthalpy, ΔH\Delta H, for a process at constant pressure is equal to the heat exchanged (qPq_P). \n\n* Principle: In a coffee-cup calorimeter, the reaction occurs in a solution open to the atmosphere, meaning the pressure remains constant.

While the volume may change slightly, the primary condition is constant pressure. Under these conditions, the heat exchanged is directly equal to the enthalpy change: ΔH=qP\Delta H = q_P. \n* Construction: A coffee-cup calorimeter is a simpler, less robust device than a bomb calorimeter.

It typically consists of: \n Two nested Styrofoam cups (Styrofoam is a good insulator, minimizing heat loss to the surroundings). \n A lid with a hole for a thermometer and a stirring rod. \n * A thermometer to measure temperature changes.

\n* Procedure: \n 1. Known volumes/masses of reactants (often in solution) are mixed in the inner Styrofoam cup. \n 2. The initial temperature of the solution is recorded. \n 3. The reaction proceeds, and the heat released or absorbed changes the temperature of the solution.

\n 4. The solution is stirred to ensure uniform temperature. \n 5. The final temperature of the solution is recorded after the reaction is complete. \n* Calculations: \n The heat absorbed or released by the solution (qsolutionq_{solution}) is calculated using: \n

qsolution=msolution×csolution×ΔTq_{solution} = m_{solution} \times c_{solution} \times \Delta T
\n where msolutionm_{solution} is the total mass of the solution, csolutionc_{solution} is the specific heat capacity of the solution (often approximated as that of water, $4.

184 \text{ J/g\textdegree C}),and), and\Delta T = T_{final} - T_{initial}.\nTheheatofthereaction(. \n The heat of the reaction (q_{reaction})isequalinmagnitudebutoppositeinsigntotheheatabsorbedbythesolution:\n) is equal in magnitude but opposite in sign to the heat absorbed by the solution: \nqreaction=qsolution=(msolution×csolution×ΔT)q_{reaction} = -q_{solution} = -(m_{solution} \times c_{solution} \times \Delta T)\nForaconstantpressureprocess,\n For a constant pressure process,q_{reaction} = \Delta H$.

Therefore, ΔH=(msolution×csolution×ΔT)\Delta H = -(m_{solution} \times c_{solution} \times \Delta T). \n The heat capacity of the calorimeter itself (the Styrofoam cups) is often neglected due to its small value, or it can be included if a more precise measurement is required.

\n\n**3. Relationship between ΔU\Delta U and ΔH\Delta H:**\nWhile ΔU\Delta U and ΔH\Delta H are distinct, they are related. From the definition of enthalpy, H=U+PVH = U + PV, the change in enthalpy can be written as: \n

ΔH=ΔU+Δ(PV)\Delta H = \Delta U + \Delta (PV)
\n For processes occurring at constant temperature and pressure, and assuming ideal gas behavior for gaseous reactants/products, we can write: \n
Δ(PV)=PΔV+VΔP\Delta (PV) = P \Delta V + V \Delta P
\n At constant pressure, ΔP=0\Delta P = 0, so Δ(PV)=PΔV\Delta (PV) = P \Delta V.

\n Thus, ΔH=ΔU+PΔV\Delta H = \Delta U + P \Delta V. \n Using the ideal gas law, PV=nRTPV = nRT, for a change involving gases at constant temperature and pressure, PΔV=ΔngRTP \Delta V = \Delta n_g RT, where Δng\Delta n_g is the change in the number of moles of gaseous products minus the number of moles of gaseous reactants.

\n Therefore, the relationship becomes: \n

ΔH=ΔU+ΔngRT\Delta H = \Delta U + \Delta n_g RT
\n * If Δng=0\Delta n_g = 0 (no change in moles of gas), then ΔH=ΔU\Delta H = \Delta U. This is often the case for reactions involving only liquids and solids, or reactions where the number of moles of gaseous reactants equals the number of moles of gaseous products.

\n * If Δng>0\Delta n_g > 0 (more moles of gas produced), then ΔH>ΔU\Delta H > \Delta U (for exothermic reactions, ΔH\Delta H is more negative than ΔU\Delta U; for endothermic reactions, ΔH\Delta H is more positive than ΔU\Delta U).

\n * If Δng<0\Delta n_g < 0 (fewer moles of gas produced), then ΔH<ΔU\Delta H < \Delta U (for exothermic reactions, ΔH\Delta H is less negative than ΔU\Delta U; for endothermic reactions, ΔH\Delta H is less positive than ΔU\Delta U).

\n\nCommon Misconceptions & NEET-Specific Angle:\n* Units: Always pay attention to units. Energy is typically in Joules (J) or kilojoules (kJ). Temperature in Kelvin (K) or Celsius (\textdegree C) for ΔT\Delta T, but always Kelvin for TT in RTRT terms.

Gas constant RR must be chosen appropriately (e.g., 8.314 J/mol\cdotK8.314 \text{ J/mol\cdot K} or 0.0821 L\cdotatm/mol\cdotK0.0821 \text{ L\cdot atm/mol\cdot K}). \n* Sign Convention: Heat absorbed by the system (qq) is positive; heat released is negative.

Work done by the system (ww) is negative; work done on the system is positive. ΔU\Delta U and ΔH\Delta H follow the same sign convention as qq. \n* Calorimeter Heat Capacity: For bomb calorimetry, CcalorimeterC_{calorimeter} includes the bomb, water, and stirrer.

For coffee-cup, it's often just the solution, but sometimes the cups' heat capacity is considered. \n* Ideal Gas Assumption: The relationship ΔH=ΔU+ΔngRT\Delta H = \Delta U + \Delta n_g RT relies on ideal gas behavior, which is a reasonable approximation for many NEET problems.

\n* Exothermic vs. Endothermic: Remember that negative ΔH\Delta H or ΔU\Delta U indicates an exothermic reaction (releases heat), and positive indicates an endothermic reaction (absorbs heat). \n* NEET Focus: Questions often involve calculating ΔU\Delta U or ΔH\Delta H from calorimetry data, or interconverting between them using the ΔngRT\Delta n_g RT relationship.

Be prepared for problems involving specific heat capacities, molar masses, and stoichiometry.

Often confused with

Side-by-side differences the NEET paper likes to test.

Measurement of ΔU and ΔH vs Coffee-Cup Calorimetry
AspectMeasurement of ΔU and ΔHCoffee-Cup Calorimetry
Operating ConditionConstant VolumeConstant Pressure
Thermodynamic Quantity Measured$\Delta U$ (Change in Internal Energy)$\Delta H$ (Change in Enthalpy)
Work DoneNo pressure-volume work ($w=0$)Pressure-volume work can be done ($w \neq 0$)
ConstructionRigid, sealed steel bomb, insulated jacket, stirrer, thermometerNested Styrofoam cups, lid, stirrer, thermometer
Typical ReactionsCombustion reactions, reactions involving gases at high pressureReactions in solution (neutralization, dissolution, precipitation)
Precision/AccuracyHigh precision, more accurate for combustionLower precision, prone to heat loss, approximations often made
Heat Capacity ConsiderationHeat capacity of entire calorimeter system ($C_{calorimeter}$) is crucialHeat capacity of solution (often water) is primary, calorimeter heat capacity often neglected

Bomb calorimetry and coffee-cup calorimetry are distinct methods for measuring energy changes in chemical reactions, each suited for different conditions and yielding different thermodynamic quantities.

Bomb calorimetry operates at constant volume, directly measuring the change in internal energy (ΔU\Delta U), and is ideal for combustion reactions due to its robust, sealed design. Coffee-cup calorimetry, conversely, operates at constant pressure, directly measuring the change in enthalpy (ΔH\Delta H), and is simpler, making it suitable for reactions in aqueous solutions.

The choice of calorimeter depends on the reaction type and the specific thermodynamic quantity required.

Why it is tested: NEET relevance: Understanding the differences between these two calorimetric methods is fundamental for solving problems related to $\Delta U$ and $\Delta H$ calculations. Questions often test the conditions under which each calorimeter is used, the quantity it measures, and the associated calculations. It's crucial for students to differentiate between $q_V$ and $q_P$ and their experimental determination.

Questions students ask

6 answered on this topic.

What is the fundamental difference between $\Delta U$ and $\Delta H$?

The fundamental difference lies in the conditions under which the heat exchange is measured. ΔU\Delta U (change in internal energy) represents the heat exchanged when a process occurs at constant volume (qVq_V).

Under these conditions, no pressure-volume work is done by or on the system. In contrast, ΔH\Delta H (change in enthalpy) represents the heat exchanged when a process occurs at constant pressure (qPq_P).

At constant pressure, the system can expand or contract, meaning pressure-volume work can be done. Thus, ΔH\Delta H accounts for both the change in internal energy and any associated pressure-volume work.

Why is a bomb calorimeter used for $\Delta U$ and a coffee-cup calorimeter for $\Delta H$?

A bomb calorimeter is designed to be a rigid, sealed vessel, ensuring that the volume of the reacting system remains constant. This constant volume condition is crucial because it eliminates pressure-volume work (w=PΔV=0w = -P\Delta V = 0), making the measured heat directly equal to ΔU\Delta U.

A coffee-cup calorimeter, on the other hand, is an open system (or nearly so) to the atmosphere, meaning the reaction occurs at constant atmospheric pressure. Under constant pressure, the heat exchanged is directly equal to ΔH\Delta H, as it accounts for any work done by volume changes.

What is the significance of the term $\Delta n_g RT$ in the relationship between $\Delta U$ and $\Delta H$?

The term ΔngRT\Delta n_g RT accounts for the pressure-volume work done when there is a change in the number of moles of gaseous substances during a reaction at constant temperature and pressure. Δng\Delta n_g is the difference between the sum of the moles of gaseous products and the sum of the moles of gaseous reactants.

If Δng\Delta n_g is non-zero, it means the system's volume changes due to gas production or consumption, leading to work being done. This work is the difference between ΔH\Delta H and ΔU\Delta U. If Δng=0\Delta n_g = 0, then ΔH=ΔU\Delta H = \Delta U because no net pressure-volume work is done by gases.

How is the heat capacity of a calorimeter determined?

The heat capacity of a calorimeter (CcalorimeterC_{calorimeter}) is typically determined through a calibration experiment. A substance with a precisely known heat of combustion (e.g., benzoic acid) is combusted in the calorimeter, and the resulting temperature change is measured.

Since the heat released by the known substance is known, and the temperature change is measured, the heat capacity of the entire calorimeter assembly (bomb, water, stirrer, thermometer) can be calculated using the formula Ccalorimeter=qknown_reaction/ΔTC_{calorimeter} = -q_{known\_reaction} / \Delta T.

This value is then used for subsequent measurements of unknown reactions.

Can $\Delta U$ and $\Delta H$ ever be equal?

Yes, ΔU\Delta U and ΔH\Delta H can be equal under specific conditions. This occurs when there is no change in the number of moles of gaseous substances during a reaction (i.e., Δng=0\Delta n_g = 0). This includes reactions where all reactants and products are in the solid or liquid phase, or gas-phase reactions where the total moles of gaseous products equal the total moles of gaseous reactants.

In such cases, the PΔVP\Delta V or ΔngRT\Delta n_g RT term in the relationship ΔH=ΔU+PΔV\Delta H = \Delta U + P\Delta V becomes zero, making ΔH=ΔU\Delta H = \Delta U.

What are the limitations of coffee-cup calorimetry?

Coffee-cup calorimetry is a relatively simple and inexpensive method, but it has several limitations. Firstly, it assumes negligible heat loss to the surroundings, which is not entirely true even with Styrofoam cups, leading to some inaccuracy.

Secondly, it's generally suitable for reactions in solution that do not involve significant gas evolution or consumption, as large volume changes can affect the constant pressure assumption. Thirdly, the specific heat capacity of the solution is often approximated as that of water, which might not be accurate for concentrated solutions.

Finally, it cannot be used for combustion reactions or reactions requiring very high temperatures or pressures.