Chemistry·MCQ Practice

Conductance in Electrolytic Solutions — MCQ Practice

NEET UG
Updated 13 Sep 2026

Interactive MCQ Practice

Test your knowledge. Click “Solve” to reveal options, select your answer, then check the result. 6 questions available.

Q1medium

The resistance of a 0.01,M0.01,M solution of an electrolyte was found to be 210,Ω210,\Omega at 298,K298,K. The cell constant is 0.88,cm−10.88,cm^{-1}. Calculate the molar conductivity of the solution.

Q2medium

Which of the following statements is INCORRECT regarding electrolytic conductance?

Q3medium

Given the limiting molar conductivities: Λm0(NaCl)=126.4,S⋅cm2⋅mol−1\Lambda_m^0(NaCl) = 126.4,S \cdot cm^2 \cdot mol^{-1}, Λm0(HCl)=425.9,S⋅cm2⋅mol−1\Lambda_m^0(HCl) = 425.9,S \cdot cm^2 \cdot mol^{-1}, Λm0(CH3COONa)=91.0,S⋅cm2⋅mol−1\Lambda_m^0(CH_3COONa) = 91.0,S \cdot cm^2 \cdot mol^{-1}. Calculate the limiting molar conductivity for acetic acid (CH3COOHCH_3COOH).

Q4easy

The conductivity of 0.20,M0.20,M solution of KCl at 298,K298,K is 0.0248,S⋅cm−10.0248,S \cdot cm^{-1}. Calculate its molar conductivity.

Q5easy

The molar conductivity of a 0.001,M0.001,M acetic acid solution is 4.95,S⋅cm2⋅mol−14.95,S \cdot cm^2 \cdot mol^{-1}. If the limiting molar conductivity of acetic acid is 390.5,S⋅cm2⋅mol−1390.5,S \cdot cm^2 \cdot mol^{-1}, calculate its degree of dissociation (α\alpha).

Q6hard

Which of the following factors does NOT affect the molar conductivity of an electrolytic solution?