Chemistry·MCQ Practice

Nernst Equation — MCQ Practice

NEET UG
Version 1Updated 22 Mar 2026

Interactive MCQ Practice

Test your knowledge. Click “Solve” to reveal options, select your answer, then check the result. 7 questions available.

Q1medium

Calculate the electrode potential of a zinc electrode dipped in 0.01,M0.01,\text{M} ZnSO4ZnSO_4 solution at 25C25^{\circ}\text{C}. Given EZn2+/Zn=0.76,VE^{\circ}_{Zn^{2+}/Zn} = -0.76,\text{V}.

Q2hard

For the cell Cu(s)Cu2+(aq,0.1M)Ag+(aq,0.01M)Ag(s)Cu(s)|Cu^{2+}(aq, 0.1M)||Ag^+(aq, 0.01M)|Ag(s) at 298,K298,\text{K}, calculate the cell potential. Given ECu2+/Cu=+0.34,VE^{\circ}_{Cu^{2+}/Cu} = +0.34,\text{V} and EAg+/Ag=+0.80,VE^{\circ}_{Ag^+/Ag} = +0.80,\text{V}.

Q3medium

At what concentration of Cu2+Cu^{2+} will the electrode potential of a copper electrode be 0.28,V0.28,\text{V} at 298,K298,\text{K}? Given ECu2+/Cu=+0.34,VE^{\circ}_{Cu^{2+}/Cu} = +0.34,\text{V}.

Q4easy

Which of the following statements about the Nernst equation is INCORRECT?

Q5hard

For the reaction 2Cr(s)+3Cd2+(aq)2Cr3+(aq)+3Cd(s)2Cr(s) + 3Cd^{2+}(aq) \rightarrow 2Cr^{3+}(aq) + 3Cd(s), if Ecell=0.34,VE^{\circ}_{cell} = 0.34,\text{V} and the concentrations are [Cr3+]=0.1,M[Cr^{3+}] = 0.1,\text{M} and [Cd2+]=0.001,M[Cd^{2+}] = 0.001,\text{M} at 298,K298,\text{K}, what is the cell potential?

Q6easy

For a reaction, Ecell=0.0592,VE^{\circ}_{cell} = 0.0592,\text{V} at 298,K298,\text{K} and n=1n=1. What is the equilibrium constant (KeqK_{eq}) for this reaction?

Q7medium

If the temperature of an electrochemical cell increases, how does the cell potential (EcellE_{cell}) generally change according to the Nernst equation, assuming Q>1Q > 1 and EcellE^{\circ}_{cell} is positive?

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