Chemistry·MCQ Practice

Nernst Equation — MCQ Practice

NEET UG
Updated 13 Sep 2026

Interactive MCQ Practice

Test your knowledge. Click “Solve” to reveal options, select your answer, then check the result. 7 questions available.

Q1medium

Calculate the electrode potential of a zinc electrode dipped in 0.01 M0.01\,\text{M} ZnSO4ZnSO_4 solution at 25∘C25^{\circ}\text{C}. Given EZn2+/Zn∘=−0.76 VE^{\circ}_{Zn^{2+}/Zn} = -0.76\,\text{V}.

Q2hard

For the cell Cu(s)∣Cu2+(aq,0.1M)∣∣Ag+(aq,0.01M)∣Ag(s)Cu(s)|Cu^{2+}(aq, 0.1M)||Ag^+(aq, 0.01M)|Ag(s) at 298 K298\,\text{K}, calculate the cell potential. Given ECu2+/Cu∘=+0.34 VE^{\circ}_{Cu^{2+}/Cu} = +0.34\,\text{V} and EAg+/Ag∘=+0.80 VE^{\circ}_{Ag^+/Ag} = +0.80\,\text{V}.

Q3medium

At what concentration of Cu2+Cu^{2+} will the electrode potential of a copper electrode be 0.28 V0.28\,\text{V} at 298 K298\,\text{K}? Given ECu2+/Cu∘=+0.34 VE^{\circ}_{Cu^{2+}/Cu} = +0.34\,\text{V}.

Q4easy

Which of the following statements about the Nernst equation is INCORRECT?

Q5hard

For the reaction 2Cr(s)+3Cd2+(aq)→2Cr3+(aq)+3Cd(s)2Cr(s) + 3Cd^{2+}(aq) \rightarrow 2Cr^{3+}(aq) + 3Cd(s), if Ecell∘=0.34 VE^{\circ}_{cell} = 0.34\,\text{V} and the concentrations are [Cr3+]=0.1 M[Cr^{3+}] = 0.1\,\text{M} and [Cd2+]=0.001 M[Cd^{2+}] = 0.001\,\text{M} at 298 K298\,\text{K}, what is the cell potential?

Q6easy

For a reaction, Ecell∘=0.0592 VE^{\circ}_{cell} = 0.0592\,\text{V} at 298 K298\,\text{K} and n=1n=1. What is the equilibrium constant (KeqK_{eq}) for this reaction?

Q7medium

If the temperature of an electrochemical cell increases, how does the cell potential (EcellE_{cell}) generally change according to the Nernst equation, assuming Q>1Q > 1 and Ecell∘E^{\circ}_{cell} is positive?