Physics·Revision Notes

Dynamics of Rotational Motion — Revision Notes

NEET UG
Version 1Updated 22 Mar 2026

⚡ 30-Second Revision

  • Torque:τ=r×F\vec{\tau} = \vec{r} \times \vec{F}, magnitude τ=rFsinθ\tau = rF\sin\theta. Unit: N\cdot m.\n- Moment of Inertia (I): Rotational inertia. I=miri2I = \sum m_i r_i^2 (discrete), I=r2dmI = \int r^2 dm (continuous). Unit: kg\cdot m2^2.\n- Newton's 2nd Law for Rotation: τnet=Iα\vec{\tau}_{net} = I\vec{\alpha}.\n- Angular Momentum (L): L=Iω\vec{L} = I\vec{\omega} (rigid body), L=r×p\vec{L} = \vec{r} \times \vec{p} (particle). Unit: kg\cdot m2^2/s or J\cdot s.\n- Conservation of Angular Momentum: If τnet=0\vec{\tau}_{net} = 0, then L=constant    I1ω1=I2ω2\vec{L} = \text{constant} \implies I_1\omega_1 = I_2\omega_2.\n- Rotational Kinetic Energy: Krot=12Iω2K_{rot} = \frac{1}{2}I\omega^2.\n- Total Kinetic Energy (Rolling): Ktotal=12MvCM2+12ICMω2K_{total} = \frac{1}{2}Mv_{CM}^2 + \frac{1}{2}I_{CM}\omega^2.\n- Rolling without Slipping: vCM=Rωv_{CM} = R\omega, aCM=Rαa_{CM} = R\alpha.\n- Parallel Axis Theorem: I=ICM+Md2I = I_{CM} + Md^2.\n- Perpendicular Axis Theorem (planar body): Iz=Ix+IyI_z = I_x + I_y.

2-Minute Revision

Rotational dynamics extends linear mechanics to spinning objects. The key players are **torque (τ\tau), the rotational equivalent of force, which causes angular acceleration (α\alpha), and moment of inertia (I)**, the rotational equivalent of mass, which resists angular acceleration.

Newton's second law for rotation is τ=Iα\tau = I\alpha. Angular momentum (L=IωL = I\omega) is the rotational quantity of motion. Crucially, if no external torque acts on a system, its angular momentum is conserved (Iω=constantI\omega = \text{constant}).

This explains phenomena like a figure skater's spin. For objects rolling without slipping, total kinetic energy is the sum of translational and rotational components (Ktotal=12MvCM2+12ICMω2K_{total} = \frac{1}{2}Mv_{CM}^2 + \frac{1}{2}I_{CM}\omega^2), with vCM=Rωv_{CM} = R\omega.

Remember standard moments of inertia for common shapes and use the parallel axis theorem (I=ICM+Md2I = I_{CM} + Md^2) when the axis is not through the center of mass. Pay attention to vector directions for torque and angular momentum.

5-Minute Revision

Dynamics of rotational motion governs how rigid bodies rotate under the influence of forces. The fundamental concept is **torque (τ\vec{\tau})**, defined as r×F\vec{r} \times \vec{F}, which is the rotational analogue of force.

It causes **angular acceleration (α\vec{\alpha}). The resistance to this angular acceleration is quantified by the moment of inertia (I)**, which depends on both mass and its distribution relative to the axis of rotation (I=miri2I = \sum m_i r_i^2).

Newton's second law for rotation states τnet=Iα\vec{\tau}_{net} = I\vec{\alpha}. \n\n**Angular momentum (L\vec{L})**, the rotational analogue of linear momentum, is given by L=Iω\vec{L} = I\vec{\omega} for a rigid body.

A cornerstone principle is the conservation of angular momentum: if the net external torque on a system is zero, its total angular momentum remains constant (I1ω1=I2ω2I_1\omega_1 = I_2\omega_2). This is vital for problems involving changing mass distribution.

\n\nRotational kinetic energy is Krot=12Iω2K_{rot} = \frac{1}{2}I\omega^2. For rolling motion without slipping, an object has both translational and rotational kinetic energy, so Ktotal=12MvCM2+12ICMω2K_{total} = \frac{1}{2}Mv_{CM}^2 + \frac{1}{2}I_{CM}\omega^2.

The condition for rolling without slipping is vCM=Rωv_{CM} = R\omega and aCM=Rαa_{CM} = R\alpha. When objects roll down an incline, their acceleration depends on their moment of inertia, with objects having smaller I/MR2I/MR^2 ratios (like a solid sphere) accelerating faster.

\n\nRemember the Parallel Axis Theorem (I=ICM+Md2I = I_{CM} + Md^2) to find moment of inertia about an axis parallel to one through the center of mass. For planar bodies, the Perpendicular Axis Theorem (Iz=Ix+IyI_z = I_x + I_y) is useful.

Practice problems involving pulley systems with massive pulleys, where both linear and rotational dynamics are coupled, and energy conservation problems involving rotational motion.

Prelims Revision Notes

    1
  1. Rotational Analogues:Understand the correspondence: Force \leftrightarrow Torque (τ\tau), Mass \leftrightarrow Moment of Inertia (I), Linear Velocity \leftrightarrow Angular Velocity (ω\omega), Linear Acceleration \leftrightarrow Angular Acceleration (α\alpha), Linear Momentum \leftrightarrow Angular Momentum (L), Kinetic Energy (Translational) \leftrightarrow Kinetic Energy (Rotational). \n2. Torque: τ=r×F\vec{\tau} = \vec{r} \times \vec{F}. Magnitude τ=rFsinθ\tau = rF\sin\theta. Direction by right-hand rule. \n3. Moment of Inertia (I): I=miri2I = \sum m_i r_i^2. Standard formulas: \n * Ring/Hollow Cylinder (about central axis): MR2MR^2 \n * Disc/Solid Cylinder (about central axis): 12MR2\frac{1}{2}MR^2 \n * Solid Sphere (about diameter): 25MR2\frac{2}{5}MR^2 \n * Hollow Sphere (about diameter): 23MR2\frac{2}{3}MR^2 \n * Rod (about center, perpendicular): 112ML2\frac{1}{12}ML^2 \n * Rod (about end, perpendicular): 13ML2\frac{1}{3}ML^2 \n4. Theorems: \n * Parallel Axis Theorem: I=ICM+Md2I = I_{CM} + Md^2. \n * Perpendicular Axis Theorem (planar body): Iz=Ix+IyI_z = I_x + I_y. \n5. Newton's Second Law for Rotation: τnet=Iα\vec{\tau}_{net} = I\vec{\alpha}. \n6. Angular Momentum: L=Iω\vec{L} = I\vec{\omega}. For a particle, L=r×mv\vec{L} = \vec{r} \times m\vec{v}. \n7. Conservation of Angular Momentum: If τnet,ext=0\vec{\tau}_{net, ext} = 0, then Linitial=Lfinal    I1ω1=I2ω2L_{initial} = L_{final} \implies I_1\omega_1 = I_2\omega_2. \n8. Rotational Kinetic Energy: Krot=12Iω2K_{rot} = \frac{1}{2}I\omega^2. \n9. Rolling Motion (without slipping): \n * vCM=Rωv_{CM} = R\omega, aCM=Rαa_{CM} = R\alpha. \n * Total Kinetic Energy: Ktotal=12MvCM2+12ICMω2K_{total} = \frac{1}{2}Mv_{CM}^2 + \frac{1}{2}I_{CM}\omega^2. \n * Acceleration down incline: a=gsinθ1+ICM/MR2a = \frac{g\sin\theta}{1 + I_{CM}/MR^2}. Object with smaller ICM/MR2I_{CM}/MR^2 (e.g., solid sphere = 2/5) has greater acceleration. \n10. Work and Power: Rotational Work W=τθW = \tau\theta. Rotational Power P=τωP = \tau\omega.

Vyyuha Quick Recall

To remember the rotational analogues: 'For My Angular Teacher, I Always Learn Well.' \nForce \rightarrow Torque (τ\tau) \nMass \rightarrow Inertia (I) \nAcceleration (linear) \rightarrow Acceleration (angular, α\alpha) \nLinear momentum \rightarrow L (Angular momentum) \nWork \rightarrow Work (rotational)

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