Physics·Revision Notes

Dynamics of Rotational Motion — Revision Notes

NEET UG
Updated 13 Sep 2026

⚡ 30-Second Revision

  • Torque: — τ⃗=r⃗×F⃗\vec{\tau} = \vec{r} \times \vec{F}, magnitude τ=rFsin⁡θ\tau = rF\sin\theta. Unit: N\cdot m.\n- Moment of Inertia (I): Rotational inertia. I=∑miri2I = \sum m_i r_i^2 (discrete), I=∫r2dmI = \int r^2 dm (continuous). Unit: kg\cdot m2^2.\n- Newton's 2nd Law for Rotation: τ⃗net=Iα⃗\vec{\tau}_{net} = I\vec{\alpha}.\n- Angular Momentum (L): L⃗=Iω⃗\vec{L} = I\vec{\omega} (rigid body), L⃗=r⃗×p⃗\vec{L} = \vec{r} \times \vec{p} (particle). Unit: kg\cdot m2^2/s or J\cdot s.\n- Conservation of Angular Momentum: If τ⃗net=0\vec{\tau}_{net} = 0, then L⃗=constant  ⟹  I1ω1=I2ω2\vec{L} = \text{constant} \implies I_1\omega_1 = I_2\omega_2.\n- Rotational Kinetic Energy: Krot=12Iω2K_{rot} = \frac{1}{2}I\omega^2.\n- Total Kinetic Energy (Rolling): Ktotal=12MvCM2+12ICMω2K_{total} = \frac{1}{2}Mv_{CM}^2 + \frac{1}{2}I_{CM}\omega^2.\n- Rolling without Slipping: vCM=Rωv_{CM} = R\omega, aCM=Rαa_{CM} = R\alpha.\n- Parallel Axis Theorem: I=ICM+Md2I = I_{CM} + Md^2.\n- Perpendicular Axis Theorem (planar body): Iz=Ix+IyI_z = I_x + I_y.

2-Minute Revision

Rotational dynamics extends linear mechanics to spinning objects. The key players are **torque (τ\tau), the rotational equivalent of force, which causes angular acceleration (α\alpha), and moment of inertia (I)**, the rotational equivalent of mass, which resists angular acceleration.

Newton's second law for rotation is τ=Iα\tau = I\alpha. Angular momentum (L=IωL = I\omega) is the rotational quantity of motion. Crucially, if no external torque acts on a system, its angular momentum is conserved (Iω=constantI\omega = \text{constant}).

This explains phenomena like a figure skater's spin. For objects rolling without slipping, total kinetic energy is the sum of translational and rotational components (Ktotal=12MvCM2+12ICMω2K_{total} = \frac{1}{2}Mv_{CM}^2 + \frac{1}{2}I_{CM}\omega^2), with vCM=Rωv_{CM} = R\omega.

Remember standard moments of inertia for common shapes and use the parallel axis theorem (I=ICM+Md2I = I_{CM} + Md^2) when the axis is not through the center of mass. Pay attention to vector directions for torque and angular momentum.

5-Minute Revision

Dynamics of rotational motion governs how rigid bodies rotate under the influence of forces. The fundamental concept is **torque (τ⃗\vec{\tau})**, defined as r⃗×F⃗\vec{r} \times \vec{F}, which is the rotational analogue of force.

It causes **angular acceleration (α⃗\vec{\alpha}). The resistance to this angular acceleration is quantified by the moment of inertia (I)**, which depends on both mass and its distribution relative to the axis of rotation (I=∑miri2I = \sum m_i r_i^2).

Newton's second law for rotation states τ⃗net=Iα⃗\vec{\tau}_{net} = I\vec{\alpha}. \n\n**Angular momentum (L⃗\vec{L})**, the rotational analogue of linear momentum, is given by L⃗=Iω⃗\vec{L} = I\vec{\omega} for a rigid body.

A cornerstone principle is the conservation of angular momentum: if the net external torque on a system is zero, its total angular momentum remains constant (I1ω1=I2ω2I_1\omega_1 = I_2\omega_2). This is vital for problems involving changing mass distribution.

\n\nRotational kinetic energy is Krot=12Iω2K_{rot} = \frac{1}{2}I\omega^2. For rolling motion without slipping, an object has both translational and rotational kinetic energy, so Ktotal=12MvCM2+12ICMω2K_{total} = \frac{1}{2}Mv_{CM}^2 + \frac{1}{2}I_{CM}\omega^2.

The condition for rolling without slipping is vCM=Rωv_{CM} = R\omega and aCM=Rαa_{CM} = R\alpha. When objects roll down an incline, their acceleration depends on their moment of inertia, with objects having smaller I/MR2I/MR^2 ratios (like a solid sphere) accelerating faster.

\n\nRemember the Parallel Axis Theorem (I=ICM+Md2I = I_{CM} + Md^2) to find moment of inertia about an axis parallel to one through the center of mass. For planar bodies, the Perpendicular Axis Theorem (Iz=Ix+IyI_z = I_x + I_y) is useful.

Practice problems involving pulley systems with massive pulleys, where both linear and rotational dynamics are coupled, and energy conservation problems involving rotational motion.

Prelims Revision Notes

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  1. Rotational Analogues: — Understand the correspondence: Force ↔\leftrightarrow Torque (τ\tau), Mass ↔\leftrightarrow Moment of Inertia (I), Linear Velocity ↔\leftrightarrow Angular Velocity (ω\omega), Linear Acceleration ↔\leftrightarrow Angular Acceleration (α\alpha), Linear Momentum ↔\leftrightarrow Angular Momentum (L), Kinetic Energy (Translational) ↔\leftrightarrow Kinetic Energy (Rotational). \n2. Torque: τ⃗=r⃗×F⃗\vec{\tau} = \vec{r} \times \vec{F}. Magnitude τ=rFsin⁡θ\tau = rF\sin\theta. Direction by right-hand rule. \n3. Moment of Inertia (I): I=∑miri2I = \sum m_i r_i^2. Standard formulas: \n * Ring/Hollow Cylinder (about central axis): MR2MR^2 \n * Disc/Solid Cylinder (about central axis): 12MR2\frac{1}{2}MR^2 \n * Solid Sphere (about diameter): 25MR2\frac{2}{5}MR^2 \n * Hollow Sphere (about diameter): 23MR2\frac{2}{3}MR^2 \n * Rod (about center, perpendicular): 112ML2\frac{1}{12}ML^2 \n * Rod (about end, perpendicular): 13ML2\frac{1}{3}ML^2 \n4. Theorems: \n * Parallel Axis Theorem: I=ICM+Md2I = I_{CM} + Md^2. \n * Perpendicular Axis Theorem (planar body): Iz=Ix+IyI_z = I_x + I_y. \n5. Newton's Second Law for Rotation: τ⃗net=Iα⃗\vec{\tau}_{net} = I\vec{\alpha}. \n6. Angular Momentum: L⃗=Iω⃗\vec{L} = I\vec{\omega}. For a particle, L⃗=r⃗×mv⃗\vec{L} = \vec{r} \times m\vec{v}. \n7. Conservation of Angular Momentum: If τ⃗net,ext=0\vec{\tau}_{net, ext} = 0, then Linitial=Lfinal  ⟹  I1ω1=I2ω2L_{initial} = L_{final} \implies I_1\omega_1 = I_2\omega_2. \n8. Rotational Kinetic Energy: Krot=12Iω2K_{rot} = \frac{1}{2}I\omega^2. \n9. Rolling Motion (without slipping): \n * vCM=Rωv_{CM} = R\omega, aCM=Rαa_{CM} = R\alpha. \n * Total Kinetic Energy: Ktotal=12MvCM2+12ICMω2K_{total} = \frac{1}{2}Mv_{CM}^2 + \frac{1}{2}I_{CM}\omega^2. \n * Acceleration down incline: a=gsin⁡θ1+ICM/MR2a = \frac{g\sin\theta}{1 + I_{CM}/MR^2}. Object with smaller ICM/MR2I_{CM}/MR^2 (e.g., solid sphere = 2/5) has greater acceleration. \n10. Work and Power: Rotational Work W=τθW = \tau\theta. Rotational Power P=τωP = \tau\omega.

Vyyuha Quick Recall

To remember the rotational analogues: 'For My Angular Teacher, I Always Learn Well.' \nForce →\rightarrow Torque (τ\tau) \nMass →\rightarrow Inertia (I) \nAcceleration (linear) →\rightarrow Acceleration (angular, α\alpha) \nLinear momentum →\rightarrow L (Angular momentum) \nWork →\rightarrow Work (rotational)