Physics

First Law of Thermodynamics

Physics·Revision Notes

Thermodynamic Processes — Revision Notes

NEET UG
Version 1Updated 24 Mar 2026

⚡ 30-Second Revision

  • First Law:DeltaU=QWDelta U = Q - W
  • Internal Energy (Ideal Gas):DeltaU=nCvDeltaTDelta U = nC_vDelta T
  • Work Done:W=intPdVW = int P dV
  • Isobaric ($P= ext{const}$):W=P(V2V1)W = P(V_2-V_1), Q=nCpDeltaTQ = nC_pDelta T
  • Isochoric ($V= ext{const}$):W=0W = 0, Q=nCvDeltaTQ = nC_vDelta T
  • Isothermal ($T= ext{const}$):DeltaU=0Delta U = 0, W=nRTln(V2/V1)W = nRT ln(V_2/V_1), Q=WQ = W
  • Adiabatic ($Q=0$):PVgamma=constPV^gamma = \text{const}, TVgamma1=constTV^{gamma-1} = \text{const}, P1gammaTgamma=constP^{1-gamma}T^gamma = \text{const}, W=P1V1P2V2gamma1=nCv(T1T2)W = \frac{P_1V_1 - P_2V_2}{gamma-1} = nC_v(T_1-T_2)
  • Cyclic Process:DeltaUcycle=0Delta U_{cycle} = 0, Qnet=WnetQ_{net} = W_{net}
  • Adiabatic Index:gamma=Cp/Cvgamma = C_p/C_v
  • Mayer's Relation:CpCv=RC_p - C_v = R

2-Minute Revision

Thermodynamic processes describe how a system changes state, involving heat (QQ) and work (WW) transfers. The First Law, DeltaU=QWDelta U = Q - W, is central. For an ideal gas, internal energy (DeltaUDelta U) depends only on temperature change (DeltaTDelta T), specifically DeltaU=nCvDeltaTDelta U = nC_vDelta T.

  • Isobaric (Constant Pressure):PP is constant. Work W=PDeltaVW = PDelta V. Heat Q=nCpDeltaTQ = nC_pDelta T. P-V diagram is a horizontal line.
  • Isochoric (Constant Volume):VV is constant. Work W=0W = 0. Heat Q=nCvDeltaTQ = nC_vDelta T. P-V diagram is a vertical line.
  • Isothermal (Constant Temperature):TT is constant. For ideal gas, DeltaU=0Delta U = 0. Work W=nRTln(V2/V1)W = nRT ln(V_2/V_1). Heat Q=WQ = W. P-V diagram is a hyperbola.
  • Adiabatic (No Heat Exchange):Q=0Q = 0. Work W=DeltaUW = -Delta U. PVgamma=constantPV^gamma = \text{constant}. P-V diagram is steeper than isothermal.
  • Cyclic Process:System returns to initial state. DeltaUcycle=0Delta U_{cycle} = 0, so Qnet=WnetQ_{net} = W_{net}. Work is the area enclosed on a P-V diagram. Remember sign conventions: QQ positive if added, WW positive if done by system.

5-Minute Revision

Thermodynamic processes are pathways for a system to transition between states, defined by changes in state variables like pressure (PP), volume (VV), and temperature (TT). Energy is exchanged as heat (QQ) and work (WW). The First Law of Thermodynamics, DeltaU=QWDelta U = Q - W, is the guiding principle, where DeltaUDelta U is the change in internal energy. For an ideal gas, DeltaUDelta U is solely dependent on temperature change, given by DeltaU=nCvDeltaTDelta U = nC_vDelta T.

Let's quickly review the key processes:

    1
  1. Isobaric Process (Constant Pressure):

* P=constantP = \text{constant}. * Work done: W=P(V2V1)W = P(V_2 - V_1). This is simply pressure times the change in volume. * Heat exchanged: Q=nCpDeltaTQ = nC_pDelta T. Here, CpC_p is molar specific heat at constant pressure. * P-V diagram: A horizontal line.

    1
  1. Isochoric Process (Constant Volume):

* V=constantV = \text{constant}. * Work done: W=0W = 0, because there's no change in volume. * Heat exchanged: Q=nCvDeltaTQ = nC_vDelta T. All heat goes into changing internal energy. * P-V diagram: A vertical line.

    1
  1. Isothermal Process (Constant Temperature):

* T=constantT = \text{constant}. * For an ideal gas, DeltaU=0Delta U = 0 since UU depends only on TT. * Work done: W=nRTln(V2/V1)W = nRT ln(V_2/V_1). Also W=P1V1ln(V2/V1)W = P_1V_1 ln(V_2/V_1). * Heat exchanged: Q=WQ = W (from DeltaU=QW=0Delta U = Q - W = 0). * P-V diagram: A hyperbola (PV=constantPV = \text{constant}). Example: A gas expands slowly in contact with a heat reservoir.

    1
  1. Adiabatic Process (No Heat Exchange):

* Q=0Q = 0. * From First Law: DeltaU=WDelta U = -W. Work done by the gas comes from its internal energy, causing temperature to drop during expansion. * Equations of state: PVgamma=constantPV^gamma = \text{constant}, TVgamma1=constantTV^{gamma-1} = \text{constant}, P1gammaTgamma=constantP^{1-gamma}T^gamma = \text{constant}, where gamma=Cp/Cvgamma = C_p/C_v. * Work done: W=P1V1P2V2gamma1=nCv(T1T2)W = \frac{P_1V_1 - P_2V_2}{gamma-1} = nC_v(T_1 - T_2). * P-V diagram: A steeper hyperbola than isothermal. Example: Rapid expansion/compression, or in a well-insulated container.

    1
  1. Cyclic Process:

* The system returns to its initial state. * DeltaUcycle=0Delta U_{cycle} = 0 (since UU is a state function). * From First Law: Qnet=WnetQ_{net} = W_{net}. The net heat absorbed equals the net work done. * Work done: Area enclosed by the loop on the P-V diagram. Clockwise loop means positive work (work done by system), counter-clockwise means negative work (work done on system).

Key Relations: CpCv=RC_p - C_v = R (Mayer's relation) and gamma=Cp/Cvgamma = C_p/C_v. Remember to use absolute temperature (Kelvin) in all calculations. Pay close attention to the sign conventions for QQ and WW!

Prelims Revision Notes

    1
  1. First Law of Thermodynamics:DeltaU=QWDelta U = Q - W. This is the energy conservation principle. DeltaUDelta U is change in internal energy, QQ is heat added to the system, WW is work done *by* the system.
  2. 2
  3. Internal Energy of Ideal Gas:U=nCvTU = nC_vT. Thus, DeltaU=nCvDeltaTDelta U = nC_vDelta T. It depends ONLY on temperature.
  4. 3
  5. Work Done ($W$):W=intPdVW = int P dV. Area under P-V curve. Positive for expansion, negative for compression.
  6. 4
  7. Isobaric Process (Constant Pressure):

* P=constantP = \text{constant}. * P-V diagram: Horizontal line. * Work: W=P(V2V1)W = P(V_2 - V_1). * Heat: Q=nCpDeltaTQ = nC_pDelta T. * DeltaU=nCvDeltaTDelta U = nC_vDelta T.

    1
  1. Isochoric Process (Constant Volume):

* V=constantV = \text{constant}. * P-V diagram: Vertical line. * Work: W=0W = 0. * Heat: Q=nCvDeltaTQ = nC_vDelta T. * DeltaU=QDelta U = Q.

    1
  1. Isothermal Process (Constant Temperature):

* T=constantT = \text{constant}. * P-V diagram: Hyperbola (PV=constantPV = \text{constant}). Boyle's Law applies. * Internal Energy: DeltaU=0Delta U = 0 (for ideal gas). * Work: W=nRTln(V2/V1)=P1V1ln(V2/V1)W = nRT ln(V_2/V_1) = P_1V_1 ln(V_2/V_1). * Heat: Q=WQ = W.

    1
  1. Adiabatic Process (No Heat Exchange):

* Q=0Q = 0. * P-V diagram: Steeper hyperbola than isothermal (PVgamma=constantPV^gamma = \text{constant}). Poisson's Law applies. * Internal Energy: DeltaU=WDelta U = -W. * Relations: PVgamma=constantPV^gamma = \text{constant}, TVgamma1=constantTV^{gamma-1} = \text{constant}, P1gammaTgamma=constantP^{1-gamma}T^gamma = \text{constant}. * Work: W=P1V1P2V2gamma1=nCv(T1T2)W = \frac{P_1V_1 - P_2V_2}{gamma-1} = nC_v(T_1 - T_2).

    1
  1. Cyclic Process:

* System returns to initial state. * DeltaUcycle=0Delta U_{cycle} = 0. * Net Heat: Qnet=WnetQ_{net} = W_{net}. * Work: Area enclosed by the loop on P-V diagram. Clockwise is positive work, counter-clockwise is negative.

    1
  1. Mayer's Relation:CpCv=RC_p - C_v = R.
  2. 2
  3. Adiabatic Index:gamma=Cp/Cvgamma = C_p/C_v.
  4. 3
  5. Units:Convert temperature to Kelvin. 1,Lcdotatm=101.3,J1,\text{L}cdot\text{atm} = 101.3,\text{J}. R=8.314,J/molcdotKR = 8.314,\text{J/mol}cdot\text{K}.

Vyyuha Quick Recall

Isothermal: Temperature Constant (TC) Adiabatic: Quantity of heat Zero (QZ) Isobaric: Pressure Constant (PC) Isochoric: Volume Constant (VC)

*Think: 'TC QZ PC VC' for the constant/zero quantity in each process.*

Featured
🎯PREP MANAGER
Your 6-Month Blueprint, Updated Nightly
AI analyses your progress every night. Wake up to a smarter plan. Every. Single. Day.
Ad Space
🎯PREP MANAGER
Your 6-Month Blueprint, Updated Nightly
AI analyses your progress every night. Wake up to a smarter plan. Every. Single. Day.