Physics·Core Principles

Thermodynamics — Core Principles

NEET UG
Updated 23 Mar 2026

Core Principles

Thermodynamics is the study of heat and its relationship to other forms of energy and work. It's built upon fundamental laws that govern energy transformations. The Zeroth Law defines temperature and thermal equilibrium.

The First Law is the principle of energy conservation: ΔU=QW\Delta U = Q - W, where ΔU\Delta U is the change in internal energy, QQ is heat supplied to the system, and WW is work done by the system.

The Second Law dictates the direction of spontaneous processes and introduces entropy (SS), a measure of disorder, stating that the total entropy of the universe always increases for spontaneous changes.

It also sets limits on the efficiency of heat engines. The Third Law establishes absolute zero as the point of zero entropy for a perfect crystal. Key processes include isothermal (ΔT=0\Delta T=0), adiabatic (Q=0Q=0), isobaric (ΔP=0\Delta P=0), and isochoric (ΔV=0\Delta V=0).

Work done is the area under the PVP-V curve. Heat engines convert heat into work, while refrigerators move heat using work. Understanding these concepts, along with sign conventions and specific formulas for ideal gases, is crucial for NEET.

Often confused with

Side-by-side differences the NEET paper likes to test.

Thermodynamics vs Isothermal Process
AspectThermodynamicsIsothermal Process
TemperatureRemains constant ($\Delta T = 0$).Changes (decreases during expansion, increases during compression).
Heat ExchangeHeat is exchanged with surroundings to maintain constant temperature ($Q \neq 0$).No heat exchange with surroundings ($Q = 0$). System is thermally insulated.
Internal Energy (Ideal Gas)Remains constant ($\Delta U = 0$) as $U$ depends only on $T$.Changes ($\Delta U = -W$) as temperature changes.
First Law Relation$Q = W$ (Heat absorbed equals work done by system).$\Delta U = -W$ (Change in internal energy equals negative of work done by system).
P-V Curve SlopeLess steep ($P V = \text{constant}$). Slope is $-P/V$.Steeper ($P V^\gamma = \text{constant}$). Slope is $-\gamma P/V$ (where $\gamma > 1$).
Work Done$W = nRT \ln(V_f/V_i)$.$W = \frac{nR(T_i - T_f)}{\gamma - 1}$.

Isothermal and adiabatic processes are two fundamental thermodynamic pathways, distinct primarily in their heat exchange characteristics. An isothermal process occurs at constant temperature, requiring continuous heat exchange with the surroundings to maintain this equilibrium.

Consequently, for an ideal gas, its internal energy remains unchanged, and any heat absorbed is directly converted into work. In contrast, an adiabatic process involves no heat exchange, typically due to rapid execution or thermal insulation.

This leads to temperature changes as work is done, directly affecting the internal energy. The PVP-V curves for adiabatic processes are notably steeper than those for isothermal processes, reflecting a more significant pressure drop for a given volume expansion.

Why it is tested: NEET relevance: This comparison is highly relevant for NEET as it frequently forms the basis of conceptual questions and numerical problems. Students must clearly differentiate between these processes, especially regarding their implications for temperature, heat exchange, internal energy, and work done. Understanding the graphical representation on $P-V$ diagrams and the specific formulas for each process is critical for solving MCQs accurately. Errors often arise from confusing the conditions or formulas of these two processes.