Physics·Revision Notes

Specific Heat Capacity — Revision Notes

NEET UG
Version 1Updated 22 Mar 2026

⚡ 30-Second Revision

  • Specific Heat Capacity (c)Q=mcDeltaTQ = mcDelta T, Unit: J/kg·K
  • Heat Capacity (C)C=mcC = mc, Unit: J/K
  • Molar Specific Heat at Constant Volume ($C_v$)Cv=f2RC_v = \frac{f}{2}R
  • Molar Specific Heat at Constant Pressure ($C_p$)C_p = left(\frac{f+2}{2}\right)R
  • Mayer's FormulaCpCv=RC_p - C_v = R
  • Ratio of Specific Heats ($gamma$)gamma=CpCv=1+2fgamma = \frac{C_p}{C_v} = 1 + \frac{2}{f}
  • Degrees of Freedom (f)

- Monoatomic: f=3f=3 (3 translational) - Diatomic (moderate T): f=5f=5 (3 translational + 2 rotational) - Polyatomic (non-linear, moderate T): f=6f=6 (3 translational + 3 rotational)

  • Values of $gamma$Monoatomic: 5/3approx1.675/3 approx 1.67; Diatomic: 7/5=1.407/5 = 1.40; Polyatomic: 4/3approx1.334/3 approx 1.33

2-Minute Revision

Specific heat capacity (cc) measures how much heat energy is needed to change the temperature of a unit mass of a substance by one degree. Its formula is Q=mcDeltaTQ = mcDelta T. For gases, we distinguish between molar specific heat at constant volume (CvC_v) and constant pressure (CpC_p).

CpC_p is always greater than CvC_v because at constant pressure, the gas expands and does work, requiring additional energy. Mayer's formula, CpCv=RC_p - C_v = R, quantifies this difference for ideal gases.

The equipartition theorem is key to determining CvC_v and CpC_p based on the molecule's degrees of freedom (ff). Each degree of freedom contributes rac12RTrac{1}{2}RT to the internal energy per mole. Monoatomic gases have f=3f=3, diatomic f=5f=5 (at moderate T), and polyatomic f=6f=6 (at moderate T).

From these, Cv=f2RC_v = \frac{f}{2}R, Cp=f+22RC_p = \frac{f+2}{2}R, and the ratio gamma=Cp/Cv=1+2fgamma = C_p/C_v = 1 + \frac{2}{f} can be calculated. These values are crucial for understanding gas behavior in various thermodynamic processes, especially adiabatic ones.

5-Minute Revision

Specific heat capacity is a critical concept in thermal physics, quantifying a material's resistance to temperature change upon heat transfer. It's defined as the heat required per unit mass per unit temperature change (c=Q/(mDeltaT)c = Q/(mDelta T)). For an entire object, we use heat capacity (C=mcC = mc).

For ideal gases, the scenario is more complex due to the possibility of work done during heating. This leads to two distinct molar specific heats:

    1
  1. $C_v$ (Constant Volume)All heat supplied goes into increasing the internal energy (DeltaUDelta U). Qv=nCvDeltaT=DeltaUQ_v = nC_vDelta T = Delta U.
  2. 2
  3. $C_p$ (Constant Pressure)Heat supplied increases internal energy AND does work of expansion (W=PDeltaVW = PDelta V). Qp=nCpDeltaT=DeltaU+WQ_p = nC_pDelta T = Delta U + W.

Mayer's Formula: For one mole of an ideal gas, CpCv=RC_p - C_v = R, where RR is the universal gas constant (8.314,J/molcdotK8.314,\text{J/mol}cdot\text{K}). This formula highlights that CpC_p is always greater than CvC_v.

**Equipartition Theorem and Degrees of Freedom (ff)**: This theorem states that each degree of freedom contributes rac12RTrac{1}{2}RT to the internal energy per mole. The total internal energy for nn moles is U=nf2RTU = n \frac{f}{2}RT. Since DeltaU=nCvDeltaTDelta U = nC_vDelta T, we get Cv=f2RC_v = \frac{f}{2}R. Using Mayer's formula, C_p = left(\frac{f}{2}+1\right)R = left(\frac{f+2}{2}\right)R.

Types of Gases and their Specific Heats (at moderate temperatures):

  • Monoatomic (e.g., He)f=3f=3 (3 translational)

* Cv=32RC_v = \frac{3}{2}R * Cp=52RC_p = \frac{5}{2}R * gamma=CpCv=53approx1.67gamma = \frac{C_p}{C_v} = \frac{5}{3} approx 1.67

  • Diatomic (e.g., O$_2$)f=5f=5 (3 translational + 2 rotational)

* Cv=52RC_v = \frac{5}{2}R * Cp=72RC_p = \frac{7}{2}R * gamma=CpCv=75=1.40gamma = \frac{C_p}{C_v} = \frac{7}{5} = 1.40 * (At high temperatures, vibrational modes activate, f=7f=7, leading to Cv=72RC_v = \frac{7}{2}R, Cp=92RC_p = \frac{9}{2}R, gamma=97approx1.29gamma = \frac{9}{7} approx 1.29)

  • Polyatomic (non-linear, e.g., H$_2$O)f=6f=6 (3 translational + 3 rotational)

* Cv=62R=3RC_v = \frac{6}{2}R = 3R * Cp=82R=4RC_p = \frac{8}{2}R = 4R * gamma=CpCv=43approx1.33gamma = \frac{C_p}{C_v} = \frac{4}{3} approx 1.33

Key Takeaways: Remember Mayer's formula, the equipartition theorem, and the specific values of ff, CvC_v, CpC_p, and gammagamma for different gas types. These are frequently tested in NEET.

Prelims Revision Notes

Specific Heat Capacity (c)

  • DefinitionHeat required to raise temperature of unit mass by 1,K1,\text{K}.
  • FormulaQ=mcDeltaTimpliesc=Q/(mDeltaT)Q = mcDelta T implies c = Q/(mDelta T).
  • UnitsJ/kg·K (SI), cal/g·°C.
  • PropertyIntensive (material-specific).

Heat Capacity (C)

  • DefinitionHeat required to raise temperature of entire body by 1,K1,\text{K}.
  • FormulaC=Q/DeltaT=mcC = Q/Delta T = mc.
  • UnitsJ/K.
  • PropertyExtensive (depends on mass).

Molar Specific Heat Capacities for Ideal Gases

  • $C_v$ (Constant Volume)

* Heat supplied only increases internal energy (DeltaUDelta U). * Qv=nCvDeltaT=DeltaUQ_v = nC_vDelta T = Delta U. * From equipartition theorem: Cv=f2RC_v = \frac{f}{2}R.

  • $C_p$ (Constant Pressure)

* Heat supplied increases internal energy AND does work (W=PDeltaVW = PDelta V). * Qp=nCpDeltaT=DeltaU+WQ_p = nC_pDelta T = Delta U + W. * From equipartition theorem: C_p = left(\frac{f+2}{2}\right)R.

Mayer's Formula

  • RelationCpCv=RC_p - C_v = R (for 1 mole of ideal gas).
  • SignificanceCp>CvC_p > C_v because of work done at constant pressure.

Degrees of Freedom ($f$) and Gas Types

  • Equipartition TheoremEach degree of freedom contributes rac12RTrac{1}{2}RT to molar internal energy.
  • Monoatomic Gas (e.g., He, Ar)

* f=3f=3 (3 translational) * Cv=32RC_v = \frac{3}{2}R, Cp=52RC_p = \frac{5}{2}R, gamma=53approx1.67gamma = \frac{5}{3} approx 1.67

  • Diatomic Gas (e.g., O$_2$, N$_2$)

* Moderate T: f=5f=5 (3 translational + 2 rotational) * Cv=52RC_v = \frac{5}{2}R, Cp=72RC_p = \frac{7}{2}R, gamma=75=1.40gamma = \frac{7}{5} = 1.40 * High T: f=7f=7 (3 translational + 2 rotational + 2 vibrational) * Cv=72RC_v = \frac{7}{2}R, Cp=92RC_p = \frac{9}{2}R, gamma=97approx1.29gamma = \frac{9}{7} approx 1.29

  • Polyatomic Gas (non-linear, e.g., H$_2$O, CH$_4$)

* Moderate T: f=6f=6 (3 translational + 3 rotational) * Cv=3RC_v = 3R, Cp=4RC_p = 4R, gamma=43approx1.33gamma = \frac{4}{3} approx 1.33

Ratio of Specific Heats ($gamma$)

  • Formulagamma=CpCv=1+2fgamma = \frac{C_p}{C_v} = 1 + \frac{2}{f}.
  • ImportanceUsed in adiabatic processes (PVgamma=constantPV^gamma = \text{constant}).

Vyyuha Quick Recall

To remember degrees of freedom for common gases: My Dog Plays:

  • Monoatomic: 3 (just translational)
  • Diatomic: 5 (3 translational + 2 rotational)
  • Polyatomic: 6 (3 translational + 3 rotational)

And for Mayer's formula: Cool People Minus Cool Vegans Rejoice! (CpCv=RC_p - C_v = R)

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