Physics

Periodic Motion

Physics·Revision Notes

Simple Harmonic Motion — Revision Notes

NEET UG
Version 1Updated 22 Mar 2026

⚡ 30-Second Revision

  • Defining Condition:F=kxF = -kx or a=omega2xa = -omega^2 x
  • Angular Frequency:omega=sqrtk/momega = sqrt{k/m} (spring-mass), omega=sqrtg/Lomega = sqrt{g/L} (simple pendulum)
  • Time Period:T=2pi/omega=2pisqrtm/kT = 2pi/omega = 2pisqrt{m/k} (spring-mass), T=2pisqrtL/gT = 2pisqrt{L/g} (simple pendulum)
  • Frequency:f=1/T=omega/(2pi)f = 1/T = omega/(2pi)
  • Displacement:x(t)=Asin(omegat+phi)x(t) = A sin(omega t + phi) or Acos(omegat+phi)A cos(omega t + phi)
  • Velocity:v(t)=Aomegacos(omegat+phi)v(t) = Aomega cos(omega t + phi) (max vmax=Aomegav_{max} = Aomega at x=0x=0)
  • Acceleration:a(t)=Aomega2sin(omegat+phi)=omega2x(t)a(t) = -Aomega^2 sin(omega t + phi) = -omega^2 x(t) (max amax=Aomega2a_{max} = Aomega^2 at x=pmAx=pm A)
  • Kinetic Energy:EK=12mv2=12momega2(A2x2)=12k(A2x2)E_K = \frac{1}{2}mv^2 = \frac{1}{2}momega^2(A^2 - x^2) = \frac{1}{2}k(A^2 - x^2)
  • Potential Energy:EP=12kx2E_P = \frac{1}{2}kx^2
  • Total Energy:E=EK+EP=12kA2=12momega2A2E = E_K + E_P = \frac{1}{2}kA^2 = \frac{1}{2}momega^2 A^2 (constant)

2-Minute Revision

Simple Harmonic Motion (SHM) is a special type of oscillatory motion where the restoring force is directly proportional to displacement and opposite in direction (F=kxF=-kx). This leads to acceleration a=omega2xa=-omega^2 x, where omegaomega is the angular frequency. Key parameters are amplitude (AA), time period (T=2pi/omegaT=2pi/omega), and frequency (f=1/Tf=1/T).

Displacement, velocity, and acceleration vary sinusoidally with time. Velocity leads displacement by pi/2pi/2, and acceleration leads velocity by pi/2pi/2 (or is pipi out of phase with displacement). Maximum velocity is AomegaAomega (at equilibrium), and maximum acceleration is Aomega2Aomega^2 (at extreme positions).

Energy is conserved in ideal SHM. Total energy E=12kA2E = \frac{1}{2}kA^2 is constant, continuously converting between kinetic energy (EK=12k(A2x2)E_K = \frac{1}{2}k(A^2-x^2)) and potential energy (EP=12kx2E_P = \frac{1}{2}kx^2). At equilibrium, EKE_K is max, EPE_P is zero. At extreme positions, EKE_K is zero, EPE_P is max.

Common examples include spring-mass systems (T=2pisqrtm/kT=2pisqrt{m/k}) and simple pendulums (for small angles, T=2pisqrtL/gT=2pisqrt{L/g}). Remember the square root dependence of TT on mm or LL, and inverse square root dependence on kk or gg. Be careful with units and phase relationships.

5-Minute Revision

Simple Harmonic Motion (SHM) is a fundamental concept describing oscillations where the restoring force is linear (F=kxF=-kx). This implies acceleration is proportional to displacement and oppositely directed (a=omega2xa=-omega^2 x). The angular frequency omega=sqrtk/momega = sqrt{k/m} for a spring-mass system and omega=sqrtg/Lomega = sqrt{g/L} for a simple pendulum (small angles). The time period T=2pi/omegaT = 2pi/omega and frequency f=1/Tf = 1/T.

The position of a particle in SHM is given by x(t)=Asin(omegat+phi)x(t) = A sin(omega t + phi), where AA is amplitude and phiphi is initial phase. Differentiating this gives velocity v(t)=Aomegacos(omegat+phi)v(t) = Aomega cos(omega t + phi) and acceleration a(t)=Aomega2sin(omegat+phi)a(t) = -Aomega^2 sin(omega t + phi). Notice that vv leads xx by pi/2pi/2, and aa leads vv by pi/2pi/2 (or aa is pipi out of phase with xx).

Key Points for Maxima/Minima:

  • Equilibrium ($x=0$):Velocity is maximum (vmax=Aomegav_{max}=Aomega), acceleration is zero, restoring force is zero, potential energy is zero, kinetic energy is maximum (EK=12mA2omega2E_K = \frac{1}{2}mA^2omega^2).
  • Extreme Positions ($x=pm A$):Velocity is zero, acceleration is maximum (amax=Aomega2a_{max}=Aomega^2), restoring force is maximum (Fmax=kAF_{max}=kA), potential energy is maximum (EP=12kA2E_P = \frac{1}{2}kA^2), kinetic energy is zero.

Energy Conservation: Total mechanical energy E=EK+EP=12kA2=12momega2A2E = E_K + E_P = \frac{1}{2}kA^2 = \frac{1}{2}momega^2 A^2 is constant. This allows you to find velocity at any position: v=omegasqrtA2x2v = omegasqrt{A^2-x^2}.

Example: A mass of 0.1,kg0.1,\text{kg} oscillates with A=0.02,mA=0.02,\text{m} and T=0.5,sT=0.5,\text{s}.

    1
  1. omega=2pi/T=2pi/0.5=4pi,rad/somega = 2pi/T = 2pi/0.5 = 4pi,\text{rad/s}.
  2. 2
  3. vmax=Aomega=0.02×4pi=0.08pi,m/sv_{max} = Aomega = 0.02 \times 4pi = 0.08pi,\text{m/s}.
  4. 3
  5. amax=Aomega2=0.02×(4pi)2=0.02×16pi2=0.32pi2,m/s2a_{max} = Aomega^2 = 0.02 \times (4pi)^2 = 0.02 \times 16pi^2 = 0.32pi^2,\text{m/s}^2.
  6. 4
  7. Spring constant k=momega2=0.1×(4pi)2=0.1×16pi2=1.6pi2,N/mk = momega^2 = 0.1 \times (4pi)^2 = 0.1 \times 16pi^2 = 1.6pi^2,\text{N/m}.
  8. 5
  9. Total Energy E=12kA2=12(1.6pi2)(0.02)2=0.8pi2×0.0004=0.00032pi2,JE = \frac{1}{2}kA^2 = \frac{1}{2}(1.6pi^2)(0.02)^2 = 0.8pi^2 \times 0.0004 = 0.00032pi^2,\text{J}.

Remember to handle units carefully and understand the physical implications of each parameter.

Prelims Revision Notes

Simple Harmonic Motion (SHM) - NEET Revision Notes

1. Defining Condition:

  • Restoring Force: F=kxF = -kx (Hooke's Law)
  • Acceleration: a=omega2xa = -omega^2 x, where omega=sqrtk/momega = sqrt{k/m} (angular frequency)
  • The negative sign indicates force/acceleration is opposite to displacement, directed towards equilibrium.

2. Key Parameters:

  • Amplitude ($A$):Maximum displacement from equilibrium.
  • Time Period ($T$):Time for one complete oscillation. T=2pi/omegaT = 2pi/omega.
  • Frequency ($f$):Number of oscillations per second. f=1/T=omega/(2pi)f = 1/T = omega/(2pi).
  • Angular Frequency ($omega$):omega=2pif=2pi/Tomega = 2pi f = 2pi/T.
  • Phase ($phi$):Initial phase constant, determined by initial conditions.

3. Equations of Motion:

  • Displacement:x(t)=Asin(omegat+phi)x(t) = A sin(omega t + phi) or x(t)=Acos(omegat+phi)x(t) = A cos(omega t + phi').
  • Velocity:v(t)=dxdt=Aomegacos(omegat+phi)v(t) = \frac{dx}{dt} = Aomega cos(omega t + phi).

* Maximum velocity: vmax=Aomegav_{max} = Aomega (at x=0x=0). * Velocity at any xx: v=pmomegasqrtA2x2v = pm omegasqrt{A^2 - x^2}.

  • Acceleration:a(t)=dvdt=Aomega2sin(omegat+phi)=omega2x(t)a(t) = \frac{dv}{dt} = -Aomega^2 sin(omega t + phi) = -omega^2 x(t).

* Maximum acceleration: amax=Aomega2a_{max} = Aomega^2 (at x=pmAx=pm A).

4. Phase Relationships:

  • Velocity leads displacement by pi/2pi/2 (or 90circ90^circ).
  • Acceleration leads velocity by pi/2pi/2 (or 90circ90^circ).
  • Acceleration is pipi (or 180circ180^circ) out of phase with displacement.

5. Energy in SHM (Ideal/Undamped):

  • Kinetic Energy ($E_K$):EK=12mv2=12momega2(A2x2)=12k(A2x2)E_K = \frac{1}{2}mv^2 = \frac{1}{2}momega^2(A^2 - x^2) = \frac{1}{2}k(A^2 - x^2).

* Maximum at x=0x=0, zero at x=pmAx=pm A.

  • Potential Energy ($E_P$):EP=12kx2E_P = \frac{1}{2}kx^2.

* Maximum at x=pmAx=pm A, zero at x=0x=0.

  • Total Mechanical Energy ($E$):E=EK+EP=12kA2=12momega2A2=constantE = E_K + E_P = \frac{1}{2}kA^2 = \frac{1}{2}momega^2 A^2 = \text{constant}.

6. Examples of SHM:

  • Spring-Mass System:T=2pisqrtm/kT = 2pisqrt{m/k}. (For springs in series: 1/keq=1/k1+1/k21/k_{eq} = 1/k_1 + 1/k_2; for parallel: keq=k1+k2k_{eq} = k_1 + k_2).
  • Simple Pendulum (small angles):T=2pisqrtL/gT = 2pisqrt{L/g}. (Independent of mass and amplitude for small angles).

7. Important Points:

  • At equilibrium (x=0x=0): vmaxv_{max}, a=0a=0, F=0F=0, EKE_K max, EP=0E_P=0.
  • At extreme positions (x=pmAx=pm A): v=0v=0, amaxa_{max}, FmaxF_{max}, EK=0E_K=0, EPE_P max.
  • All SHM is oscillatory, but not all oscillatory motion is SHM (e.g., large angle pendulum).
  • Average velocity over one complete cycle is zero. Average speed is 4A/T4A/T.

Vyyuha Quick Recall

To remember the phase relationships in SHM (Displacement, Velocity, Acceleration):

Displacement Lags Velocity Lags Acceleration by pi/2pi/2.

Think: Don't Lag, Velocity Leads Always!

This means if displacement is a sine function, velocity is a cosine (leading by pi/2pi/2), and acceleration is a negative sine (leading velocity by pi/2pi/2, thus lagging displacement by pipi). Alternatively, acceleration is always opposite to displacement.

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