Physics·Revision Notes

Gauss's Law — Revision Notes

NEET UG
Updated 22 Mar 2026

⚡ 30-Second Revision

  • Gauss's Law:EdvecA=qencϵ0\oint \vec{E} \cdot dvec{A} = \frac{q_{enc}}{\epsilon_0}
  • Electric Flux:ΦE=EdvecA\Phi_E = \int \vec{E} \cdot dvec{A} (units: Nm2/CN \cdot m^2/C or VmV \cdot m)
  • $\epsilon_0$ (Permittivity of free space):8.854×1012C2/(Nm2)8.854 \times 10^{-12} C^2/(N \cdot m^2)
  • Point Charge:E=14piepsilon0qr2E = \frac{1}{4piepsilon_0} \frac{q}{r^2}
  • Infinite Line Charge:E=lambda2piepsilon0rE = \frac{lambda}{2piepsilon_0 r}
  • Infinite Plane Sheet (non-conducting):E=sigma2ϵ0E = \frac{sigma}{2\epsilon_0}
  • Spherical Shell (charged $Q$):E=0E=0 for r<Rr<R; E=14piepsilon0Qr2E = \frac{1}{4piepsilon_0} \frac{Q}{r^2} for rRr \ge R
  • Solid Non-conducting Sphere (charged $Q$):E=14piepsilon0QrR3E = \frac{1}{4piepsilon_0} \frac{Qr}{R^3} for r<Rr<R; E=14piepsilon0Qr2E = \frac{1}{4piepsilon_0} \frac{Q}{r^2} for rRr \ge R
  • Conductor in Electrostatic Equilibrium:E=0E=0 inside, charge resides on surface.

2-Minute Revision

Gauss's Law is a fundamental principle in electrostatics, stating that the total electric flux through any closed surface is proportional to the net electric charge enclosed within that surface. The mathematical form is EdvecA=qencϵ0\oint \vec{E} \cdot dvec{A} = \frac{q_{enc}}{\epsilon_0}.

Electric flux is the measure of electric field lines passing through a surface. The law is universally true but most practical for calculating electric fields of highly symmetric charge distributions (point, line, plane, spherical).

For a point charge, E1/r2E \propto 1/r^2. For an infinite line charge, E1/rE \propto 1/r. For an infinite plane sheet, EE is constant. Inside a uniformly charged spherical shell or any conductor, the electric field is zero.

Inside a uniformly charged solid non-conducting sphere, ErE \propto r. Remember to choose a Gaussian surface that exploits symmetry and correctly identify the enclosed charge. Charges outside the Gaussian surface contribute to the electric field but not to the net flux.

5-Minute Revision

Gauss's Law is a cornerstone of electrostatics, providing an elegant way to relate electric flux to enclosed charge. Electric flux (ΦE\Phi_E) quantifies the 'flow' of electric field through a surface, given by ΦE=EdvecA\Phi_E = \int \vec{E} \cdot dvec{A}.

Gauss's Law states EdvecA=qencϵ0\oint \vec{E} \cdot dvec{A} = \frac{q_{enc}}{\epsilon_0}. The 'Gaussian surface' is an imaginary closed surface chosen to simplify calculations, usually matching the symmetry of the charge distribution.

qencq_{enc} is the net charge inside this surface; charges outside contribute to E\vec{E} but not to the net flux.

Key Applications & Formulas:

    1
  1. Point Charge $q$:E=14piepsilon0qr2E = \frac{1}{4piepsilon_0} \frac{q}{r^2} (Spherical Gaussian surface).
  2. 2
  3. Infinite Line Charge $\lambda$:E=lambda2piepsilon0rE = \frac{lambda}{2piepsilon_0 r} (Cylindrical Gaussian surface). Example: If λ=2nC/m\lambda = 2\,\text{nC/m}, at r=1cmr=1\,\text{cm}, E=2×1092π×8.85×1012×0.013600N/CE = \frac{2 \times 10^{-9}}{2\pi \times 8.85 \times 10^{-12} \times 0.01} \approx 3600\,\text{N/C}.
  4. 3
  5. Infinite Plane Sheet $\sigma$ (non-conducting):E=sigma2ϵ0E = \frac{sigma}{2\epsilon_0} (Pillbox Gaussian surface). Example: If σ=10nC/m2\sigma = 10\,\text{nC/m}^2, E=10×1092×8.85×1012565N/CE = \frac{10 \times 10^{-9}}{2 \times 8.85 \times 10^{-12}} \approx 565\,\text{N/C}.
  6. 4
  7. **Uniformly Charged Spherical Shell (Radius RR, Charge QQ):**

* Inside (r<Rr<R): E=0E=0 (since qenc=0q_{enc}=0). * Outside (rRr \ge R): E=14piepsilon0Qr2E = \frac{1}{4piepsilon_0} \frac{Q}{r^2}.

    1
  1. **Uniformly Charged Solid Non-conducting Sphere (Radius RR, Charge QQ):**

* Inside (r<Rr<R): E=14piepsilon0QrR3E = \frac{1}{4piepsilon_0} \frac{Qr}{R^3} (here qenc=Q(r3/R3)q_{enc} = Q(r^3/R^3)). * Outside (rRr \ge R): E=14piepsilon0Qr2E = \frac{1}{4piepsilon_0} \frac{Q}{r^2}.

Important Points:

  • Electric field inside a conductor is always zero in electrostatic equilibrium.
  • All excess charge on a conductor resides on its outer surface.
  • Gauss's Law is a powerful shortcut for symmetric problems; for asymmetric ones, direct integration using Coulomb's Law is needed.

Prelims Revision Notes

Gauss's Law is a fundamental principle for NEET, simplifying electric field calculations for symmetric charge distributions.

1. Electric Flux ($\Phi_E$):

  • Definition: Number of electric field lines passing through a surface.
  • Formula: ΦE=EA\Phi_E = \vec{E} \cdot \vec{A} for uniform field and planar area. ΦE=EdvecA\Phi_E = \int \vec{E} \cdot dvec{A} for general cases.
  • Units: Nm2/CN \cdot m^2/C or VmV \cdot m.
  • Direction: Outward flux is positive, inward is negative.

2. Gauss's Law:

  • Statement: Total electric flux through any closed surface (Gaussian,surfaceGaussian,surface) is qencϵ0\frac{q_{enc}}{\epsilon_0}.
  • Formula: EdvecA=qencϵ0\oint \vec{E} \cdot dvec{A} = \frac{q_{enc}}{\epsilon_0}.
  • qencq_{enc}: Net charge enclosed by the Gaussian surface. Charges outside contribute to E\vec{E} but not to qencq_{enc}.
  • ϵ0\epsilon_0: Permittivity of free space (8.854×1012C2/(Nm2)8.854 \times 10^{-12} C^2/(N \cdot m^2)).

3. Key Applications (Electric Field $E$):

  • Point Charge $q$:E=14piepsilon0qr2E = \frac{1}{4piepsilon_0} \frac{q}{r^2} (radial).
  • Infinite Line Charge $\lambda$:E=lambda2piepsilon0rE = \frac{lambda}{2piepsilon_0 r} (radial, perpendicular to wire).
  • Infinite Plane Sheet $\sigma$ (non-conducting):E=sigma2ϵ0E = \frac{sigma}{2\epsilon_0} (uniform, perpendicular to plane).
  • **Uniformly Charged Spherical Shell (Radius RR, Charge QQ):**

* r<Rr < R: E=0E=0. * rRr \ge R: E=14piepsilon0Qr2E = \frac{1}{4piepsilon_0} \frac{Q}{r^2}.

  • **Uniformly Charged Solid Non-conducting Sphere (Radius RR, Charge QQ):**

* r<Rr < R: E=14piepsilon0QrR3E = \frac{1}{4piepsilon_0} \frac{Qr}{R^3}. * rRr \ge R: E=14piepsilon0Qr2E = \frac{1}{4piepsilon_0} \frac{Q}{r^2}.

4. Conductors in Electrostatic Equilibrium:

  • Electric field inside a conductor is always zero (Ein=0E_{in}=0).
  • Any net charge resides entirely on the outer surface of the conductor.
  • Electric field just outside the surface of a conductor is perpendicular to the surface and has magnitude E=sigmaϵ0E = \frac{sigma}{\epsilon_0}.

5. Strategy for Problems:

  • Identify symmetry: Spherical, cylindrical, or planar.
  • Choose appropriate Gaussian surface: Sphere, cylinder, or pillbox.
  • Determine qencq_{enc}: Sum of charges inside the Gaussian surface.
  • Apply Gauss's Law and solve for EE. Remember to convert units (e.g., cm to m, nC to C).

Vyyuha Quick Recall

Gauss's Law: Get All Underlying Symmetry Solved. Look At What's Enclosed. (G.A.U.S.S. L.A.W. E.N.C.)

Gaussian surface Area vector Uniform field (for simplification) Symmetry (crucial for easy application) Surface integral

Lambda (line charge) Alpha (area, for plane charge) Within (enclosed charge)

Epsilon naught (permittivity) Net charge (only enclosed) Conductors (E=0 inside)