Physics·Revision Notes

Gauss's Law — Revision Notes

NEET UG
Version 1Updated 22 Mar 2026

⚡ 30-Second Revision

  • Gauss's Law:ointvecEcdotdvecA=qencepsilon0oint vec{E} cdot dvec{A} = \frac{q_{enc}}{epsilon_0}
  • Electric Flux:PhiE=intvecEcdotdvecAPhi_E = int vec{E} cdot dvec{A} (units: Ncdotm2/CN cdot m^2/C or VcdotmV cdot m)
  • $epsilon_0$ (Permittivity of free space):8.854×1012C2/(Ncdotm2)8.854 \times 10^{-12} C^2/(N cdot m^2)
  • Point Charge:E=14piepsilon0qr2E = \frac{1}{4piepsilon_0} \frac{q}{r^2}
  • Infinite Line Charge:E=lambda2piepsilon0rE = \frac{lambda}{2piepsilon_0 r}
  • Infinite Plane Sheet (non-conducting):E=sigma2epsilon0E = \frac{sigma}{2epsilon_0}
  • Spherical Shell (charged $Q$):E=0E=0 for r<Rr<R; E=14piepsilon0Qr2E = \frac{1}{4piepsilon_0} \frac{Q}{r^2} for rgeRr ge R
  • Solid Non-conducting Sphere (charged $Q$):E=14piepsilon0QrR3E = \frac{1}{4piepsilon_0} \frac{Qr}{R^3} for r<Rr<R; E=14piepsilon0Qr2E = \frac{1}{4piepsilon_0} \frac{Q}{r^2} for rgeRr ge R
  • Conductor in Electrostatic Equilibrium:E=0E=0 inside, charge resides on surface.

2-Minute Revision

Gauss's Law is a fundamental principle in electrostatics, stating that the total electric flux through any closed surface is proportional to the net electric charge enclosed within that surface. The mathematical form is ointvecEcdotdvecA=qencepsilon0oint vec{E} cdot dvec{A} = \frac{q_{enc}}{epsilon_0}.

Electric flux is the measure of electric field lines passing through a surface. The law is universally true but most practical for calculating electric fields of highly symmetric charge distributions (point, line, plane, spherical).

For a point charge, Epropto1/r2E propto 1/r^2. For an infinite line charge, Epropto1/rE propto 1/r. For an infinite plane sheet, EE is constant. Inside a uniformly charged spherical shell or any conductor, the electric field is zero.

Inside a uniformly charged solid non-conducting sphere, EproptorE propto r. Remember to choose a Gaussian surface that exploits symmetry and correctly identify the enclosed charge. Charges outside the Gaussian surface contribute to the electric field but not to the net flux.

5-Minute Revision

Gauss's Law is a cornerstone of electrostatics, providing an elegant way to relate electric flux to enclosed charge. Electric flux (PhiEPhi_E) quantifies the 'flow' of electric field through a surface, given by PhiE=intvecEcdotdvecAPhi_E = int vec{E} cdot dvec{A}.

Gauss's Law states ointvecEcdotdvecA=qencepsilon0oint vec{E} cdot dvec{A} = \frac{q_{enc}}{epsilon_0}. The 'Gaussian surface' is an imaginary closed surface chosen to simplify calculations, usually matching the symmetry of the charge distribution.

qencq_{enc} is the net charge *inside* this surface; charges outside contribute to vecEvec{E} but not to the net flux.

Key Applications & Formulas:

    1
  1. Point Charge $q$:E=14piepsilon0qr2E = \frac{1}{4piepsilon_0} \frac{q}{r^2} (Spherical Gaussian surface).
  2. 2
  3. Infinite Line Charge $lambda$:E=lambda2piepsilon0rE = \frac{lambda}{2piepsilon_0 r} (Cylindrical Gaussian surface). Example: If lambda=2,nC/mlambda = 2,\text{nC/m}, at r=1,cmr=1,\text{cm}, E=2×1092pi×8.85×1012×0.01approx3600,N/CE = \frac{2 \times 10^{-9}}{2pi \times 8.85 \times 10^{-12} \times 0.01} approx 3600,\text{N/C}.
  4. 3
  5. Infinite Plane Sheet $sigma$ (non-conducting):E=sigma2epsilon0E = \frac{sigma}{2epsilon_0} (Pillbox Gaussian surface). Example: If sigma=10,nC/m2sigma = 10,\text{nC/m}^2, E=10×1092×8.85×1012approx565,N/CE = \frac{10 \times 10^{-9}}{2 \times 8.85 \times 10^{-12}} approx 565,\text{N/C}.
  6. 4
  7. **Uniformly Charged Spherical Shell (Radius RR, Charge QQ):**

* Inside (r<Rr<R): E=0E=0 (since qenc=0q_{enc}=0). * Outside (rgeRr ge R): E=14piepsilon0Qr2E = \frac{1}{4piepsilon_0} \frac{Q}{r^2}.

    1
  1. **Uniformly Charged Solid Non-conducting Sphere (Radius RR, Charge QQ):**

* Inside (r<Rr<R): E=14piepsilon0QrR3E = \frac{1}{4piepsilon_0} \frac{Qr}{R^3} (here qenc=Q(r3/R3)q_{enc} = Q(r^3/R^3)). * Outside (rgeRr ge R): E=14piepsilon0Qr2E = \frac{1}{4piepsilon_0} \frac{Q}{r^2}.

Important Points:

  • Electric field inside a conductor is always zero in electrostatic equilibrium.
  • All excess charge on a conductor resides on its outer surface.
  • Gauss's Law is a powerful shortcut for symmetric problems; for asymmetric ones, direct integration using Coulomb's Law is needed.

Prelims Revision Notes

Gauss's Law is a fundamental principle for NEET, simplifying electric field calculations for symmetric charge distributions.

1. Electric Flux ($Phi_E$):

  • Definition: Number of electric field lines passing through a surface.
  • Formula: PhiE=vecEcdotvecAPhi_E = vec{E} cdot vec{A} for uniform field and planar area. PhiE=intvecEcdotdvecAPhi_E = int vec{E} cdot dvec{A} for general cases.
  • Units: Ncdotm2/CN cdot m^2/C or VcdotmV cdot m.
  • Direction: Outward flux is positive, inward is negative.

2. Gauss's Law:

  • Statement: Total electric flux through any closed surface (Gaussian,surfaceGaussian,surface) is racqencepsilon0rac{q_{enc}}{epsilon_0}.
  • Formula: ointvecEcdotdvecA=qencepsilon0oint vec{E} cdot dvec{A} = \frac{q_{enc}}{epsilon_0}.
  • qencq_{enc}: Net charge *enclosed* by the Gaussian surface. Charges outside contribute to vecEvec{E} but not to qencq_{enc}.
  • epsilon0epsilon_0: Permittivity of free space (8.854×1012C2/(Ncdotm2)8.854 \times 10^{-12} C^2/(N cdot m^2)).

3. Key Applications (Electric Field $E$):

  • Point Charge $q$:E=14piepsilon0qr2E = \frac{1}{4piepsilon_0} \frac{q}{r^2} (radial).
  • Infinite Line Charge $lambda$:E=lambda2piepsilon0rE = \frac{lambda}{2piepsilon_0 r} (radial, perpendicular to wire).
  • Infinite Plane Sheet $sigma$ (non-conducting):E=sigma2epsilon0E = \frac{sigma}{2epsilon_0} (uniform, perpendicular to plane).
  • **Uniformly Charged Spherical Shell (Radius RR, Charge QQ):**

* r<Rr < R: E=0E=0. * rgeRr ge R: E=14piepsilon0Qr2E = \frac{1}{4piepsilon_0} \frac{Q}{r^2}.

  • **Uniformly Charged Solid Non-conducting Sphere (Radius RR, Charge QQ):**

* r<Rr < R: E=14piepsilon0QrR3E = \frac{1}{4piepsilon_0} \frac{Qr}{R^3}. * rgeRr ge R: E=14piepsilon0Qr2E = \frac{1}{4piepsilon_0} \frac{Q}{r^2}.

4. Conductors in Electrostatic Equilibrium:

  • Electric field inside a conductor is always zero (Ein=0E_{in}=0).
  • Any net charge resides entirely on the outer surface of the conductor.
  • Electric field just outside the surface of a conductor is perpendicular to the surface and has magnitude E=sigmaepsilon0E = \frac{sigma}{epsilon_0}.

5. Strategy for Problems:

  • Identify symmetry: Spherical, cylindrical, or planar.
  • Choose appropriate Gaussian surface: Sphere, cylinder, or pillbox.
  • Determine qencq_{enc}: Sum of charges *inside* the Gaussian surface.
  • Apply Gauss's Law and solve for EE. Remember to convert units (e.g., cm to m, nC to C).

Vyyuha Quick Recall

Gauss's Law: Get All Underlying Symmetry Solved. Look At What's Enclosed. (G.A.U.S.S. L.A.W. E.N.C.)

Gaussian surface Area vector Uniform field (for simplification) Symmetry (crucial for easy application) Surface integral

Lambda (line charge) Alpha (area, for plane charge) Within (enclosed charge)

Epsilon naught (permittivity) Net charge (only enclosed) Conductors (E=0 inside)

Featured
🎯PREP MANAGER
Your 6-Month Blueprint, Updated Nightly
AI analyses your progress every night. Wake up to a smarter plan. Every. Single. Day.
Ad Space
🎯PREP MANAGER
Your 6-Month Blueprint, Updated Nightly
AI analyses your progress every night. Wake up to a smarter plan. Every. Single. Day.