Self and Mutual Inductance — Explained

On this page

1. Conceptual Foundation
2. Self-Inductance ($L$)
3. Mathematical Formulation:
4. Factors Affecting Self-Inductance:
5. Derivation of Self-Inductance for a Long Solenoid:
6. Energy Stored in an Inductor:
7. Mutual Inductance ($M$)
8. Mathematical Formulation:
9. Factors Affecting Mutual Inductance:
10. Derivation of Mutual Inductance for Two Coaxial Solenoids:
11. Coefficient of Coupling ($k$):
12. Real-World Applications
13. Common Misconceptions
14. NEET-Specific Angle

Detailed Explanation

The concepts of self and mutual inductance are cornerstones of electromagnetic theory, providing insight into how circuits respond to changing currents and how magnetic fields can mediate interactions between separate circuits. They are direct consequences of Faraday's Law of Electromagnetic Induction and Lenz's Law.

Conceptual Foundation

At the heart of inductance lies the relationship between electric current and magnetic fields. An electric current flowing through a conductor generates a magnetic field around it. For a coil or solenoid, this magnetic field is concentrated, creating a significant magnetic flux through its own turns.

If the current changes, the magnetic field strength changes, and consequently, the magnetic flux linked with the coil also changes. According to Faraday's Law, a changing magnetic flux induces an electromotive force (EMF).

Lenz's Law further dictates that the direction of this induced EMF is such that it opposes the very change in magnetic flux (and thus, the change in current) that produced it.

Self-Inductance ($L$)

Definition: Self-inductance is the property of a single coil or circuit element by virtue of which it opposes any change in the current flowing through it by inducing an EMF in itself. This induced EMF is often called a 'back EMF' because it always acts to oppose the change in current.

Mathematical Formulation:

The magnetic flux ($\Phi_B$) linked with a coil is directly proportional to the current ($I$) flowing through it, assuming no ferromagnetic materials are involved that would cause non-linearity. Therefore, we can write:

$$\Phi_B \propto I$$

$$\Phi_B = LI$$

where $L$ is the constant of proportionality, known as the self-inductance of the coil. Its unit is the Henry (H), which is equivalent to Weber per Ampere (Wb/A).

From Faraday's Law of Induction, the induced EMF ($\mathcal{E}$) in the coil is given by:

$$\mathcal{E} = -N \frac{d\Phi_B}{dt}$$

where $N$ is the number of turns in the coil. For a single coil, $\Phi_B$ refers to the total flux linkage, which is $N$ times the flux through a single turn.

Substituting $\Phi_B = LI$ (where $\Phi_B$ here represents the total flux linkage for the entire coil, $Nphi_{turn}$):

$$\mathcal{E} = -\frac{d(LI)}{dt}$$

If $L$ is constant (which it is for most practical inductors in air or non-magnetic cores):

$$\mathcal{E} = -L \frac{dI}{dt}$$

The negative sign is a direct consequence of Lenz's Law, indicating that the induced EMF opposes the change in current.

If $dI/dt$ is positive (current increasing), $\mathcal{E}$ is negative, opposing the increase. If $dI/dt$ is negative (current decreasing), $\mathcal{E}$ is positive, opposing the decrease.

Factors Affecting Self-Inductance:

1
Geometry of the coil: — The number of turns ($N$), cross-sectional area ($A$), and length ($l$) of the coil significantly influence $L$.
2
Permeability of the core material ($\mu$): — If a magnetic material is placed inside the coil, its permeability greatly increases the magnetic flux for a given current, thus increasing $L$. Air-core inductors have lower inductance than iron-core inductors.

Derivation of Self-Inductance for a Long Solenoid:

Consider a long solenoid of length $l$, cross-sectional area $A$, and $N$ turns. Let $n = N/l$ be the number of turns per unit length. When a current $I$ flows through the solenoid, the magnetic field inside it (assuming it's long and uniform) is given by:

$$B = \mu_0 n I = \mu_0 \frac{N}{l} I$$

The magnetic flux through each turn is $\phi_{turn} = B A = \mu_0 \frac{N}{l} I A$.

The total magnetic flux linked with the entire solenoid (flux linkage) is $\Phi_B = N \phi_{turn} = N \left( \mu_0 \frac{N}{l} I A \right)$. So, $\Phi_B = \mu_0 \frac{N^2 A}{l} I$. Comparing this with $\Phi_B = LI$, we get the self-inductance $L$ of the solenoid:

$$L = \mu_0 \frac{N^2 A}{l}$$

If the solenoid has a core of relative permeability $\mu_r$, then $\mu_0$ is replaced by $\mu = \mu_0 \mu_r$, so $L = \mu_0 \mu_r \frac{N^2 A}{l}$.

Energy Stored in an Inductor:

When current flows through an inductor, energy is stored in its magnetic field. The work done by the source to establish a current $I$ against the back EMF is stored as potential energy. The instantaneous power delivered to the inductor is $P = I |\mathcal{E}| = I L \frac{dI}{dt}$.

The total energy stored ($U$) when the current increases from $0$ to $I$ is:

$$U = \int P dt = \int (LI \frac{dI}{dt}) dt = \int_0^I LI dI$$

$$U = \frac{1}{2} LI^2$$

This energy is stored in the magnetic field within the inductor.

The energy density ($u_B$) in a magnetic field $B$ is given by $u_B = \frac{B^2}{2\mu_0}$. For a solenoid, $B = \mu_0 n I$, so $I = B/(\mu_0 n)$. Substituting this into the energy formula and using $L = \mu_0 n^2 A l$ (where $N=nl$):

$$U = \frac{1}{2} (\mu_0 n^2 A l) (\frac{B}{\mu_0 n})^2 = \frac{1}{2} (\mu_0 n^2 A l) \frac{B^2}{\mu_0^2 n^2} = \frac{B^2}{2\mu_0} (Al)$$

Since $Al$ is the volume of the solenoid, the energy density is indeed $u_B = \frac{B^2}{2\mu_0}$.

Mutual Inductance ($M$)

Definition: Mutual inductance is the property of two coils or circuits by virtue of which a changing current in one coil induces an EMF in the other coil. The coil carrying the changing current is often called the primary coil, and the coil in which EMF is induced is called the secondary coil.

Mathematical Formulation:

Consider two coils, coil 1 and coil 2, placed near each other. If a current $I_1$ flows through coil 1, it produces a magnetic field. A portion of this magnetic field passes through coil 2, creating a magnetic flux $\Phi_{B2}$ linked with coil 2. This flux $\Phi_{B2}$ is proportional to $I_1$:

$$\Phi_{B2} \propto I_1$$

$$\Phi_{B2} = M_{21} I_1$$

where $M_{21}$ is the mutual inductance of coil 2 with respect to coil 1. Its unit is also the Henry (H).

If the current $I_1$ in coil 1 changes, an EMF ($\mathcal{E}_2$) is induced in coil 2, given by Faraday's Law:

$$\mathcal{E}_2 = -\frac{d\Phi_{B2}}{dt} = -\frac{d(M_{21} I_1)}{dt}$$

Assuming $M_{21}$ is constant:

$$\mathcal{E}_2 = -M_{21} \frac{dI_1}{dt}$$

Similarly, if a current $I_2$ flows through coil 2, it produces a magnetic flux $\Phi_{B1}$ linked with coil 1:

$$\Phi_{B1} = M_{12} I_2$$

And if $I_2$ changes, an EMF ($\mathcal{E}_1$) is induced in coil 1:

$$\mathcal{E}_1 = -M_{12} \frac{dI_2}{dt}$$

It can be shown that $M_{12} = M_{21}$, so we simply denote it as $M$.

The mutual inductance between two coils is a reciprocal property.

Factors Affecting Mutual Inductance:

1
Geometry of both coils: — Number of turns, cross-sectional area, and length of both coils.
2
Relative orientation and separation: — The closer the coils and the more aligned their axes, the greater the magnetic flux linkage and thus greater $M$.
3
Permeability of the core material: — Introducing a magnetic core significantly increases $M$.

Derivation of Mutual Inductance for Two Coaxial Solenoids:

Consider two long coaxial solenoids. Let solenoid 1 (primary) have $N_1$ turns, length $l_1$, and radius $r_1$. Solenoid 2 (secondary) has $N_2$ turns, length $l_2$, and radius $r_2$. Assume solenoid 2 is placed inside solenoid 1, and $r_2 < r_1$. The magnetic field produced by current $I_1$ in solenoid 1 is $B_1 = \mu_0 n_1 I_1 = \mu_0 \frac{N_1}{l_1} I_1$. This field is approximately uniform inside solenoid 1.

The magnetic flux linked with each turn of solenoid 2 is $\phi_{B2,turn} = B_1 A_2 = (\mu_0 \frac{N_1}{l_1} I_1) (\pi r_2^2)$. The total magnetic flux linked with solenoid 2 is $\Phi_{B2} = N_2 \phi_{B2,turn} = N_2 (\mu_0 \frac{N_1}{l_1} I_1 \pi r_2^2)$.

So, $\Phi_{B2} = (\mu_0 \frac{N_1 N_2 \pi r_2^2}{l_1}) I_1$. Comparing this with $\Phi_{B2} = M I_1$, we get the mutual inductance $M$:

$$M = \mu_0 \frac{N_1 N_2 \pi r_2^2}{l_1}$$

If the core has relative permeability $\mu_r$, then $M = \mu_0 \mu_r \frac{N_1 N_2 \pi r_2^2}{l_1}$.

Coefficient of Coupling ($k$):

The mutual inductance $M$ between two coils is related to their individual self-inductances $L_1$ and $L_2$ by the coefficient of coupling $k$:

$$M = k \sqrt{L_1 L_2}$$

where $0 \le k \le 1$.

If $k=1$, the coils are perfectly coupled, meaning all the magnetic flux from one coil links with the other. This is an ideal scenario, often approximated in well-designed transformers.
If $k=0$, there is no magnetic coupling between the coils.
For practical coils, $0 < k < 1$.

Real-World Applications

1
Inductors (Chokes): — Used in AC circuits to limit current without significant power loss (unlike resistors). They are crucial in filters, oscillators, and tuning circuits.
2
Transformers: — Operate on the principle of mutual inductance. A changing current in the primary coil induces an EMF in the secondary coil, allowing for voltage step-up or step-down.
3
Ignition Coils in Automobiles: — A rapidly collapsing magnetic field in the primary coil (due to switching off current) induces a very high voltage in the secondary coil, creating a spark for combustion.
4
Metal Detectors: — Utilize mutual inductance principles to detect metallic objects by sensing changes in the induced currents.
5
Induction Cooktops: — Generate rapidly changing magnetic fields that induce eddy currents in ferromagnetic cookware, heating it directly.

Common Misconceptions

Inductance vs. Resistance: — Inductance opposes changes in current, while resistance opposes the flow of current. An ideal inductor dissipates no energy, only stores it in its magnetic field, whereas a resistor dissipates energy as heat.
Direction of Induced EMF: — Students often forget Lenz's Law. The induced EMF always opposes the change in current, not necessarily the current itself. If current is increasing, induced EMF opposes the increase. If current is decreasing, induced EMF tries to maintain it.
Mutual Inductance is One-Way: — It's a common mistake to think that only the primary coil affects the secondary. Mutual inductance is reciprocal ($M_{12} = M_{21}$), meaning a change in current in either coil induces an EMF in the other.
Inductance is Always Present: — Any current-carrying loop or wire has some self-inductance, though it may be negligible for straight wires. Coils are designed to maximize this effect.

NEET-Specific Angle

For NEET, a strong grasp of the definitions, formulas, and their applications is essential. Questions often involve:

Calculating self-inductance of a solenoid given its dimensions and number of turns.
Calculating induced EMF given $L$ and $dI/dt$.
Calculating energy stored in an inductor.
Calculating mutual inductance for simple configurations or using the coefficient of coupling.
Conceptual questions on Lenz's Law, factors affecting $L$ and $M$, and the energy transformation in inductors.
Understanding the role of inductors in AC circuits (though detailed AC circuit analysis with inductors is covered in a separate chapter, the basic properties are relevant here).
Comparison between self and mutual induction.

Often confused with

Side-by-side differences the NEET paper likes to test.

Self and Mutual Inductance vs Mutual Inductance

Aspect	Self and Mutual Inductance	Mutual Inductance
Definition	Property of a single coil to oppose changes in its own current.	Property of two coils where a changing current in one induces EMF in the other.
Number of Coils Involved	One coil.	Two or more coils.
Cause of Induced EMF	Change in current in the *same* coil.	Change in current in a *nearby* coil.
Formula for Induced EMF	$\mathcal{E} = -L \frac{dI}{dt}$	$\mathcal{E}_2 = -M \frac{dI_1}{dt}$ (or vice versa)
Factors Affecting	Geometry of the coil (N, A, l), core material.	Geometry of both coils, their relative orientation and separation, core material.
Energy Storage	Stores energy in its own magnetic field ($U = \frac{1}{2}LI^2$).	Facilitates energy transfer between coils, but the energy is stored in the combined magnetic field.

Self-inductance is an intrinsic property of a single coil, quantifying its opposition to changes in its own current. It's about a coil's 'magnetic inertia.' Mutual inductance, conversely, describes the magnetic interaction between two separate coils, where a current change in one induces an EMF in the other.

While self-inductance focuses on a single circuit's response to internal current changes, mutual inductance highlights the magnetic coupling and energy transfer potential between distinct circuits. Both are measured in Henrys and are crucial for understanding electromagnetic devices.

Why it is tested: For NEET, understanding these differences is critical for conceptual questions and for correctly applying the appropriate formulas in problem-solving. Students must distinguish when to use $L$ and when to use $M$, and how their influencing factors differ.

Questions students ask

5 answered on this topic.

What is the fundamental difference between self-inductance and mutual inductance?

The fundamental difference lies in the interaction. Self-inductance describes the property of a single coil to induce an EMF within itself due to a change in its own current. It's an intrinsic property of a coil.

Mutual inductance, conversely, describes the phenomenon where a changing current in one coil induces an EMF in a separate, nearby coil. It quantifies the magnetic coupling between two distinct circuits.

Both are manifestations of electromagnetic induction, but one is internal to a single circuit, and the other is an interaction between two.

Why is the induced EMF in an inductor sometimes called 'back EMF'?

The induced EMF in an inductor is called 'back EMF' because, according to Lenz's Law, its direction is always such that it opposes the change in current that produced it. If the current is increasing, the back EMF acts to reduce it; if the current is decreasing, the back EMF acts to maintain it. This opposition makes it 'back' or counter to the change, much like a back pressure or a resistive force, though it's not a resistive force in the sense of dissipating energy.

What happens to the energy stored in an inductor when the current is switched off?

When the current through an inductor is switched off, the magnetic field collapses. The energy previously stored in this magnetic field ($U = \frac{1}{2}LI^2$) is released. This rapid release of energy can induce a very large EMF (a 'spark') across the switch terminals or in the circuit, as the inductor tries to maintain the current. This energy is typically dissipated as heat in the circuit resistance, radiated as electromagnetic waves, or used to power other components for a brief period.

Can mutual inductance exist between two coils if they are very far apart?

Theoretically, yes, but practically, it would be negligible. Mutual inductance depends on the magnetic flux linkage between the two coils. As the distance between the coils increases, the magnetic field produced by one coil that passes through the other coil diminishes rapidly. Therefore, the flux linkage becomes extremely small, leading to a very low (almost zero) mutual inductance. For significant mutual inductance, the coils need to be in close proximity and appropriately oriented.

How does the core material affect the self-inductance of a coil?

The core material significantly affects the self-inductance by altering the magnetic permeability ($\mu$) inside the coil. If the coil has an air core, its permeability is $\mu_0$. If a ferromagnetic material (like iron) is inserted into the core, its relative permeability ($\mu_r$) can be very high (hundreds or thousands).

Since $L \propto \mu$, a ferromagnetic core dramatically increases the magnetic flux for a given current, and thus greatly increases the self-inductance of the coil. This is why chokes and transformers often use iron cores.