Vapour Pressure of Solutions of Solids in Liquids — Explained

On this page

1. Conceptual Foundation
2. Key Principles and Laws: Raoult's Law
3. Derivations: Relative Lowering of Vapour Pressure
4. Real-World Applications
5. Common Misconceptions
6. NEET-Specific Angle

Detailed Explanation

The concept of vapour pressure is fundamental to understanding the behavior of liquid solutions. When a non-volatile solid is dissolved in a volatile liquid, the resulting solution exhibits a lower vapour pressure than the pure solvent at the same temperature. This phenomenon is not just an observation but is governed by a precise scientific law and has significant implications in chemistry and biology.

Conceptual Foundation

To grasp why the vapour pressure lowers, let's first revisit the concept of vapour pressure for a pure liquid. In a closed container, a pure liquid establishes a dynamic equilibrium with its vapour. Molecules at the liquid surface, possessing sufficient kinetic energy, escape into the gaseous phase (evaporation).

Simultaneously, vapour molecules collide with the liquid surface and return to the liquid phase (condensation). At equilibrium, the rate of evaporation equals the rate of condensation, and the pressure exerted by the vapour is the vapour pressure of the pure liquid ($P_A^0$).

Now, consider dissolving a non-volatile solid solute (e.g., glucose, urea) into this volatile liquid solvent (e.g., water). A non-volatile solute is one that does not readily vaporize at the given temperature.

When the solute dissolves, its particles distribute uniformly throughout the solvent, including at the liquid-vapour interface. The presence of these non-volatile solute particles at the surface effectively reduces the fraction of the surface area available for the solvent molecules to escape into the vapour phase.

With fewer solvent molecules exposed at the surface, the rate at which solvent molecules can evaporate decreases. While the rate of condensation of solvent molecules from the vapour phase remains largely unchanged (or decreases slightly as vapour concentration drops), the net effect is a reduction in the number of solvent molecules in the vapour phase at equilibrium.

Consequently, the pressure exerted by the vapour above the solution ($P_A$) is lower than that above the pure solvent ($P_A^0$).

Key Principles and Laws: Raoult's Law

This qualitative understanding is quantified by Raoult's Law. For a solution containing a non-volatile solute, Raoult's Law states that the partial vapour pressure of the solvent ($P_A$) in the solution is directly proportional to its mole fraction ($x_A$) in the solution. The proportionality constant is the vapour pressure of the pure solvent ($P_A^0$) at the same temperature.

Mathematically, Raoult's Law for a non-volatile solute is expressed as:

$$P_A = x_A P_A^0$$

Where:

$P_A$ = Vapour pressure of the solvent in the solution
$x_A$ = Mole fraction of the solvent in the solution
$P_A^0$ = Vapour pressure of the pure solvent

The mole fraction of the solvent, $x_A$, is defined as:

$$x_A = \frac{n_A}{n_A + n_B}$$

Where $n_A$ is the number of moles of solvent and $n_B$ is the number of moles of solute.

Since $x_A$ is always less than 1 for a solution (as $n_B > 0$), it directly follows that $P_A < P_A^0$, confirming the lowering of vapour pressure.

Derivations: Relative Lowering of Vapour Pressure

The lowering of vapour pressure, denoted as $\Delta P$, is the difference between the vapour pressure of the pure solvent and the vapour pressure of the solvent in the solution:

$$\Delta P = P_A^0 - P_A$$

Substituting Raoult's Law ($P_A = x_A P_A^0$):

$$\Delta P = P_A^0 - x_A P_A^0 = P_A^0 (1 - x_A)$$

We know that for a binary solution, the sum of mole fractions of all components is 1, i.e., $x_A + x_B = 1$. Therefore, $1 - x_A = x_B$, where $x_B$ is the mole fraction of the solute.

So, the lowering of vapour pressure can also be expressed as:

$$\Delta P = x_B P_A^0$$

The relative lowering of vapour pressure is defined as the ratio of the lowering of vapour pressure to the vapour pressure of the pure solvent:

$$\frac{\Delta P}{P_A^0} = \frac{P_A^0 - P_A}{P_A^0}$$

Substituting $\Delta P = x_B P_A^0$:

$$\frac{P_A^0 - P_A}{P_A^0} = \frac{x_B P_A^0}{P_A^0} = x_B$$

This is a very significant result: **the relative lowering of vapour pressure is equal to the mole fraction of the solute ($x_B$)**.

This relationship is particularly useful because it allows us to determine the molar mass of an unknown non-volatile solute. We know that:

$$x_B = \frac{n_B}{n_A + n_B}$$

For dilute solutions, where $n_B \ll n_A$, we can approximate $n_A + n_B \approx n_A$. In such cases:

$$x_B \approx \frac{n_B}{n_A}$$

And since $n = \frac{\text{mass}}{\text{molar mass}}$, we have $n_B = \frac{w_B}{M_B}$ and $n_A = \frac{w_A}{M_A}$.

Substituting these into the approximate expression for $x_B$:

$$\frac{P_A^0 - P_A}{P_A^0} \approx \frac{w_B/M_B}{w_A/M_A} = \frac{w_B M_A}{M_B w_A}$$

This equation can be rearranged to solve for the molar mass of the solute ($M_B$):

$$M_B = \frac{w_B M_A}{w_A} \times \frac{P_A^0}{P_A^0 - P_A}$$

This method is a classic way to determine the molar mass of non-volatile solutes experimentally.

Real-World Applications

1
Desalination — While not directly using vapour pressure lowering, the principle is related to osmotic pressure, which is also a colligative property. Understanding how solute concentration affects solvent properties is key to processes like reverse osmosis.
2
Antifreeze Solutions — Although primarily related to freezing point depression, the underlying principle of colligative properties (dependence on solute concentration) is the same. Adding a non-volatile solute (like ethylene glycol) to water lowers its freezing point and raises its boiling point, making it useful in car radiators.
3
Food Preservation — Concentrated sugar solutions (jams, jellies) or salt solutions (pickles) have lower water activity due to reduced vapour pressure. This inhibits microbial growth, extending shelf life.
4
Pharmaceutical Industry — Vapour pressure measurements can be used to determine the purity and concentration of solutions, and to characterize new compounds.
5
Chemical Analysis — As derived, the relative lowering of vapour pressure provides a method for determining the molar mass of unknown non-volatile substances, which is a crucial step in chemical identification and characterization.

Common Misconceptions

1
Vapour pressure lowering vs. boiling point elevation — While related (both are colligative properties), they are distinct phenomena. Lowering of vapour pressure causes boiling point elevation. Students sometimes confuse the two or use the wrong formula.
2
Applicability of Raoult's Law — Raoult's Law strictly applies only to ideal solutions. Ideal solutions are those where the intermolecular forces between solute-solvent particles are similar to those between solute-solute and solvent-solvent particles. In reality, most solutions are non-ideal and show deviations (positive or negative) from Raoult's Law. However, for dilute solutions, the law provides a good approximation.
3
Nature of solute — Students might forget that Raoult's Law for vapour pressure lowering applies specifically to non-volatile solutes. If the solute is also volatile, the total vapour pressure of the solution would be the sum of the partial vapour pressures of both components, each governed by Raoult's Law for volatile components.
4
Units — Care must be taken with units, especially when calculating mole fractions or molar masses. Ensure consistency.

NEET-Specific Angle

For NEET, this topic is highly important due to its quantitative nature and its role as a foundational colligative property. Questions typically involve:

Direct application of Raoult's Law — Calculating the vapour pressure of a solution given the mole fraction of the solvent and pure solvent vapour pressure.
Calculating relative lowering of vapour pressure — Given concentrations, finding $x_B$ or vice versa.
Molar mass determination — Using the relative lowering of vapour pressure to find the molar mass of an unknown non-volatile solute.
Conceptual questions — Understanding why vapour pressure lowers, identifying factors affecting it (temperature, concentration, nature of solvent), and distinguishing between ideal and non-ideal solutions (though detailed non-ideal behavior is often covered separately).
Relationship with other colligative properties — Sometimes questions might indirectly link vapour pressure lowering to boiling point elevation or freezing point depression, requiring a holistic understanding of colligative properties. Always remember that colligative properties depend only on the number of solute particles, not their identity. For ionic solutes, the van't Hoff factor ($i$) must be considered to account for dissociation.

Often confused with

Side-by-side differences the NEET paper likes to test.

Vapour Pressure of Solutions of Solids in Liquids vs Pure Solvent vs. Solution with Non-volatile Solute

Aspect	Vapour Pressure of Solutions of Solids in Liquids	Pure Solvent vs. Solution with Non-volatile Solute
Surface Area for Evaporation	Entire surface available for solvent molecules to escape.	Portion of surface occupied by non-volatile solute particles, reducing available area for solvent escape.
Rate of Evaporation	Higher rate of solvent molecule escape.	Lower rate of solvent molecule escape due to reduced surface exposure.
Vapour Pressure	Higher vapour pressure ($P_A^0$).	Lower vapour pressure ($P_A < P_A^0$). The extent of lowering depends on solute concentration.
Boiling Point	Lower boiling point (boils when $P_A^0$ equals external pressure).	Higher boiling point (requires higher temperature for $P_A$ to equal external pressure, known as boiling point elevation).
Freezing Point	Higher freezing point.	Lower freezing point (known as freezing point depression).
Raoult's Law	Not applicable in this context (it's a reference point).	Obeys Raoult's Law: $P_A = x_A P_A^0$ (for ideal solutions).

The fundamental difference between a pure solvent and a solution containing a non-volatile solute lies in their vapour pressures and, consequently, other colligative properties. The presence of non-volatile solute particles at the liquid surface in a solution hinders the escape of solvent molecules, leading to a reduced rate of evaporation and thus a lower vapour pressure compared to the pure solvent.

This lowering of vapour pressure is a direct cause for the elevation of the boiling point and depression of the freezing point of the solution, all of which are colligative properties dependent on the number of solute particles.

Why it is tested: NEET relevance: Understanding these differences is crucial for solving conceptual and numerical problems related to colligative properties. Questions often test the qualitative effects of adding a non-volatile solute on vapour pressure, boiling point, and freezing point, as well as quantitative calculations using Raoult's Law.

Questions students ask

5 answered on this topic.

What is vapour pressure and how does it relate to solutions?

Vapour pressure is the pressure exerted by the vapour in thermodynamic equilibrium with its condensed phases (solid or liquid) at a given temperature in a closed system. For solutions, when a non-volatile solute is added to a volatile solvent, the vapour pressure of the solution is observed to be lower than that of the pure solvent.

This is because the solute particles occupy a portion of the surface area, reducing the number of solvent molecules available to escape into the vapour phase, thus decreasing the rate of evaporation and leading to a lower equilibrium vapour pressure.

What is Raoult's Law for solutions containing non-volatile solutes?

Raoult's Law states that for a solution containing a non-volatile solute, the partial vapour pressure of the solvent in the solution is directly proportional to its mole fraction in the solution. Mathematically, it's expressed as $P_A = x_A P_A^0$, where $P_A$ is the vapour pressure of the solvent in the solution, $x_A$ is the mole fraction of the solvent, and $P_A^0$ is the vapour pressure of the pure solvent at the same temperature.

This law forms the basis for understanding the colligative property of vapour pressure lowering.

Why is the lowering of vapour pressure considered a colligative property?

The lowering of vapour pressure is a colligative property because it depends solely on the number of solute particles present in the solution, irrespective of their chemical nature or identity. Whether you add 1 mole of glucose or 1 mole of urea to the same amount of solvent, the extent of vapour pressure lowering will be approximately the same, provided both are non-volatile and do not dissociate.

This characteristic is shared with other colligative properties like boiling point elevation, freezing point depression, and osmotic pressure.

How can the molar mass of a non-volatile solute be determined using vapour pressure lowering?

The relative lowering of vapour pressure is equal to the mole fraction of the solute ($x_B$). This relationship, $\frac{P_A^0 - P_A}{P_A^0} = x_B$, can be expanded. Since $x_B = \frac{n_B}{n_A + n_B}$ and $n = \frac{\text{mass}}{\text{molar mass}}$, we can substitute these to get $\frac{P_A^0 - P_A}{P_A^0} = \frac{w_B/M_B}{w_A/M_A + w_B/M_B}$.

For dilute solutions, this simplifies to $\frac{P_A^0 - P_A}{P_A^0} \approx \frac{w_B M_A}{M_B w_A}$. By measuring the vapour pressures and knowing the masses and molar mass of the solvent, the molar mass of the solute ($M_B$) can be calculated.

What are ideal and non-ideal solutions in the context of Raoult's Law?

An ideal solution is one that obeys Raoult's Law over the entire range of concentrations and temperatures. In an ideal solution, the intermolecular forces between solute-solvent particles (A-B) are similar to those between solute-solute (B-B) and solvent-solvent (A-A) particles.

Non-ideal solutions, on the other hand, deviate from Raoult's Law. They can show positive deviation (vapour pressure higher than predicted, weaker A-B interactions) or negative deviation (vapour pressure lower than predicted, stronger A-B interactions).

Most real solutions are non-ideal to some extent, but dilute solutions often approximate ideal behavior.