Chemistry

Vapour Pressure of Liquid Solutions

Chemistry·Explained

Vapour Pressure of Solutions of Solids in Liquids — Explained

NEET UG
Version 1Updated 22 Mar 2026

Detailed Explanation

The concept of vapour pressure is fundamental to understanding the behavior of liquid solutions. When a non-volatile solid is dissolved in a volatile liquid, the resulting solution exhibits a lower vapour pressure than the pure solvent at the same temperature. This phenomenon is not just an observation but is governed by a precise scientific law and has significant implications in chemistry and biology.

Conceptual Foundation

To grasp why the vapour pressure lowers, let's first revisit the concept of vapour pressure for a pure liquid. In a closed container, a pure liquid establishes a dynamic equilibrium with its vapour. Molecules at the liquid surface, possessing sufficient kinetic energy, escape into the gaseous phase (evaporation).

Simultaneously, vapour molecules collide with the liquid surface and return to the liquid phase (condensation). At equilibrium, the rate of evaporation equals the rate of condensation, and the pressure exerted by the vapour is the vapour pressure of the pure liquid (PA0P_A^0).

Now, consider dissolving a non-volatile solid solute (e.g., glucose, urea) into this volatile liquid solvent (e.g., water). A non-volatile solute is one that does not readily vaporize at the given temperature.

When the solute dissolves, its particles distribute uniformly throughout the solvent, including at the liquid-vapour interface. The presence of these non-volatile solute particles at the surface effectively reduces the fraction of the surface area available for the solvent molecules to escape into the vapour phase.

With fewer solvent molecules exposed at the surface, the rate at which solvent molecules can evaporate decreases. While the rate of condensation of solvent molecules from the vapour phase remains largely unchanged (or decreases slightly as vapour concentration drops), the net effect is a reduction in the number of solvent molecules in the vapour phase at equilibrium.

Consequently, the pressure exerted by the vapour above the solution (PAP_A) is lower than that above the pure solvent (PA0P_A^0).

Key Principles and Laws: Raoult's Law

This qualitative understanding is quantified by Raoult's Law. For a solution containing a non-volatile solute, Raoult's Law states that the partial vapour pressure of the solvent (PAP_A) in the solution is directly proportional to its mole fraction (xAx_A) in the solution. The proportionality constant is the vapour pressure of the pure solvent (PA0P_A^0) at the same temperature.

Mathematically, Raoult's Law for a non-volatile solute is expressed as:

PA=xAPA0P_A = x_A P_A^0
Where:

  • PAP_A = Vapour pressure of the solvent in the solution
  • xAx_A = Mole fraction of the solvent in the solution
  • PA0P_A^0 = Vapour pressure of the pure solvent

The mole fraction of the solvent, xAx_A, is defined as:

xA=nAnA+nBx_A = \frac{n_A}{n_A + n_B}
Where nAn_A is the number of moles of solvent and nBn_B is the number of moles of solute.

Since xAx_A is always less than 1 for a solution (as nB>0n_B > 0), it directly follows that PA<PA0P_A < P_A^0, confirming the lowering of vapour pressure.

Derivations: Relative Lowering of Vapour Pressure

The *lowering of vapour pressure*, denoted as DeltaPDelta P, is the difference between the vapour pressure of the pure solvent and the vapour pressure of the solvent in the solution:

DeltaP=PA0PADelta P = P_A^0 - P_A
Substituting Raoult's Law (PA=xAPA0P_A = x_A P_A^0):
DeltaP=PA0xAPA0=PA0(1xA)Delta P = P_A^0 - x_A P_A^0 = P_A^0 (1 - x_A)
We know that for a binary solution, the sum of mole fractions of all components is 1, i.e., xA+xB=1x_A + x_B = 1. Therefore, 1xA=xB1 - x_A = x_B, where xBx_B is the mole fraction of the solute.

So, the lowering of vapour pressure can also be expressed as:

DeltaP=xBPA0Delta P = x_B P_A^0

The *relative lowering of vapour pressure* is defined as the ratio of the lowering of vapour pressure to the vapour pressure of the pure solvent:

DeltaPPA0=PA0PAPA0\frac{Delta P}{P_A^0} = \frac{P_A^0 - P_A}{P_A^0}
Substituting DeltaP=xBPA0Delta P = x_B P_A^0:
PA0PAPA0=xBPA0PA0=xB\frac{P_A^0 - P_A}{P_A^0} = \frac{x_B P_A^0}{P_A^0} = x_B
This is a very significant result: **the relative lowering of vapour pressure is equal to the mole fraction of the solute (xBx_B)**.

This relationship is particularly useful because it allows us to determine the molar mass of an unknown non-volatile solute. We know that:

xB=nBnA+nBx_B = \frac{n_B}{n_A + n_B}
For dilute solutions, where nBllnAn_B ll n_A, we can approximate nA+nBapproxnAn_A + n_B approx n_A. In such cases:
xBnBnAx_B \approx \frac{n_B}{n_A}
And since n=massmolar massn = \frac{\text{mass}}{\text{molar mass}}, we have nB=wBMBn_B = \frac{w_B}{M_B} and nA=wAMAn_A = \frac{w_A}{M_A}.

Substituting these into the approximate expression for xBx_B:

PA0PAPA0wB/MBwA/MA=wBMAMBwA\frac{P_A^0 - P_A}{P_A^0} \approx \frac{w_B/M_B}{w_A/M_A} = \frac{w_B M_A}{M_B w_A}
This equation can be rearranged to solve for the molar mass of the solute (MBM_B):
MB=wBMAwA×PA0PA0PAM_B = \frac{w_B M_A}{w_A} \times \frac{P_A^0}{P_A^0 - P_A}
This method is a classic way to determine the molar mass of non-volatile solutes experimentally.

Real-World Applications

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  1. DesalinationWhile not directly using vapour pressure lowering, the principle is related to osmotic pressure, which is also a colligative property. Understanding how solute concentration affects solvent properties is key to processes like reverse osmosis.
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  3. Antifreeze SolutionsAlthough primarily related to freezing point depression, the underlying principle of colligative properties (dependence on solute concentration) is the same. Adding a non-volatile solute (like ethylene glycol) to water lowers its freezing point and raises its boiling point, making it useful in car radiators.
  4. 3
  5. Food PreservationConcentrated sugar solutions (jams, jellies) or salt solutions (pickles) have lower water activity due to reduced vapour pressure. This inhibits microbial growth, extending shelf life.
  6. 4
  7. Pharmaceutical IndustryVapour pressure measurements can be used to determine the purity and concentration of solutions, and to characterize new compounds.
  8. 5
  9. Chemical AnalysisAs derived, the relative lowering of vapour pressure provides a method for determining the molar mass of unknown non-volatile substances, which is a crucial step in chemical identification and characterization.

Common Misconceptions

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  1. Vapour pressure lowering vs. boiling point elevationWhile related (both are colligative properties), they are distinct phenomena. Lowering of vapour pressure *causes* boiling point elevation. Students sometimes confuse the two or use the wrong formula.
  2. 2
  3. Applicability of Raoult's LawRaoult's Law strictly applies only to *ideal solutions*. Ideal solutions are those where the intermolecular forces between solute-solvent particles are similar to those between solute-solute and solvent-solvent particles. In reality, most solutions are non-ideal and show deviations (positive or negative) from Raoult's Law. However, for dilute solutions, the law provides a good approximation.
  4. 3
  5. Nature of soluteStudents might forget that Raoult's Law for vapour pressure lowering applies specifically to *non-volatile* solutes. If the solute is also volatile, the total vapour pressure of the solution would be the sum of the partial vapour pressures of both components, each governed by Raoult's Law for volatile components.
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  7. UnitsCare must be taken with units, especially when calculating mole fractions or molar masses. Ensure consistency.

NEET-Specific Angle

For NEET, this topic is highly important due to its quantitative nature and its role as a foundational colligative property. Questions typically involve:

  • Direct application of Raoult's LawCalculating the vapour pressure of a solution given the mole fraction of the solvent and pure solvent vapour pressure.
  • Calculating relative lowering of vapour pressureGiven concentrations, finding xBx_B or vice versa.
  • Molar mass determinationUsing the relative lowering of vapour pressure to find the molar mass of an unknown non-volatile solute.
  • Conceptual questionsUnderstanding *why* vapour pressure lowers, identifying factors affecting it (temperature, concentration, nature of solvent), and distinguishing between ideal and non-ideal solutions (though detailed non-ideal behavior is often covered separately).
  • Relationship with other colligative propertiesSometimes questions might indirectly link vapour pressure lowering to boiling point elevation or freezing point depression, requiring a holistic understanding of colligative properties. Always remember that colligative properties depend only on the *number* of solute particles, not their identity. For ionic solutes, the van't Hoff factor (ii) must be considered to account for dissociation.
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