Chemistry

Vapour Pressure of Liquid Solutions

Chemistry·Prelims Strategy

Vapour Pressure of Solutions of Solids in Liquids — Prelims Strategy

NEET UG
Version 1Updated 22 Mar 2026

Prelims Strategy

To excel in NEET questions on 'Vapour Pressure of Solutions of Solids in Liquids,' a systematic approach is essential. For numerical problems, always start by clearly identifying the given values (PA0P_A^0, PAP_A, wAw_A, wBw_B, MAM_A, MBM_B) and what needs to be calculated.

Pay close attention to units and ensure consistency. The key formulas are Raoult's Law (PA=xAPA0P_A = x_A P_A^0) and the relative lowering of vapour pressure (racPA0PAPA0=xBrac{P_A^0 - P_A}{P_A^0} = x_B). Remember that xA=nAnA+nBx_A = \frac{n_A}{n_A + n_B} and xB=nBnA+nBx_B = \frac{n_B}{n_A + n_B}.

For molar mass determination, the expanded form racPA0PAPA0=wBMAMBwArac{P_A^0 - P_A}{P_A^0} = \frac{w_B M_A}{M_B w_A} (for dilute solutions) is very useful. For conceptual questions, focus on the 'why' behind the lowering of vapour pressure – the reduction of solvent molecules at the surface.

Be wary of trap options that might suggest an increase in vapour pressure or confuse absolute lowering with relative lowering. Practice converting between different concentration units (mass percent, molality, mole fraction) if required, though mole fraction is most common here.

Always double-check calculations, especially when dealing with fractions and decimals, as small arithmetic errors can lead to incorrect options.

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