Chemistry·Explained

Vapour Pressure of Liquid Solutions — Explained

NEET UG
Version 1Updated 24 Mar 2026

Detailed Explanation

The concept of vapour pressure is fundamental to understanding the physical properties of liquid solutions. It describes the tendency of molecules to escape from the liquid phase into the gaseous phase. For a pure liquid, this pressure is a characteristic property at a given temperature. When we introduce a solute to form a solution, the vapour pressure of the system changes, and this change is governed by the nature of the solute and solvent.

1. Vapour Pressure of Pure Liquids:

Before delving into solutions, let's reiterate that for a pure liquid in a closed container, molecules are constantly transitioning between liquid and vapour phases. At equilibrium, the pressure exerted by the vapour is its vapour pressure. This value increases with temperature because a higher temperature provides more kinetic energy to molecules, enabling more of them to overcome intermolecular forces and escape into the gas phase.

2. Raoult's Law for Solutions:

Raoult's Law is a cornerstone principle that quantitatively describes the vapour pressure of ideal solutions. It can be applied in two primary scenarios:

a) Solutions Containing a Non-Volatile Solute:

When a non-volatile solute (one that does not vaporize significantly at the given temperature, e.g., glucose, urea, common salts) is dissolved in a volatile solvent, the vapour pressure of the solution is solely due to the solvent.

Raoult's Law states that for such a solution, the partial vapour pressure of each volatile component (in this case, only the solvent) in the solution is directly proportional to its mole fraction in the solution.

Mathematically, for a solvent A and a non-volatile solute B:

PA=XAPA0P_A = X_A P_A^0
Where: * PAP_A is the partial vapour pressure of the solvent in the solution. * XAX_A is the mole fraction of the solvent in the solution.

* PA0P_A^0 is the vapour pressure of the pure solvent at the same temperature.

Since XA<1X_A < 1 (as XA+XB=1X_A + X_B = 1 and XB>0X_B > 0), it implies that PA<PA0P_A < P_A^0. This means the vapour pressure of the solution is always lower than that of the pure solvent. This phenomenon is known as the lowering of vapour pressure.

The relative lowering of vapour pressure is a colligative property, meaning it depends only on the number of solute particles, not their identity. Relative lowering of vapour pressure is given by:

PA0PAPA0=PA0XAPA0PA0=PA0(1XA)PA0=1XA\frac{P_A^0 - P_A}{P_A^0} = \frac{P_A^0 - X_A P_A^0}{P_A^0} = \frac{P_A^0(1 - X_A)}{P_A^0} = 1 - X_A
Since 1XA=XB1 - X_A = X_B (mole fraction of solute), we get:
PA0PAPA0=XB\frac{P_A^0 - P_A}{P_A^0} = X_B
This equation is extremely useful for determining the molar mass of a non-volatile solute.

b) Solutions Containing Two or More Volatile Components:

When a solution consists of two or more volatile liquids (e.g., benzene and toluene), each component contributes to the total vapour pressure. Raoult's Law extends to this scenario, stating that for each volatile component, its partial vapour pressure in the solution is proportional to its mole fraction in the solution. For a binary solution of volatile components A and B: * Partial vapour pressure of A: PA=XAPA0P_A = X_A P_A^0 * Partial vapour pressure of B: PB=XBPB0P_B = X_B P_B^0

According to Dalton's Law of Partial Pressures, the total vapour pressure of the solution (PtotalP_{total}) is the sum of the partial vapour pressures of its components:

Ptotal=PA+PBP_{total} = P_A + P_B
Substituting Raoult's Law expressions:
Ptotal=XAPA0+XBPB0P_{total} = X_A P_A^0 + X_B P_B^0
Since XB=1XAX_B = 1 - X_A, we can also write:
Ptotal=XAPA0+(1XA)PB0P_{total} = X_A P_A^0 + (1 - X_A) P_B^0
Ptotal=(PA0PB0)XA+PB0P_{total} = (P_A^0 - P_B^0) X_A + P_B^0
This equation shows that the total vapour pressure of an ideal solution varies linearly with the mole fraction of one of its components.

3. Ideal Solutions:

An ideal solution is one that obeys Raoult's Law over the entire range of concentrations and temperatures. For an ideal solution, the intermolecular forces between solute-solvent molecules (A-B) are identical to the intermolecular forces between solute-solute (A-A) and solvent-solvent (B-B) molecules.

This means: * \Delta H_{mixing} = 0: No heat is absorbed or released when components are mixed. * \Delta V_{mixing} = 0: There is no change in volume upon mixing. * Interactions: A-B interactions are similar in magnitude to A-A and B-B interactions.

Examples: Benzene and toluene, n-hexane and n-heptane, chloroethane and bromoethane.

4. Non-Ideal Solutions (Deviations from Raoult's Law):

Most real solutions do not behave ideally and show deviations from Raoult's Law. These deviations arise when the intermolecular forces between solute and solvent molecules are significantly different from those between pure components.

a) Positive Deviation from Raoult's Law:

* Observation: The total vapour pressure of the solution is higher than that predicted by Raoult's Law. * Molecular Explanation: In these solutions, the A-B intermolecular forces are weaker than the average of A-A and B-B interactions.

This means molecules of A and B find it easier to escape from the solution surface into the vapour phase compared to their pure states. Consequently, the partial vapour pressures of A and B, and thus the total vapour pressure, are higher than ideal.

* Thermodynamic Consequences: \Delta H_{mixing} > 0 (endothermic, heat is absorbed) and \Delta V_{mixing} > 0 (volume increases upon mixing). * Examples: Ethanol and water, acetone and ethanol, carbon disulphide and acetone.

b) Negative Deviation from Raoult's Law:

* Observation: The total vapour pressure of the solution is lower than that predicted by Raoult's Law. * Molecular Explanation: Here, the A-B intermolecular forces are stronger than the average of A-A and B-B interactions.

This enhanced attraction makes it more difficult for molecules of A and B to escape from the solution surface into the vapour phase. As a result, the partial vapour pressures of A and B, and the total vapour pressure, are lower than ideal.

* Thermodynamic Consequences: \Delta H_{mixing} < 0 (exothermic, heat is released) and \Delta V_{mixing} < 0 (volume decreases upon mixing). * Examples: Acetone and chloroform (due to hydrogen bonding), nitric acid and water, acetic acid and pyridine.

5. Azeotropes:

Non-ideal solutions that show significant deviations from Raoult's Law can form azeotropes. An azeotrope (or constant boiling mixture) is a liquid mixture that boils at a constant temperature and distills without change in composition. This means the composition of the vapour phase is the same as that of the liquid phase. Azeotropes cannot be separated into their pure components by fractional distillation.

a) Minimum Boiling Azeotropes: Formed by solutions showing large positive deviations from Raoult's Law. At a specific composition, the vapour pressure is maximum, leading to a minimum boiling point. Example: Ethanol (95.6%) and water (4.4%) mixture boils at 351.3 K, lower than pure ethanol (351.5 K) or pure water (373 K).

b) Maximum Boiling Azeotropes: Formed by solutions showing large negative deviations from Raoult's Law. At a specific composition, the vapour pressure is minimum, leading to a maximum boiling point. Example: Nitric acid (68%) and water (32%) mixture boils at 393.5 K, higher than pure nitric acid (359 K) or pure water (373 K).

Real-World Applications:

  • DistillationUnderstanding vapour pressure is crucial for separating liquid mixtures by distillation. Components with higher vapour pressure (lower boiling point) vaporize more readily.
  • HumidityThe partial pressure of water vapour in the air contributes to atmospheric pressure and determines humidity levels.
  • Boiling Point Elevation/Freezing Point DepressionThese colligative properties are direct consequences of the lowering of vapour pressure by a non-volatile solute.
  • Industrial ProcessesMany chemical processes, from petroleum refining to pharmaceutical manufacturing, involve controlling and predicting vapour pressures of mixtures.

Common Misconceptions:

  • Vapour pressure is always lowered by adding any soluteThis is true for non-volatile solutes. For volatile solutes, the vapour pressure can be higher or lower than the pure components depending on their relative volatility and mole fractions.
  • Ideal solutions are commonMost real solutions are non-ideal. Ideal solutions are theoretical constructs that provide a baseline for understanding deviations.
  • Azeotropes are compoundsAzeotropes are mixtures, not pure compounds, even though they boil at a constant temperature and have a fixed composition during distillation. They can be separated by other means, like azeotropic distillation or extractive distillation.

NEET-Specific Angle:

For NEET, questions frequently test the direct application of Raoult's Law for both non-volatile and volatile solutes. Identifying ideal vs. non-ideal solutions based on given properties (\Delta H_{mixing}, \Delta V_{mixing}, or intermolecular forces) is common.

Understanding the characteristics and examples of positive and negative deviations, and the formation of azeotropes, are high-yield areas. Numerical problems often involve calculating the vapour pressure of a solution, the mole fraction of a component, or the molar mass of a non-volatile solute using the relative lowering of vapour pressure formula.

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