Chemistry·Revision Notes

Vapour Pressure of Liquid Solutions — Revision Notes

NEET UG
Version 1Updated 24 Mar 2026

⚡ 30-Second Revision

  • Vapour Pressure (VP)Pressure by vapour in equilibrium with liquid.
  • Raoult's Law (Non-volatile solute)Ps=XsolventPsolvent0P_s = X_{solvent} P_{solvent}^0.
  • Relative Lowering of VPPsolvent0PsPsolvent0=Xsolute\frac{P_{solvent}^0 - P_s}{P_{solvent}^0} = X_{solute}.
  • Raoult's Law (Volatile solutes)PA=XAPA0P_A = X_A P_A^0, PB=XBPB0P_B = X_B P_B^0.
  • Total VPPtotal=PA+PB=XAPA0+XBPB0P_{total} = P_A + P_B = X_A P_A^0 + X_B P_B^0.
  • Ideal SolutionObeys Raoult's Law, ΔHmixing=0\Delta H_{mixing} = 0, ΔVmixing=0\Delta V_{mixing} = 0, A-B forces similar to A-A, B-B.
  • Positive DeviationPtotal>PidealP_{total} > P_{ideal}, A-B forces < A-A/B-B, ΔHmixing>0\Delta H_{mixing} > 0, ΔVmixing>0\Delta V_{mixing} > 0. (e.g., Ethanol + Water)
  • Negative DeviationPtotal<PidealP_{total} < P_{ideal}, A-B forces > A-A/B-B, ΔHmixing<0\Delta H_{mixing} < 0, ΔVmixing<0\Delta V_{mixing} < 0. (e.g., Acetone + Chloroform)
  • AzeotropesConstant boiling mixtures, cannot be separated by fractional distillation.

- Minimum Boiling Azeotrope: From large positive deviation. - Maximum Boiling Azeotrope: From large negative deviation.

2-Minute Revision

Vapour pressure is the pressure exerted by a vapour in equilibrium with its liquid. For a pure liquid, it increases with temperature. When a non-volatile solute is added, the vapour pressure of the solution decreases, a phenomenon explained by Raoult's Law: Ps=XsolventPsolvent0P_s = X_{solvent} P_{solvent}^0. The relative lowering of vapour pressure, Psolvent0PsPsolvent0\frac{P_{solvent}^0 - P_s}{P_{solvent}^0}, is equal to the mole fraction of the solute (XsoluteX_{solute}), a key colligative property used to find molar mass.

For solutions with two volatile components, each contributes to the total vapour pressure according to its mole fraction and pure vapour pressure: Ptotal=XAPA0+XBPB0P_{total} = X_A P_A^0 + X_B P_B^0. Ideal solutions strictly follow Raoult's Law, with no heat or volume change on mixing, and similar intermolecular forces.

Non-ideal solutions deviate. Positive deviations occur when solute-solvent interactions are weaker, leading to higher vapour pressure, positive \Delta H_{mixing} and \Delta V_{mixing}. Negative deviations occur when solute-solvent interactions are stronger, leading to lower vapour pressure, negative \Delta H_{mixing} and \Delta V_{mixing}.

Significant deviations can form azeotropes, which are constant boiling mixtures (minimum boiling from positive deviation, maximum boiling from negative deviation) that cannot be separated by simple distillation.

5-Minute Revision

Let's quickly review the critical aspects of vapour pressure of liquid solutions for NEET. Firstly, remember that vapour pressure is the equilibrium pressure of vapour above a liquid. For pure liquids, it's temperature-dependent.

When we introduce a non-volatile solute, the vapour pressure of the solvent is lowered. This is quantitatively described by Raoult's Law: Ps=XsolventPsolvent0P_s = X_{solvent} P_{solvent}^0. A direct consequence is the relative lowering of vapour pressure, Psolvent0PsPsolvent0=Xsolute\frac{P_{solvent}^0 - P_s}{P_{solvent}^0} = X_{solute}, which is a colligative property and often used to determine the molar mass of an unknown solute.

For example, if pure water has a VP of 20 mmHg and a solution has 18 mmHg, the relative lowering is (2018)/20=0.1(20-18)/20 = 0.1, so the mole fraction of solute is 0.1.

When both components are volatile, each contributes to the total vapour pressure. Raoult's Law states PA=XAPA0P_A = X_A P_A^0 and PB=XBPB0P_B = X_B P_B^0. The total pressure is Ptotal=PA+PBP_{total} = P_A + P_B. For instance, if PA0=100P_A^0 = 100 mmHg and PB0=200P_B^0 = 200 mmHg, and XA=0.5X_A = 0.5, then Ptotal=(0.5×100)+(0.5×200)=50+100=150P_{total} = (0.5 \times 100) + (0.5 \times 200) = 50 + 100 = 150 mmHg.

Solutions are classified as ideal or non-ideal. Ideal solutions obey Raoult's Law perfectly, with \Delta H_{mixing} = 0 and \Delta V_{mixing} = 0, implying similar intermolecular forces (e.g., benzene-toluene).

Non-ideal solutions deviate. Positive deviations occur when A-B interactions are weaker than A-A and B-B, leading to higher vapour pressure, \Delta H_{mixing} > 0, and \Delta V_{mixing} > 0 (e.g., ethanol-water).

Negative deviations occur when A-B interactions are stronger, resulting in lower vapour pressure, \Delta H_{mixing} < 0, and \Delta V_{mixing} < 0 (e.g., acetone-chloroform).

Finally, remember azeotropes. These are constant boiling mixtures formed by non-ideal solutions. Minimum boiling azeotropes arise from large positive deviations (e.g., 95.6% ethanol-water), having a boiling point lower than either pure component. Maximum boiling azeotropes arise from large negative deviations (e.g., 68% nitric acid-water), having a boiling point higher than either pure component. Crucially, azeotropes cannot be separated by simple fractional distillation.

Prelims Revision Notes

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  1. Vapour Pressure (VP)Pressure exerted by vapour in equilibrium with liquid at a given temperature. Increases with temperature.
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  3. Raoult's Law for Non-Volatile SoluteWhen a non-volatile solute is added to a volatile solvent, the vapour pressure of the solution (PsP_s) is directly proportional to the mole fraction of the solvent (XsolventX_{solvent}) and the vapour pressure of the pure solvent (Psolvent0P_{solvent}^0). Formula: Ps=XsolventPsolvent0P_s = X_{solvent} P_{solvent}^0.
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  5. Lowering of Vapour PressurePsolvent0PsP_{solvent}^0 - P_s.
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  7. Relative Lowering of Vapour PressurePsolvent0PsPsolvent0=Xsolute\frac{P_{solvent}^0 - P_s}{P_{solvent}^0} = X_{solute}. This is a colligative property, dependent only on the number of solute particles. Used to calculate molar mass of non-volatile solutes.
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  9. Raoult's Law for Volatile Solute MixturesFor a binary solution of volatile liquids A and B, the partial vapour pressure of each component is PA=XAPA0P_A = X_A P_A^0 and PB=XBPB0P_B = X_B P_B^0. The total vapour pressure is Ptotal=PA+PB=XAPA0+XBPB0P_{total} = P_A + P_B = X_A P_A^0 + X_B P_B^0.
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  11. Composition of Vapour PhaseThe mole fraction of a component in the vapour phase (YAY_A) can be calculated using Dalton's Law of Partial Pressures: YA=PAPtotalY_A = \frac{P_A}{P_{total}}.
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  13. Ideal Solutions

* Obey Raoult's Law over the entire concentration range. * Intermolecular forces (A-B) are similar to (A-A) and (B-B). * ΔHmixing=0\Delta H_{mixing} = 0 (no heat change). * ΔVmixing=0\Delta V_{mixing} = 0 (no volume change). * Examples: Benzene + Toluene, n-Hexane + n-Heptane.

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  1. Non-Ideal Solutions (Deviations from Raoult's Law)

* Positive Deviation: * A-B intermolecular forces are weaker than A-A and B-B. * Molecules escape more easily, so Ptotal>(XAPA0+XBPB0)P_{total} > (X_A P_A^0 + X_B P_B^0). * ΔHmixing>0\Delta H_{mixing} > 0 (endothermic).

* ΔVmixing>0\Delta V_{mixing} > 0 (volume expansion). * Examples: Ethanol + Water, Acetone + Ethanol, Carbon Disulphide + Acetone. * Negative Deviation: * A-B intermolecular forces are stronger than A-A and B-B.

* Molecules escape less easily, so Ptotal<(XAPA0+XBPB0)P_{total} < (X_A P_A^0 + X_B P_B^0). * ΔHmixing<0\Delta H_{mixing} < 0 (exothermic). * ΔVmixing<0\Delta V_{mixing} < 0 (volume contraction). * Examples: Acetone + Chloroform, Nitric acid + Water, Acetic acid + Pyridine.

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  1. Azeotropes (Constant Boiling Mixtures)

* Liquid mixtures that boil at a constant temperature without changing composition. * Cannot be separated by fractional distillation. * Minimum Boiling Azeotropes: Formed by solutions showing large positive deviations (e.g., 95.6% ethanol in water, boils below pure ethanol or water). * Maximum Boiling Azeotropes: Formed by solutions showing large negative deviations (e.g., 68% nitric acid in water, boils above pure nitric acid or water).

Vyyuha Quick Recall

For deviations from Raoult's Law:

Positive Deviation: People Drink Ethanol & Water (Ethanol + Water). They feel Weaker (A-B forces weaker), get Hot (ΔHmixing>0\Delta H_{mixing} > 0), and Volume Increases (ΔVmixing>0\Delta V_{mixing} > 0). Their Vapour Pressure is High.

Negative Deviation: No Drinking Acetone & Chloroform (Acetone + Chloroform). They feel Stronger (A-B forces stronger), get Cold (ΔHmixing<0\Delta H_{mixing} < 0), and Volume Decreases (ΔVmixing<0\Delta V_{mixing} < 0). Their Vapour Pressure is Low.

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