Chemistry

Integrated Rate Equations

Chemistry·Revision Notes

Zero and First Order Reactions — Revision Notes

NEET UG
Version 1Updated 22 Mar 2026

⚡ 30-Second Revision

  • Zero-Order Reaction:

- Rate Law: Rate=k\text{Rate} = k - Integrated Rate Law: [A]t=[A]0kt[A]_t = [A]_0 - kt - Half-life: t1/2=[A]02kt_{1/2} = \frac{[A]_0}{2k} (proportional to [A]0[A]_0) - Units of kk: mol L1^{-1} s1^{-1} - Linear Plot: [A]t[A]_t vs. tt (slope = k-k)

  • First-Order Reaction:

- Rate Law: Rate=k[A]\text{Rate} = k[A] - Integrated Rate Law: ln([A]t[A]0)=kt\ln\left(\frac{[A]_t}{[A]_0}\right) = -kt or 2.303log([A]0[A]t)=kt2.303 \log\left(\frac{[A]_0}{[A]_t}\right) = kt - Half-life: t1/2=0.693kt_{1/2} = \frac{0.693}{k} (independent of [A]0[A]_0) - Units of kk: s1^{-1} - Linear Plot: ln[A]t\ln[A]_t vs. tt (slope = k-k)

2-Minute Revision

For NEET, quickly recall the core aspects of zero and first-order reactions. Zero-order reactions have a constant rate, meaning the reactant's concentration doesn't affect how fast it reacts. Think of it as a factory producing at a fixed pace, regardless of how much raw material is stockpiled.

The key formula is [A]t=[A]0kt[A]_t = [A]_0 - kt. Its half-life, t1/2=[A]0/2kt_{1/2} = [A]_0 / 2k, is directly proportional to the initial concentration. The rate constant (kk) for zero-order reactions has units of mol L1^{-1} s1^{-1}.

Graphically, a plot of concentration vs. time is a straight line with a negative slope of k-k.

First-order reactions, on the other hand, have a rate directly proportional to the reactant's concentration. Imagine a population growth where the more individuals there are, the faster it grows. The integrated rate law is ln([A]t/[A]0)=ktln([A]_t/[A]_0) = -kt.

A crucial feature is its half-life, t1/2=0.693/kt_{1/2} = 0.693 / k, which is constant and independent of the initial concentration. The units of kk for first-order reactions are s1^{-1}. A plot of ln[A]tln[A]_t vs.

time yields a straight line with a negative slope of k-k. Remember these distinct characteristics, especially the half-life dependence and rate constant units, as they are frequently tested.

5-Minute Revision

A thorough revision of zero and first-order reactions for NEET involves understanding their definitions, integrated rate laws, half-life characteristics, and graphical representations.

Zero-Order Reactions: The rate is independent of reactant concentration. This implies that the reaction proceeds at a constant speed until the reactant is depleted. The differential rate law is Rate=d[A]/dt=k\text{Rate} = -d[A]/dt = k.

Integrating this gives the integrated rate law: [A]t=[A]0kt[A]_t = [A]_0 - kt. This equation is linear, so a plot of [A]t[A]_t vs. tt yields a straight line with a slope of k-k and y-intercept [A]0[A]_0. The half-life for a zero-order reaction is t1/2=[A]0/2kt_{1/2} = [A]_0 / 2k, which means it is directly proportional to the initial concentration.

The **units of the rate constant (kk)** are mol L1^{-1} s1^{-1}. A common example is the decomposition of ammonia on a hot platinum surface when the surface is saturated.

First-Order Reactions: The rate is directly proportional to the first power of the reactant concentration. This means the reaction slows down as the reactant is consumed. The differential rate law is Rate=d[A]/dt=k[A]\text{Rate} = -d[A]/dt = k[A].

Integrating this gives the integrated rate law: ln([A]t/[A]0)=ktln([A]_t/[A]_0) = -kt or, in base-10 logarithm, 2.303log([A]0/[A]t)=kt2.303 \log([A]_0/[A]_t) = kt. A plot of ln[A]tln[A]_t vs. tt (or log[A]tlog[A]_t vs. tt) yields a straight line with a slope of k-k (or $-k/2.

303)andyintercept) and y-interceptln[A]_0(or(orlog[A]_0).Themostdistinctivefeatureisitshalflife:). The most distinctive feature is its **half-life**:t_{1/2} = 0.693 / k,whichisconstantandindependentoftheinitialconcentration.Theunitsoftherateconstant(, which is constant and independent of the initial concentration. The **units of the rate constant (k)ares)** are s^{-1}$.

Radioactive decay is a classic example.

Key Differences to Remember: Focus on the dependence of half-life on initial concentration and the units of kk. Practice numerical problems involving both types, especially those requiring calculation of time, concentration, or rate constant. Be prepared to interpret graphs to determine reaction order.

Prelims Revision Notes

Zero-Order Reactions

  • Definition:Rate is independent of reactant concentration.
  • Rate Law:Rate=k[A]0=k\text{Rate} = k[A]^0 = k
  • Integrated Rate Law:[A]t=[A]0kt[A]_t = [A]_0 - kt

* [A]t[A]_t: concentration at time tt * [A]0[A]_0: initial concentration * kk: rate constant * tt: time

  • Units of Rate Constant ($k$):mol L1^{-1} s1^{-1} (or M s1^{-1})
  • Half-life ($t_{1/2}$):t1/2=[A]02kt_{1/2} = \frac{[A]_0}{2k}

* Key Feature: t1/2t_{1/2} is directly proportional to the initial concentration [A]0[A]_0.

  • Graphical Representation:Plot of [A]t[A]_t vs. tt is a straight line.

* Slope =k= -k * Y-intercept =[A]0= [A]_0

  • Examples:Enzyme-catalyzed reactions (at high substrate conc.), surface-catalyzed reactions (e.g., NH3NH_3 decomposition on Pt).

First-Order Reactions

  • Definition:Rate is directly proportional to the first power of reactant concentration.
  • Rate Law:Rate=k[A]1=k[A]\text{Rate} = k[A]^1 = k[A]
  • Integrated Rate Law:

* ln([A]t[A]0)=kt\ln\left(\frac{[A]_t}{[A]_0}\right) = -kt * 2.303log([A]0[A]t)=kt2.303 \log\left(\frac{[A]_0}{[A]_t}\right) = kt * [A]t=[A]0ekt[A]_t = [A]_0 e^{-kt}

  • Units of Rate Constant ($k$):s1^{-1} (or min1^{-1}, hr1^{-1})
  • Half-life ($t_{1/2}$):t1/2=ln(2)k=0.693kt_{1/2} = \frac{\ln(2)}{k} = \frac{0.693}{k}

* Key Feature: t1/2t_{1/2} is constant and independent of the initial concentration [A]0[A]_0.

  • Graphical Representation:Plot of ln[A]tln[A]_t vs. tt is a straight line.

* Slope =k= -k * Y-intercept =ln[A]0= \ln[A]_0 * Plot of log[A]tlog[A]_t vs. tt is a straight line with slope =k/2.303= -k/2.303.

  • Examples:Radioactive decay, decomposition of N2O5N_2O_5, hydrolysis of esters (pseudo-first-order).

Important Points for NEET

  • Distinguish Order vs. Molecularity:Order is experimental, molecularity is theoretical (for elementary steps).
  • Pseudo-First-Order Reactions:Understand when a higher-order reaction behaves as first-order (e.g., excess solvent).
  • Calculations:Be proficient in using integrated rate laws and half-life formulas to solve for kk, tt, [A]t[A]_t, or [A]0[A]_0. Remember ln(x)=2.303log(x)ln(x) = 2.303 \log(x).

Vyyuha Quick Recall

Zero Constant Linear Half-life Proportional

  • Zero-order: Constant rate (independent of concentration)
  • Linear plot: [A][A] vs tt
  • Half-life: Proportional to initial concentration ([A]0[A]_0)

First Exponential Log Half-life Independent

  • First-order: Exponential decay
  • Log plot: ln[A]\ln[A] vs tt
  • Half-life: Independent of initial concentration
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