Physics·Explained

Work by Constant Force — Explained

NEET UG
Version 1Updated 22 Mar 2026

Detailed Explanation

The concept of work is one of the most fundamental ideas in physics, serving as a bridge between force and energy. While in everyday language 'work' might imply effort or activity, in physics, it has a very specific and quantitative meaning. For NEET UG, a deep understanding of work done by a constant force is crucial, as it forms the basis for understanding energy conservation, power, and more complex scenarios involving variable forces.

Conceptual Foundation: Work as Energy Transfer

At its core, work is a mechanism for energy transfer. When a force does work on an object, it either adds energy to the object (positive work) or removes energy from it (negative work). This energy transfer manifests as changes in the object's kinetic energy, potential energy, or internal energy. For work to be done, two conditions must be met:

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  1. A force must act on an object.
  2. 2
  3. The object must undergo a displacement.

Furthermore, there must be a component of the force along the direction of the displacement. If a force acts but there is no displacement, or if the force is always perpendicular to the displacement, no work is done by that force.

Key Principles and Laws: The Dot Product Definition

The most precise definition of work done by a constant force F\vec{F} causing a displacement d\vec{d} is given by the scalar product (or dot product) of these two vectors:

W=FdW = \vec{F} \cdot \vec{d}
This mathematical operation yields a scalar quantity, which is consistent with work being a scalar. Expanding the dot product, we get:
W=FdcosθW = Fd \cos\theta
where:

  • FF is the magnitude of the force vector F\vec{F}.
  • dd is the magnitude of the displacement vector d\vec{d}.
  • θ\theta is the angle between the direction of the force vector F\vec{F} and the direction of the displacement vector d\vec{d}.

Derivations and Cases of Work

Let's break down the W=FdcosθW = Fd \cos\theta formula to understand its implications:

1. Positive Work ($\theta < 90^\circ$):

When the angle θ\theta between the force and displacement is acute (between 00^\circ and 9090^\circ), cosθ\cos\theta is positive. This means the force has a component in the direction of motion, and thus, positive work is done. The force adds energy to the object. Examples include:

  • Pushing a box horizontally across a floor in the direction of motion.
  • Lifting an object against gravity (work done by the lifting force).
  • A car accelerating (work done by the engine's propulsive force).

2. Negative Work ($\theta > 90^\circ$):

When the angle θ\theta is obtuse (between 9090^\circ and 180180^\circ), cosθ\cos\theta is negative. This implies the force has a component opposing the direction of motion, and negative work is done. The force removes energy from the object. Examples include:

  • Work done by friction when an object slides across a surface. Friction always opposes motion, so θ=180\theta = 180^\circ, and cos(180)=1\cos(180^\circ) = -1.
  • Work done by air resistance on a moving object.
  • Work done by gravity when an object is lifted upward (gravity acts downward, displacement is upward, so θ=180\theta = 180^\circ).

3. Zero Work ($\theta = 90^\circ$):

When the angle θ\theta is exactly 9090^\circ, cos(90)=0\cos(90^\circ) = 0. In this case, no work is done by the force, even if there is a force and a displacement. This happens when the force is perpendicular to the displacement. Examples include:

  • Work done by the normal force on an object moving horizontally. The normal force acts perpendicular to the surface, while displacement is parallel to it.
  • Work done by the centripetal force on an object moving in a circular path at constant speed. The centripetal force is always directed towards the center (perpendicular to the tangential displacement).
  • Work done by gravity on an object moving horizontally (e.g., carrying a bag across a room at constant height).

Units and Dimensions

The SI unit of work is the Joule (J). One Joule is defined as the work done when a force of one Newton (N) causes a displacement of one meter (m) in the direction of the force. So, 1,J=1,Ncdotm1,\text{J} = 1,\text{N} cdot \text{m}. Other units include:

  • Erg (CGS unit): 1,J=107,erg1,\text{J} = 10^7,\text{erg}.
  • Electron-volt (eV): Used in atomic and nuclear physics.

The dimensional formula for work is derived from W=FdW = Fd. Since F=maF = ma, its dimensions are [M][L][T2][M][L][T^{-2}]. Multiplying by displacement [L][L], we get the dimensions of work as [M][L2][T2][M][L^2][T^{-2}]. This is the same as the dimensional formula for energy, reinforcing the idea that work is a form of energy transfer.

Real-World Applications

  • Lifting objects:When you lift a book from the floor to a shelf, you do positive work against gravity. The force you apply is upward, and the displacement is upward. Gravity, however, does negative work.
  • Pushing a cart:If you push a shopping cart, the force you apply does positive work, increasing the cart's kinetic energy.
  • Braking a vehicle:The friction force exerted by the brakes on the wheels does negative work, reducing the vehicle's kinetic energy and bringing it to a stop.
  • Walking:When you walk on a level surface, the normal force from the ground does no work on you because it's perpendicular to your horizontal displacement. The static friction force from the ground, which propels you forward, does positive work.

Common Misconceptions

  • Work vs. Effort:Students often confuse physical effort or fatigue with work done in physics. As discussed, pushing a stationary wall requires effort but results in zero work.
  • Work done by all forces:It's crucial to specify 'work done *by a specific force*'. An object might have multiple forces acting on it, each doing positive, negative, or zero work. The net work done is the sum of work done by all individual forces.
  • Direction of force vs. direction of motion:The angle θ\theta is between the force vector and the *displacement* vector, not necessarily the velocity vector. While often aligned, it's important to consider the actual displacement.
  • Work-Energy Theorem:While closely related, work and energy are distinct concepts. Work is the process of energy transfer, while energy is the capacity to do work. The Work-Energy Theorem states that the net work done on an object equals the change in its kinetic energy (Wnet=ΔKW_{net} = \Delta K). This theorem is a powerful tool for solving problems involving work and energy.

NEET-Specific Angle

For NEET, questions on work by a constant force often involve:

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  1. Direct application of $W = Fd \cos\theta$:Calculating work given force, displacement, and angle. This requires careful identification of θ\theta.
  2. 2
  3. Identifying forces doing zero work:Recognizing situations where normal force, tension (in certain cases), or centripetal force do no work.
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  5. Calculating work done by specific forces:For example, work done by gravity, friction, or an applied force.
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  7. Problems involving multiple forces:Calculating the net work done by summing the work done by individual forces.
  8. 5
  9. Graphical interpretation:Understanding that for a constant force, work is simply the area under the Force-displacement graph (a rectangle).
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  11. Connecting work to the Work-Energy Theorem:Using Wnet=ΔKW_{net} = \Delta K to find changes in speed or displacement. This is a very common type of problem.

Mastering these aspects requires not just memorizing the formula but developing a strong conceptual understanding of force, displacement, and their vector nature, along with careful attention to the direction of each vector involved.

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