Physics·Explained

Collisions — Explained

NEET UG
Version 1Updated 22 Mar 2026

Detailed Explanation

Collisions are ubiquitous phenomena in the physical world, ranging from the microscopic interactions of subatomic particles to the macroscopic impacts of vehicles. From a physics standpoint, a collision is a transient event characterized by strong interaction forces between two or more bodies over a short duration, leading to significant changes in their respective momenta and kinetic energies.

The study of collisions is fundamentally rooted in the principles of conservation of linear momentum and, in specific cases, conservation of kinetic energy.

Conceptual Foundation: Impulse and Momentum

Before delving into the types of collisions, it's essential to understand the concepts of impulse and momentum. Linear momentum (vecpvec{p}) of an object is defined as the product of its mass (mm) and its velocity (vecvvec{v}), i.e., vecp=mvecvvec{p} = mvec{v}. It is a vector quantity, having both magnitude and direction. The total linear momentum of a system of particles is the vector sum of the individual momenta.

When objects collide, they exert forces on each other. According to Newton's third law, these forces are equal in magnitude and opposite in direction. The effect of a force acting over a period of time is quantified by 'impulse' (vecJvec{J}).

Impulse is defined as the integral of force over time: vecJ=intvecF,dtvec{J} = int vec{F} , dt. From Newton's second law, vecF=dvecpdtvec{F} = \frac{dvec{p}}{dt}, so integrating this over time yields the 'impulse-momentum theorem':

J=Δp=pfpi\vec{J} = \Delta\vec{p} = \vec{p}_f - \vec{p}_i
This theorem states that the impulse acting on an object is equal to the change in its linear momentum.

During a collision, the forces are typically very large, but the time duration (DeltatDelta t) is very small. The impulse-momentum theorem is crucial because it allows us to analyze the effect of these large, short-duration forces without needing to know the exact time-varying force function.

Key Principles: Conservation Laws

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  1. Conservation of Linear Momentum:This is the most fundamental principle applied to collisions. For a system of colliding bodies, if no net external force acts on the system during the collision, the total linear momentum of the system remains conserved. This means the vector sum of the momenta of all objects *before* the collision is equal to the vector sum of their momenta *after* the collision.

pinitial=pfinal\sum \vec{p}_{initial} = \sum \vec{p}_{final}
For two colliding objects, m1m_1 and m2m_2, with initial velocities vecu1vec{u}_1 and vecu2vec{u}_2, and final velocities vecv1vec{v}_1 and vecv2vec{v}_2:
m1u1+m2u2=m1v1+m2v2m_1\vec{u}_1 + m_2\vec{u}_2 = m_1\vec{v}_1 + m_2\vec{v}_2
This principle holds true for *all* types of collisions (elastic, inelastic, perfectly inelastic) as long as the system is isolated from external forces.

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  1. Conservation of Kinetic Energy:Unlike momentum, kinetic energy is not always conserved in a collision. Kinetic energy (KE=12mv2KE = \frac{1}{2}mv^2) is a scalar quantity. Its conservation depends on the nature of the collision.

Types of Collisions

Collisions are primarily classified based on whether kinetic energy is conserved.

1. Elastic Collisions

An elastic collision is an idealized collision in which both linear momentum and kinetic energy are conserved. There is no loss of kinetic energy; it is merely redistributed among the colliding bodies. These collisions are rare in the macroscopic world but are a good approximation for interactions between hard, non-deforming objects (like billiard balls) or at the atomic/subatomic level.

Characteristics:

  • Linear momentum is conserved: m1u1+m2u2=m1v1+m2v2m_1\vec{u}_1 + m_2\vec{u}_2 = m_1\vec{v}_1 + m_2\vec{v}_2
  • Kinetic energy is conserved: 12m1u12+12m2u22=12m1v12+12m2v22\frac{1}{2}m_1u_1^2 + \frac{1}{2}m_2u_2^2 = \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2
  • Total energy is conserved.
  • Forces involved are conservative (e.g., elastic potential energy temporarily stored and released).

One-Dimensional Elastic Collision:

Consider two masses m1m_1 and m2m_2 moving along a straight line with initial velocities u1u_1 and u2u_2 (positive for rightward motion, negative for leftward). After the collision, their velocities are v1v_1 and v2v_2.

From momentum conservation:

m1u1+m2u2=m1v1+m2v2(1)m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2 \quad (1)
From kinetic energy conservation:
12m1u12+12m2u22=12m1v12+12m2v22\frac{1}{2}m_1u_1^2 + \frac{1}{2}m_2u_2^2 = \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2
m1(u12v12)=m2(v22u22)m_1(u_1^2 - v_1^2) = m_2(v_2^2 - u_2^2)
m1(u1v1)(u1+v1)=m2(v2u2)(v2+u2)(2)m_1(u_1 - v_1)(u_1 + v_1) = m_2(v_2 - u_2)(v_2 + u_2) \quad (2)
Rearranging (1):
m1(u1v1)=m2(v2u2)(3)m_1(u_1 - v_1) = m_2(v_2 - u_2) \quad (3)
Dividing (2) by (3) (assuming u1v1u_1 \neq v_1 and u2v2u_2 \neq v_2):
u1+v1=v2+u2u_1 + v_1 = v_2 + u_2
u1u2=(v1v2)u_1 - u_2 = -(v_1 - v_2)
This crucial result implies that the relative speed of approach before an elastic collision is equal to the relative speed of separation after the collision.

This is also related to the coefficient of restitution, e=1e=1 for elastic collisions.

Solving for v1v_1 and v2v_2 (after some algebraic manipulation):

v1=(m1m2)u1+2m2u2m1+m2v_1 = \frac{(m_1 - m_2)u_1 + 2m_2u_2}{m_1 + m_2}
v2=(m2m1)u2+2m1u1m1+m2v_2 = \frac{(m_2 - m_1)u_2 + 2m_1u_1}{m_1 + m_2}

Special Cases of 1D Elastic Collisions:

  • Equal Masses ($m_1 = m_2$):v1=u2v_1 = u_2 and v2=u1v_2 = u_1. The bodies exchange velocities. (e.g., billiard balls)
  • **Target at Rest (u2=0u_2 = 0):**

v1=(m1m2)u1m1+m2v_1 = \frac{(m_1 - m_2)u_1}{m_1 + m_2}
v2=2m1u1m1+m2v_2 = \frac{2m_1u_1}{m_1 + m_2}
* If m1=m2m_1 = m_2, then v1=0v_1 = 0 and v2=u1v_2 = u_1. The first body stops, and the second body moves with the initial velocity of the first.

* If m1m2m_1 \ll m_2 (light body hits heavy body at rest), then v1u1v_1 \approx -u_1 and v20v_2 \approx 0. The light body rebounds with nearly its initial speed, and the heavy body remains almost at rest. (e.

g., tennis ball hitting a wall) * If m1m2m_1 \gg m_2 (heavy body hits light body at rest), then v1u1v_1 \approx u_1 and v22u1v_2 \approx 2u_1. The heavy body continues with almost its initial speed, and the light body moves with nearly twice the initial speed of the heavy body.

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2. Inelastic Collisions

In an inelastic collision, linear momentum is conserved, but kinetic energy is *not* conserved. Some kinetic energy is lost, typically converted into other forms of energy such as heat, sound, or energy used to deform the colliding objects. Most real-world collisions are inelastic to some degree.

Characteristics:

  • Linear momentum is conserved: m1u1+m2u2=m1v1+m2v2m_1\vec{u}_1 + m_2\vec{u}_2 = m_1\vec{v}_1 + m_2\vec{v}_2
  • Kinetic energy is *not* conserved: KEinitial>KEfinalKE_{initial} > KE_{final}.
  • Total energy is conserved (including all forms of energy).
  • Forces involved may be non-conservative (e.g., friction, deformation).

Perfectly Inelastic Collisions:

This is a special case of inelastic collision where the colliding objects stick together after impact and move as a single combined mass. This results in the maximum possible loss of kinetic energy consistent with momentum conservation.

One-Dimensional Perfectly Inelastic Collision:

If m1m_1 and m2m_2 collide and stick together, they move with a common final velocity vecVvec{V}. From momentum conservation:

m1u1+m2u2=(m1+m2)Vm_1u_1 + m_2u_2 = (m_1 + m_2)V
V=m1u1+m2u2m1+m2V = \frac{m_1u_1 + m_2u_2}{m_1 + m_2}

Loss of Kinetic Energy in Perfectly Inelastic Collision:

The initial kinetic energy is KEi=12m1u12+12m2u22KE_i = \frac{1}{2}m_1u_1^2 + \frac{1}{2}m_2u_2^2. The final kinetic energy is KEf=12(m1+m2)V2=12(m1+m2)(m1u1+m2u2m1+m2)2=(m1u1+m2u2)22(m1+m2)KE_f = \frac{1}{2}(m_1 + m_2)V^2 = \frac{1}{2}(m_1 + m_2)\left(\frac{m_1u_1 + m_2u_2}{m_1 + m_2}\right)^2 = \frac{(m_1u_1 + m_2u_2)^2}{2(m_1 + m_2)}. The loss in kinetic energy is ΔKE=KEiKEf\Delta KE = KE_i - KE_f. This loss is always positive (or zero if u1=u2=0u_1=u_2=0), indicating that kinetic energy is always lost or converted in perfectly inelastic collisions.

Coefficient of Restitution ($e$)

The coefficient of restitution is a dimensionless quantity that quantifies the 'bounciness' of a collision. It is defined as the ratio of the relative speed of separation after the collision to the relative speed of approach before the collision, along the common normal to the surfaces at the point of impact.

e=Relative speed of separationRelative speed of approach=v2v1u1u2e = \frac{\text{Relative speed of separation}}{\text{Relative speed of approach}} = \frac{|v_2 - v_1|}{|u_1 - u_2|}

Values of $e$:

  • $e = 1$:For a perfectly elastic collision. Relative speed of separation equals relative speed of approach.
  • $e = 0$:For a perfectly inelastic collision. The objects stick together, so their relative speed of separation is zero (v1=v2v_1 = v_2).
  • $0 < e < 1$:For an inelastic collision. Some kinetic energy is lost, but the objects do not stick together.

This coefficient provides a convenient way to analyze collisions without explicitly dealing with kinetic energy conservation equations, especially when the collision is not perfectly elastic or inelastic.

Two-Dimensional Collisions

When objects collide and move in different directions after impact, the collision is two-dimensional. The principle of conservation of linear momentum still applies, but it must be applied vectorially, meaning separately for the components along the x-axis and y-axis.

m1u1x+m2u2x=m1v1x+m2v2xm_1u_{1x} + m_2u_{2x} = m_1v_{1x} + m_2v_{2x}
m1u1y+m2u2y=m1v1y+m2v2ym_1u_{1y} + m_2u_{2y} = m_1v_{1y} + m_2v_{2y}

For 2D elastic collisions, kinetic energy is also conserved, but this often leads to complex equations. For 2D inelastic collisions, kinetic energy is not conserved. The coefficient of restitution can also be applied, usually along the line of impact.

Real-World Applications and NEET-Specific Angle

  • Billiards/Pool:Excellent examples of nearly elastic collisions where momentum and kinetic energy conservation (approximately) dictate the outcome.
  • Car Crashes:Highly inelastic collisions where significant kinetic energy is converted into deformation, heat, and sound. Safety features like crumple zones are designed to increase the collision time, thereby reducing the impact force (Impulse = F DeltatDelta t).
  • Rocket Propulsion:While not a direct collision, it's a classic example of momentum conservation. The expulsion of high-velocity exhaust gases in one direction results in the rocket gaining momentum in the opposite direction.
  • Ballistic Pendulum:A common experimental setup to determine the speed of a bullet, involving a perfectly inelastic collision followed by conservation of mechanical energy.

Common Misconceptions:

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  1. Momentum is always conserved, kinetic energy is always conserved:While momentum is always conserved in an isolated system, kinetic energy is only conserved in *elastic* collisions. This is a frequent trap.
  2. 2
  3. Perfectly inelastic means total energy is lost:No, only kinetic energy is lost (transformed). Total energy (including heat, sound, deformation energy) is always conserved.
  4. 3
  5. Coefficient of restitution is only for 1D collisions:While often introduced in 1D, it can be applied to 2D collisions along the line of impact.
  6. 4
  7. Impulse is just force:Impulse is force *multiplied by time*, representing the *effect* of force over time, which is the change in momentum. A large force for a short time can have the same impulse as a small force for a long time.

For NEET, a strong grasp of 1D elastic and perfectly inelastic collisions is paramount. Questions often involve calculating final velocities, kinetic energy loss, or applying the coefficient of restitution. Two-dimensional collisions are less frequent but require careful vector component analysis. Practice with various scenarios, especially those involving objects at rest or equal masses, will solidify understanding.

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