Physics·Revision Notes

Motion in a Plane — Revision Notes

NEET UG
Version 1Updated 22 Mar 2026

⚡ 30-Second Revision

  • Position Vectorr=xi^+yj^\vec{r} = x\hat{i} + y\hat{j}
  • DisplacementΔr=rfri\Delta\vec{r} = \vec{r}_f - \vec{r}_i
  • Velocityv=dr/dt=vxi^+vyj^\vec{v} = d\vec{r}/dt = v_x\hat{i} + v_y\hat{j}
  • Accelerationa=dv/dt=axi^+ayj^\vec{a} = d\vec{v}/dt = a_x\hat{i} + a_y\hat{j}
  • Equations of Motion (constant $\vec{a}$)

- v=u+at\vec{v} = \vec{u} + \vec{a}t - s=ut+12at2\vec{s} = \vec{u}t + \frac{1}{2}\vec{a}t^2

  • Projectile Motion (from ground, $u$ at $\theta$)

- ux=ucosθu_x = u\cos\theta, uy=usinθu_y = u\sin\theta - ax=0a_x = 0, ay=ga_y = -g - Time of Flight: T=2usinθgT = \frac{2u\sin\theta}{g} - Max Height: H=u2sin2θ2gH = \frac{u^2\sin^2\theta}{2g} - Horizontal Range: R=u2sin(2θ)gR = \frac{u^2\sin(2\theta)}{g} - Trajectory: y=xtanθgx22u2cos2θy = x\tan\theta - \frac{gx^2}{2u^2\cos^2\theta}

  • Uniform Circular Motion (UCM)

- Linear-Angular relation: v=rωv = r\omega - Centripetal Acceleration: ac=v2r=rω2a_c = \frac{v^2}{r} = r\omega^2

  • Relative VelocityvAB=vAvB\vec{v}_{AB} = \vec{v}_A - \vec{v}_B

2-Minute Revision

Motion in a plane extends 1D kinematics to two dimensions, requiring vectors for position, displacement, velocity, and acceleration. The core principle is the independence of perpendicular motions: horizontal and vertical components are analyzed separately, linked only by time.

For constant acceleration, 1D kinematic equations apply to each component. Projectile motion, a key example, involves constant horizontal velocity (ucosθu\cos\theta) and vertical motion under gravity (usinθgtu\sin\theta - gt).

Key formulas for time of flight (T=2usinθ/gT = 2u\sin\theta/g), max height (H=u2sin2θ/2gH = u^2\sin^2\theta/2g), and range (R=u2sin(2θ)/gR = u^2\sin(2\theta)/g) are essential. Uniform Circular Motion (UCM) features constant speed but changing velocity, leading to centripetal acceleration (ac=v2/ra_c = v^2/r) directed towards the center.

Relative velocity in 2D uses vector subtraction (vAB=vAvB\vec{v}_{AB} = \vec{v}_A - \vec{v}_B) for scenarios like river crossings or rain falling on a moving person. Always resolve vectors into components and draw diagrams.

5-Minute Revision

Motion in a plane is the study of objects moving in two dimensions, typically described using x and y coordinates. All kinematic quantities (position r\vec{r}, displacement Δr\Delta\vec{r}, velocity v\vec{v}, acceleration a\vec{a}) are vectors. The position vector is r=xi^+yj^\vec{r} = x\hat{i} + y\hat{j}. Velocity is v=dr/dt=vxi^+vyj^\vec{v} = d\vec{r}/dt = v_x\hat{i} + v_y\hat{j}, and acceleration is a=dv/dt=axi^+ayj^\vec{a} = d\vec{v}/dt = a_x\hat{i} + a_y\hat{j}.

The most important concept is the independence of perpendicular motions. This means motion along the x-axis does not affect motion along the y-axis, allowing us to apply 1D kinematic equations separately to each component. Time is the common parameter.

Projectile Motion: An object launched into the air, moving under gravity. Neglecting air resistance, horizontal acceleration ax=0a_x = 0, so vx=ux=ucosθv_x = u_x = u\cos\theta is constant. Vertical acceleration ay=ga_y = -g. Key formulas:

  • Time of Flight (TT): T=2usinθgT = \frac{2u\sin\theta}{g}
  • Maximum Height (HH): H=u2sin2θ2gH = \frac{u^2\sin^2\theta}{2g}
  • Horizontal Range (RR): R=u2sin(2θ)gR = \frac{u^2\sin(2\theta)}{g}. Max range at θ=45circ\theta = 45^circ.
  • Equation of Trajectory: y=xtanθgx22u2cos2θy = x\tan\theta - \frac{gx^2}{2u^2\cos^2\theta}

Uniform Circular Motion (UCM): Object moves in a circle at constant speed vv. Velocity direction continuously changes, so there is acceleration. This is centripetal acceleration (aca_c), directed towards the center. Its magnitude is ac=v2r=rω2a_c = \frac{v^2}{r} = r\omega^2, where ω=v/r\omega = v/r is angular velocity. The force causing this is centripetal force (Fc=macF_c = ma_c).

Relative Velocity: The velocity of an object A as observed from a moving object B is vAB=vAvB\vec{v}_{AB} = \vec{v}_A - \vec{v}_B. This is crucial for:

  • River-Boat Problemsvboat,ground=vboat,water+vwater,ground\vec{v}_{boat, ground} = \vec{v}_{boat, water} + \vec{v}_{water, ground}. For shortest time, boat heads perpendicular to river. For shortest path, boat heads upstream such that resultant velocity is perpendicular to river.
  • Rain-Man Problemsvrain,man=vrain,groundvman,ground\vec{v}_{rain, man} = \vec{v}_{rain, ground} - \vec{v}_{man, ground}.

Example: A ball is thrown horizontally from a 45,m45,\text{m} high cliff with a speed of 15,m/s15,\text{m/s}. Find the time to hit the ground (g=10,m/s2g=10,\text{m/s}^2).

  • Vertical motion: uy=0u_y = 0, sy=45,ms_y = -45,\text{m}, ay=10,m/s2a_y = -10,\text{m/s}^2. Using sy=uyt+12ayt2s_y = u_yt + \frac{1}{2}a_yt^2: 45=0t+12(10)t2    45=5t2    t2=9    t=3,s-45 = 0 \cdot t + \frac{1}{2}(-10)t^2 \implies -45 = -5t^2 \implies t^2 = 9 \implies t = 3,\text{s}.
  • Horizontal distance: sx=uxt=15,m/s×3,s=45,ms_x = u_xt = 15,\text{m/s} \times 3,\text{s} = 45,\text{m}.

Always draw vector diagrams, resolve components, and apply the correct kinematic equations. Be careful with signs for direction.

Prelims Revision Notes

    1
  1. Vector BasicsVectors have magnitude and direction. Scalars only magnitude. Position r=xi^+yj^\vec{r} = x\hat{i} + y\hat{j}. Displacement Δr=rfri\Delta\vec{r} = \vec{r}_f - \vec{r}_i. Velocity v=dr/dt\vec{v} = d\vec{r}/dt. Acceleration a=dv/dt\vec{a} = d\vec{v}/dt. Vector addition/subtraction is component-wise. Magnitude of A=Axi^+Ayj^\vec{A} = A_x\hat{i} + A_y\hat{j} is vecA=Ax2+Ay2|vec{A}| = \sqrt{A_x^2 + A_y^2}. Direction tanθ=Ay/Ax\tan\theta = A_y/A_x.
  2. 2
  3. Independence of Perpendicular MotionsThe key concept. Horizontal and vertical motions are independent. Time is the link. Apply 1D equations separately to x and y components.
  4. 3
  5. Equations of Motion (Constant Acceleration)

* vx=ux+axtv_x = u_x + a_xt, vy=uy+aytv_y = u_y + a_yt * x=uxt+12axt2x = u_xt + \frac{1}{2}a_xt^2, y=uyt+12ayt2y = u_yt + \frac{1}{2}a_yt^2 * vx2=ux2+2axxv_x^2 = u_x^2 + 2a_xx, vy2=uy2+2ayyv_y^2 = u_y^2 + 2a_yy

    1
  1. Projectile Motion (Ground to Ground)

* Initial velocity uu at angle θ\theta with horizontal. * Horizontal component: ux=ucosθu_x = u\cos\theta, ax=0a_x = 0, vx=uxv_x = u_x (constant). * Vertical component: uy=usinθu_y = u\sin\theta, ay=ga_y = -g. * Time of Flight (TT): T=2usinθgT = \frac{2u\sin\theta}{g}.

* Maximum Height (HH): H=u2sin2θ2gH = \frac{u^2\sin^2\theta}{2g}. (At max height, vy=0v_y = 0). * Horizontal Range (RR): R=u2sin(2θ)gR = \frac{u^2\sin(2\theta)}{g}. Max range at θ=45circ\theta = 45^circ (Rmax=u2/gR_{max} = u^2/g). Ranges are equal for complementary angles (θ\theta and 90circθ90^circ - \theta).

* Velocity at any time tt: v(t)=(ucosθ)i^+(usinθgt)j^\vec{v}(t) = (u\cos\theta)\hat{i} + (u\sin\theta - gt)\hat{j}.

    1
  1. Uniform Circular Motion (UCM)

* Speed vv is constant, but velocity v\vec{v} changes direction, hence acceleration exists. * Angular velocity ω=DeltaθDeltat\omega = \frac{Delta\theta}{Delta t}. Relation: v=rωv = r\omega. * Centripetal Acceleration (aca_c): Always directed towards the center. ac=v2r=rω2a_c = \frac{v^2}{r} = r\omega^2. It is perpendicular to v\vec{v}. * Centripetal Force (FcF_c): Fc=mac=mv2r=mrω2F_c = ma_c = \frac{mv^2}{r} = mr\omega^2. This is the net force causing the circular motion.

    1
  1. Relative Velocity in 2D

* General formula: vAB=vAvB\vec{v}_{AB} = \vec{v}_A - \vec{v}_B. * River-Boat Problems: vboat,ground=vboat,water+vwater,ground\vec{v}_{boat, ground} = \vec{v}_{boat, water} + \vec{v}_{water, ground}. * Shortest Time: Boat heads perpendicular to river flow.

Time T=Widthvboat,waterT = \frac{\text{Width}}{v_{boat, water}}. Drift x=vwater,groundTx = v_{water, ground} \cdot T. * Shortest Path: Resultant velocity is perpendicular to river flow. Boat heads upstream at angle θ\theta such that vboat,watersinθ=vwater,groundv_{boat, water}\sin\theta = v_{water, ground}.

Time T=Widthvboat,water2vwater,ground2T = \frac{\text{Width}}{\sqrt{v_{boat, water}^2 - v_{water, ground}^2}}. * Rain-Man Problems: vrain,man=vrain,groundvman,ground\vec{v}_{rain, man} = \vec{v}_{rain, ground} - \vec{v}_{man, ground}. Draw vector diagrams to find magnitude and direction of apparent rain velocity.

Vyyuha Quick Recall

For Projectile Motion formulas, remember 'T-H-R': Time of flight: Two Up Side Gravity (2usinθ/g2u\sin\theta/g) Height: Half Up Side Square Gravity (u2sin2θ/2gu^2\sin^2\theta/2g) Range: Up Side Twice Gravity (u2sin(2θ)/gu^2\sin(2\theta)/g)

For Relative Velocity, think 'A relative to B is A minus B': vAB=vAvB\vec{v}_{AB} = \vec{v}_A - \vec{v}_B. Always remember the 'minus' for relative velocity, and then use vector addition for resultant velocities like vBG=vBW+vWG\vec{v}_{BG} = \vec{v}_{BW} + \vec{v}_{WG}.

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