Physics·Revision Notes

Newton's Second Law — Revision Notes

NEET UG
Version 1Updated 22 Mar 2026

⚡ 30-Second Revision

  • Newton's Second LawFnet=dpdt\vec{F}_{\text{net}} = \frac{d\vec{p}}{dt}
  • For constant massFnet=ma\vec{F}_{\text{net}} = m\vec{a}
  • Linear Momentump=mv\vec{p} = m\vec{v}
  • UnitsForce (Newton, N), Mass (kilogram, kg), Acceleration (m/s2^2), Momentum (kg·m/s)
  • Key PrincipleNet force causes acceleration in its direction, inversely proportional to mass.
  • FBDsEssential for identifying all forces and their directions.

2-Minute Revision

Newton's Second Law is the cornerstone of dynamics, stating that the net external force on an object is equal to the rate of change of its linear momentum. This is expressed as Fnet=dpdt\vec{F}_{\text{net}} = \frac{d\vec{p}}{dt}.

For systems with constant mass, this simplifies to the widely used form Fnet=ma\vec{F}_{\text{net}} = m\vec{a}. This equation tells us that an object accelerates only when a net (unbalanced) force acts on it.

The acceleration is directly proportional to the net force and inversely proportional to the object's mass. Crucially, the acceleration always occurs in the same direction as the net force. The SI unit of force is the Newton (N), defined as 1kgm/s21\,\text{kg} \cdot \text{m/s}^2.

Remember that this law is valid only in inertial frames of reference. When solving problems, always start with a clear Free-Body Diagram (FBD) to identify all forces, resolve them into components, and then apply F=maF=ma along each relevant axis.

5-Minute Revision

Newton's Second Law is the quantitative heart of classical mechanics. It fundamentally states that the net external force (vecFnetvec{F}_{\text{net}}) acting on an object is equal to the rate of change of its linear momentum (vecpvec{p}). Mathematically, vecFnet=dpdtvec{F}_{\text{net}} = \frac{d\vec{p}}{dt}. Linear momentum is defined as the product of mass and velocity, vecp=mvvec{p} = m\vec{v}.

For the vast majority of NEET problems, where the mass of the object remains constant, the law simplifies to its most common form: Fnet=ma\vec{F}_{\text{net}} = m\vec{a}. This equation highlights three critical aspects:

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  1. Direct ProportionalityAcceleration (vecavec{a}) is directly proportional to the net force (vecFnetvec{F}_{\text{net}}).
  2. 2
  3. Inverse ProportionalityAcceleration (vecavec{a}) is inversely proportional to the mass (mm).
  4. 3
  5. DirectionThe acceleration vector is always in the same direction as the net force vector.

The SI unit of force is the Newton (N), where 1N=1kgm/s21\,\text{N} = 1\,\text{kg} \cdot \text{m/s}^2. It's vital to remember that vecFnetvec{F}_{\text{net}} refers to the *vector sum* of all external forces. This law is strictly applicable only in inertial frames of reference (non-accelerating frames).

Problem-Solving Strategy for NEET:

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  1. Draw FBDsFor each object in the system, draw a free-body diagram showing all forces acting *on* that object (e.g., gravity, normal force, tension, friction, applied force).
  2. 2
  3. Choose Coordinate SystemAlign axes strategically (e.g., parallel/perpendicular to inclined planes).
  4. 3
  5. Resolve ForcesBreak down forces acting at angles into components along the chosen axes.
  6. 4
  7. Apply $\vec{F}_{\text{net}} = m\vec{a}$Write separate equations for each axis (e.g., Fx=max\sum F_x = ma_x and Fy=may\sum F_y = ma_y).
  8. 5
  9. SolveSolve the resulting system of equations. Remember that action-reaction pairs (Newton's Third Law) are crucial for relating forces between interacting objects (e.g., tension in a string).

Example: A 2kg2\,\text{kg} block is pulled by a 12N12\,\text{N} force on a frictionless horizontal surface. Calculate its acceleration. Solution: Fnet=12NF_{\text{net}} = 12\,\text{N}, m=2kgm = 2\,\text{kg}. Using Fnet=maF_{\text{net}} = m\vec{a}, we get 12N=2kg×a12\,\text{N} = 2\,\text{kg} \times a. So, a=6m/s2a = 6\,\text{m/s}^2.

Prelims Revision Notes

  • DefinitionNet external force is proportional to the rate of change of momentum.
  • Formula (General)Fnet=dpdt\vec{F}_{\text{net}} = \frac{d\vec{p}}{dt}
  • Formula (Constant Mass)Fnet=ma\vec{F}_{\text{net}} = m\vec{a}
  • Momentump=mv\vec{p} = m\vec{v} (vector quantity, direction same as velocity).
  • Force and AccelerationBoth are vector quantities. a\vec{a} is always in the direction of Fnet\vec{F}_{\text{net}}.
  • Units1Newton (N)=1kgm/s21\,\text{Newton (N)} = 1\,\text{kg} \cdot \text{m/s}^2.
  • Inertial FramesNewton's Second Law is valid only in inertial (non-accelerating) frames of reference.
  • Net ForceIt's the vector sum of all external forces. If Fnet=0\vec{F}_{\text{net}} = 0, then a=0\vec{a} = 0 (object is in equilibrium).
  • ApplicationsCommon scenarios include:

- Single body: Direct application of F=maF=ma. - Connected bodies: Treat as a system for common acceleration, then analyze individual bodies for internal forces (tension, contact force). - Pulleys: Tension is uniform in a massless, inextensible string over an ideal pulley.

Apply F=maF=ma to each hanging mass. - Inclined Planes: Resolve gravitational force (mgmg) into components: mgsinθmg \sin \theta (parallel to incline) and mgcosθmg \cos \theta (perpendicular to incline). - Elevator Problems: Apparent weight (normal force) changes with acceleration.

N=m(g+a)N = m(g+a) for upward acceleration, N=m(ga)N = m(g-a) for downward acceleration.

  • Common Traps

- Confusing mass and weight. - Using individual forces instead of net force. - Incorrectly resolving forces into components. - Forgetting the vector nature of force and acceleration.

Vyyuha Quick Recall

For My Acceleration, Force Must Act! (F=ma)

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